金额转人民币大写是一种常见的要求,但是这一看似简单的要求,实现起来却并不容易。
前不久,我被问到了这样一道题,当时写了个算法,昨天晚上又和BJDP的人们讨论了一下,觉得很有必要把这个算法写下来。
总共37行,去掉空行还不到30行,就不多啰嗦解释了。
1 public class ChineseCurrencyConverter { 2 3 private static final String[] UNITS = {"亿","仟","佰","拾","万","仟","佰","拾","" }; 4 private static final String[] CHINESE_NUMBER = {"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"}; 5 6 public static String convert(long yuan) { 7 8 if (yuan >= 1e9 || yuan < 0) { 9 return "这个数字超出解析范围了"; 10 } 11 String amount = String.valueOf(yuan); 12 int len = amount.length(); 13 int unitsLen = UNITS.length; 14 15 String chineseCurrency = ""; 16 for (int i = len - 1; i >= 0; i--) { 17 chineseCurrency = number(amount.charAt(i)) + unit(amount.charAt(i), unitsLen - len + i) +chineseCurrency; 18 } 19 20 chineseCurrency = chineseCurrency.replaceAll("零+","零"); 21 chineseCurrency = chineseCurrency + "元整"; 22 chineseCurrency = chineseCurrency.replaceAll("零万","万"); 23 chineseCurrency = chineseCurrency.replaceAll("零元","元"); 24 return chineseCurrency; 25 } 26 27 private static String number(char number) { 28 return CHINESE_NUMBER[Integer.parseInt(String.valueOf(number))]; 29 } 30 31 private static String unit(char number, int pos) { 32 if(number == '0' && pos != UNITS.length - 5) { 33 return ""; 34 } 35 return UNITS[pos]; 36 } 37 }
下面是一些用来测试的代码:
1 public class TestConverter { 2 3 public static void main(String[] args) { 4 System.out.println(ChineseCurrencyConverter.convert(100)); 5 System.out.println(ChineseCurrencyConverter.convert(130)); 6 System.out.println(ChineseCurrencyConverter.convert(102)); 7 System.out.println(ChineseCurrencyConverter.convert(124)); 8 System.out.println(ChineseCurrencyConverter.convert(1000)); 9 System.out.println(ChineseCurrencyConverter.convert(10000)); 10 System.out.println(ChineseCurrencyConverter.convert(100000)); 11 System.out.println(ChineseCurrencyConverter.convert(1000000)); 12 System.out.println(ChineseCurrencyConverter.convert(10000000)); 13 System.out.println(ChineseCurrencyConverter.convert(10000000)); 14 System.out.println(ChineseCurrencyConverter.convert(100000000)); 15 System.out.println(ChineseCurrencyConverter.convert(1000000000)); 16 System.out.println(ChineseCurrencyConverter.convert(1002)); 17 System.out.println(ChineseCurrencyConverter.convert(1020)); 18 System.out.println(ChineseCurrencyConverter.convert(1200)); 19 System.out.println(ChineseCurrencyConverter.convert(10003)); 20 System.out.println(ChineseCurrencyConverter.convert(10030)); 21 System.out.println(ChineseCurrencyConverter.convert(10033)); 22 System.out.println(ChineseCurrencyConverter.convert(10330)); 23 System.out.println(ChineseCurrencyConverter.convert(13030)); 24 System.out.println(ChineseCurrencyConverter.convert(100030)); 25 System.out.println(ChineseCurrencyConverter.convert(100003)); 26 System.out.println(ChineseCurrencyConverter.convert(100300)); 27 System.out.println(ChineseCurrencyConverter.convert(103000)); 28 System.out.println(ChineseCurrencyConverter.convert(100303)); 29 System.out.println(ChineseCurrencyConverter.convert(1000004)); 30 System.out.println(ChineseCurrencyConverter.convert(10000005)); 31 System.out.println(ChineseCurrencyConverter.convert(10000006)); 32 System.out.println(ChineseCurrencyConverter.convert(12000006)); 33 System.out.println(ChineseCurrencyConverter.convert(10030006)); 34 System.out.println(ChineseCurrencyConverter.convert(10200006)); 35 System.out.println(ChineseCurrencyConverter.convert(100000007)); 36 System.out.println(ChineseCurrencyConverter.convert(1000000008)); 37 38 } 39 }
这些数字测试的结果还都正确。
这里没有处理角和分,留给有想法的同学去尝试一下吧。