很简单的问题,最笨的算法,自己第一个用scheme写的稍微算长点的程序.
废话不多说,直接上代码.
(begin (load "ex2.scm") (define (make-maze) (define (for-each proc things) (cond ((null? things) nil) (else (let ((ret (proc (car things)))) (if (null? ret) (for-each proc (cdr things)) ret))))) ;迷宫 (define maze '((1 1 1 1 1 1 1 1 1) (1 0 1 0 0 0 1 0 1) (1 0 1 0 1 0 1 0 1) (1 0 1 0 1 0 1 0 1) (1 0 0 0 0 0 0 0 1) (1 1 1 1 1 1 1 1 1))) (define direction '((0 -1)(0 1)(-1 0)(1 0))) ;上下左右 (define (get-x-y array-2d x y) (list-ref (list-ref array-2d x) y)) (define (is-close cur path);是否已经走过的路 (= 1 (accumulate (lambda (pos sum) (if (and (= (car pos) (car cur)) (= (cadr pos) (cadr cur))) (+ sum 1) sum)) 0 path))) ;检查是否合法路径 (define (check cur dir path) (let ((x (+ (car dir) (car cur))) (y (+ (cadr dir) (cadr cur)))) (cond ((is-close (list x y) path) nil) ((= (get-x-y maze x y) 1) nil);阻挡 (else (list x y))))) ;返回下一步合法的坐标 ;返回一条路径 (define (find-path-one start target) (define (iter cur-step path) (define (move dir) (let ((next (check cur-step (list-ref direction dir) path))) (cond ((null? next) nil) (else (iter next (cons cur-step path)))))) (if (and (= (car target) (car cur-step)) (= (cadr target) (cadr cur-step))) (cons cur-step path) (for-each move (enumerate-interval 0 3))) ) (reverse (iter start nil)) ) ;返回所有路径 (define (find-path-all start target) (define (iter cur-step path) (define (move dir) (let ((next (check cur-step (list-ref direction dir) path))) (cond ((null? next) nil) (else (iter next (cons cur-step path)))))) (cond ((and (= (car target) (car cur-step)) (= (cadr target) (cadr cur-step))) (list (cons cur-step path))) ;到达目的地,返回路劲 (else (accumulate (lambda (dir p) (append (move dir) p)) nil (enumerate-interval 0 3)))) ) (map reverse (iter start nil)) ) (lambda (op start target) (cond ((eq? op 'find-path-all) (find-path-all start target)) ((eq? op 'find-path-one) (find-path-one start target)) (else "bad op")) )) ) ;(define maze make-maze) ;(maze 'find-path-one '(1 1) '(1 7))