判断日期天数

#coding:utf-8
from collections import OrderedDict
import datetime
dt=['20171001','20171001','20171002','20171003','20171005','20171006','20171006','20171008','20171009','20171010','20171015']

 
'''
d1 = datetime.date(2015,10,7)
d2 = datetime.date(2015,8,15)
print((d1-d2).days)

'''

def isnextday(dt1,dt2):
    d1 = datetime.datetime.strptime(dt1, '%Y%m%d')
    d2 = datetime.datetime.strptime(dt2, '%Y%m%d')
    delta = (d2 - d1).days
    if delta==1:
        return 1
    else:
        return 0

d=OrderedDict()
l=[]
l2=[]
for i, val in enumerate(dt) :
    d[i+1]=val
    
  
for k,v in d.items():
    if k==1:
        l.append(1)
        l2.append(1)
    else:
        if v==d.get(k-1):
            l.append(0)
            l2.append(0)
        elif isnextday(d.get(k-1),v)==1:
            l.append(0)
            l2.append(1)
        else:
            l.append(1)
            l2.append(1)

sum=0
for i in l:
    sum+=i
    
sum2=0
for i in l2:
    sum2+=i


print ("第一种  #连续出现的日期判定为1天 规则下统计  ")
print (str(sum)+'天')

print ('----------------------------------------')

print ("第二种  #一天出现多次判定为1天 规则下统计  ")
print (str(sum2)+'天')