• [Swift]LeetCode837. 新21点 | New 21 Game


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    Alice plays the following game, loosely based on the card game "21".

    Alice starts with 0 points, and draws numbers while she has less than K points.  During each draw, she gains an integer number of points randomly from the range [1, W], where W is an integer.  Each draw is independent and the outcomes have equal probabilities.

    Alice stops drawing numbers when she gets K or more points.  What is the probability that she has N or less points?

    Example 1:

    Input: N = 10, K = 1, W = 10
    Output: 1.00000
    Explanation:  Alice gets a single card, then stops.
    

    Example 2:

    Input: N = 6, K = 1, W = 10
    Output: 0.60000
    Explanation:  Alice gets a single card, then stops.
    In 6 out of W = 10 possibilities, she is at or below N = 6 points.
    

    Example 3:

    Input: N = 21, K = 17, W = 10
    Output: 0.73278

    Note:

    1. 0 <= K <= N <= 10000
    2. 1 <= W <= 10000
    3. Answers will be accepted as correct if they are within 10^-5 of the correct answer.
    4. The judging time limit has been reduced for this question.

    爱丽丝参与一个大致基于纸牌游戏 “21点” 规则的游戏,描述如下:

    爱丽丝以 0 分开始,并在她的得分少于 K分时抽取数字。 抽取时,她从 [1, W] 的范围中随机获得一个整数作为分数进行累计,其中 W 是整数。 每次抽取都是独立的,其结果具有相同的概率。

    当爱丽丝获得不少于 K 分时,她就停止抽取数字。 爱丽丝的分数不超过 N 的概率是多少?

    示例 1:

    输入:N = 10, K = 1, W = 10
    输出:1.00000
    说明:爱丽丝得到一张卡,然后停止。

    示例 2:

    输入:N = 6, K = 1, W = 10
    输出:0.60000
    说明:爱丽丝得到一张卡,然后停止。
    在 W = 10 的 6 种可能下,她的得分不超过 N = 6 分。

    示例 3:

    输入:N = 21, K = 17, W = 10
    输出:0.73278

    提示:

    1. 0 <= K <= N <= 10000
    2. 1 <= W <= 10000
    3. 如果答案与正确答案的误差不超过 10^-5,则该答案将被视为正确答案通过。
    4. 此问题的判断限制时间已经减少。

    24ms

     1 class Solution {
     2     func new21Game(_ N: Int, _ K: Int, _ W: Int) -> Double {
     3         guard N > 0 else { return 1.0 }
     4         guard W >= N - K else { return 1.0 }
     5         var dp = Array(repeating: 0.0, count: N+1)
     6         dp[0] = 1
     7         let w = Double(W)
     8         var temp = 0.0
     9         for i in 1...N {
    10             if i <= K {
    11               temp += dp[i-1] / w  
    12             }
    13             if i > W {
    14                 temp -= dp[i-W-1] / w
    15             } 
    16             dp[i] = temp  
    17         }
    18         return dp[K...].reduce(0.0, +)
    19     }
    20 }

    Runtime: 48 ms
    Memory Usage: 18.8 MB
     1 class Solution {
     2     func new21Game(_ N: Int, _ K: Int, _ W: Int) -> Double {        
     3         if K == 0 || N >= (K + W) {return 1.0}        
     4         var dp:[Double] = [Double](repeating:0.0,count:K + W)
     5         dp[0] = 1.0
     6         for i in 1..<(K + W)
     7         {
     8             dp[i] = dp[i - 1]
     9             if i <= W
    10             {
    11                 dp[i] += dp[i - 1] / Double(W)
    12             }
    13             else
    14             {
    15                 dp[i] += (dp[i - 1] - dp[i - W - 1]) / Double(W)
    16             }
    17             if i > K
    18             {
    19                 dp[i] -= (dp[i - 1] - dp[K - 1]) / Double(W)            
    20             }            
    21         }
    22         return dp[N] - dp[K - 1]
    23     }
    24 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10576171.html
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