• [SQL]LeetCode627. 交换工资 | Swap Salary


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    SQL架构

    1 create table if not exists salary(id int, name varchar(100), sex char(1), salary int)
    2 Truncate table salary
    3 insert into salary (id, name, sex, salary) values ('1', 'A', 'm', '2500')
    4 insert into salary (id, name, sex, salary) values ('2', 'B', 'f', '1500')
    5 insert into salary (id, name, sex, salary) values ('3', 'C', 'm', '5500')
    6 insert into salary (id, name, sex, salary) values ('4', 'D', 'f', '500')

    Given a table salary, such as the one below, that has m=male and f=female values. Swap all f and m values (i.e., change all f values to m and vice versa) with a single update query and no intermediate temp table. 

    For example: 

    | id | name | sex | salary |
    |----|------|-----|--------|
    | 1  | A    | m   | 2500   |
    | 2  | B    | f   | 1500   |
    | 3  | C    | m   | 5500   |
    | 4  | D    | f   | 500    |
    

    After running your query, the above salary table should have the following rows:

    | id | name | sex | salary |
    |----|------|-----|--------|
    | 1  | A    | f   | 2500   |
    | 2  | B    | m   | 1500   |
    | 3  | C    | f   | 5500   |
    | 4  | D    | m   | 500    |

    给定一个 salary表,如下所示,有m=男性 和 f=女性的值 。交换所有的 f 和 m 值(例如,将所有 f 值更改为 m,反之亦然)。要求使用一个更新查询,并且没有中间临时表。

    例如:

    | id | name | sex | salary |
    |----|------|-----|--------|
    | 1  | A    | m   | 2500   |
    | 2  | B    | f   | 1500   |
    | 3  | C    | m   | 5500   |
    | 4  | D    | f   | 500    |
    

    运行你所编写的查询语句之后,将会得到以下表:

    | id | name | sex | salary |
    |----|------|-----|--------|
    | 1  | A    | f   | 2500   |
    | 2  | B    | m   | 1500   |
    | 3  | C    | f   | 5500   |
    | 4  | D    | m   | 500    |

    129ms
    1 # Write your MySQL query statement below
    2 select id, name, if(sex = 'm','f','m') sex,salary from salary; 

    281ms

    1 UPDATE salary
    2 SET sex = CASE
    3 WHEN sex = 'f' THEN 'm'
    4 ELSE 'f'
    5 END

    282ms

    1 # Write your MySQL query statement below
    2 update salary set sex= if(sex='m','f','m');

    283ms

    1 # Write your MySQL query statement below
    2 UPDATE salary
    3 SET
    4     sex = CASE sex
    5         WHEN 'm' THEN 'f'
    6         ELSE 'm'
    7     END;

    284ms

    1 update salary set sex=case sex when 'm' then 'f' else 'm' end;

    287ms

    1 # Write your MySQL query statement below
    2 update salary set sex= CHAR(ASCII('f') + ASCII('m') - ASCII(sex));
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  • 原文地址:https://www.cnblogs.com/strengthen/p/10472837.html
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