POJ_3204
这个题目和ZOJ_2532是一样的题目,具体的思路可以参考我的ZOJ_2532的解题报告:http://www.cnblogs.com/staginner/archive/2012/08/11/2633751.html。
#include<stdio.h> #include<string.h> #include<algorithm> #define MAXD 510 #define MAXM 10010 #define INF 0x3f3f3f3f int N, M, first[MAXD], e, next[MAXM], v[MAXM], flow[MAXM]; int S, T, d[MAXD], q[MAXD], work[MAXD], visx[MAXD], visy[MAXD]; void add(int x, int y, int z) { v[e] = y, flow[e] = z; next[e] = first[x], first[x] = e ++; } void init() { int i, x, y, z; S = 0, T = N - 1; memset(first, -1, sizeof(first[0]) * N), e = 0; for(i = 0; i < M; i ++) { scanf("%d%d%d", &x, &y, &z); add(x, y, z), add(y, x, 0); } } int bfs() { int i, j, rear = 0; memset(d, -1, sizeof(d[0]) * N); d[S] = 0, q[rear ++] = S; for(i = 0; i < rear; i ++) for(j = first[q[i]]; j != -1; j = next[j]) if(flow[j] && d[v[j]] == -1) { d[v[j]] = d[q[i]] + 1, q[rear ++] = v[j]; if(v[j] == T) return 1; } return 0; } int dfs(int cur, int a) { if(cur == T) return a; for(int &i = work[cur]; i != -1; i = next[i]) if(flow[i] && d[v[i]] == d[cur] + 1) if(int t = dfs(v[i], std::min(a, flow[i]))) { flow[i] -= t, flow[i ^ 1] += t; return t; } return 0; } void dinic() { while(bfs()) { memcpy(work, first, sizeof(first[0]) * N); while(dfs(S, INF)); } } void DFS(int cur, int *vis, int k) { int i; vis[cur] = 1; for(i = first[cur]; i != -1; i = next[i]) if(!vis[v[i]] && flow[i ^ k] != 0) DFS(v[i], vis, k); } void solve() { int i, cnt = 0; dinic(); memset(visx, 0, sizeof(visx[0]) * N), memset(visy, 0, sizeof(visy[0]) * N); DFS(S, visx, 0), DFS(T, visy, 1); for(i = 0; i < e; i += 2) if(flow[i] == 0 && visx[v[i ^ 1]] && visy[v[i]]) ++ cnt; printf("%d\n", cnt); } int main() { while(scanf("%d%d", &N, &M) == 2) { init(); solve(); } return 0; }