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➤微信公众号:山青咏芝(shanqingyongzhi)
➤博客园地址:山青咏芝(https://www.cnblogs.com/strengthen/)
➤GitHub地址:https://github.com/strengthen/LeetCode
➤原文地址:https://www.cnblogs.com/strengthen/p/11179552.html
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Given a string S
, remove the vowels 'a'
, 'e'
, 'i'
, 'o'
, and 'u'
from it, and return the new string.
Example 1:
Input: "leetcodeisacommunityforcoders"
Output: "ltcdscmmntyfrcdrs"
Example 2:
Input: "aeiou"
Output: ""
Note:
S
consists of lowercase English letters only.1 <= S.length <= 1000
给你一个字符串 S
,请你删去其中的所有元音字母( 'a'
,'e'
,'i'
,'o'
,'u'
),并返回这个新字符串。
示例 1:
输入:"leetcodeisacommunityforcoders" 输出:"ltcdscmmntyfrcdrs"
示例 2:
输入:"aeiou" 输出:""
提示:
S
仅由小写英文字母组成。1 <= S.length <= 1000
8ms
1 class Solution { 2 func removeVowels(_ S: String) -> String { 3 let arrS:[Character] = Array(S) 4 var ret:String = String() 5 for i in 0..<S.count 6 { 7 if arrS[i] == "a" || arrS[i] == "e" || arrS[i] == "i" || arrS[i] == "o" || arrS[i] == "u" 8 { 9 continue 10 } 11 else 12 { 13 ret.append(arrS[i]) 14 } 15 } 16 return ret 17 } 18 }