• 洛谷 P3376 【模板】网络最大流


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    AcWing 2171 EK求最大流

    Version 1: EK

    #include <bits/stdc++.h>
    
    using namespace std;
    using ll = long long;
    using p = pair<int, int>;
    const int inf(0x3f3f3f3f);
    const int maxn(1e3 + 10);
    const int maxm(2e4 + 10);
    int ecnt, head[maxn];
    int mn[maxn], pre[maxn];
    bool vis[maxn];
    
    struct edge {
        int to, flow, nxt;
    } edges[maxm];
    
    template<typename T = int>
    inline const T read()
    {
        T x = 0, f = 1;
        char ch = getchar();
        while (ch < '0' or ch > '9') {
            if (ch == '-') f = -1;
            ch = getchar();
        }
        while (ch >= '0' and ch <= '9') {
            x = (x << 3) + (x << 1) + ch - '0';
            ch = getchar();
        }
        return x * f;
    }
    
    template<typename T>
    inline void write(T x, bool ln)
    {
        if (x < 0) {
            putchar('-');
            x = -x;
        }
        if (x > 9) write(x / 10, false);
        putchar(x % 10 + '0');
        if (ln) putchar(10);
    }
    
    inline void addEdge(int u, int v, int w)
    {
        edges[ecnt].to = v;
        edges[ecnt].flow = w;
        edges[ecnt].nxt = head[u];
        head[u] = ecnt++;
    }
    
    bool bfs(int src, int des)
    {
        queue<int> q;
        memset(vis, false, sizeof vis);
        q.push(src);
        vis[src] = true;
        mn[src] = inf;
        while (not q.empty()) {
            int u = q.front();
            q.pop();
            for (int i = head[u]; compl i; i = edges[i].nxt) {
                int v = edges[i].to, w = edges[i].flow;
                if (not vis[v] and w) {
                    vis[v] = true;
                    mn[v] = min(mn[u], w);
                    pre[v] = i;
                    if (v == des) {
                        return true;
                    }
                    q.push(v);
                }
            }
        }
        return false;
    }
    
    ll ek(int src, int des)
    {
        ll res = 0;
        while (bfs(src, des)) {
            res += mn[des];
            for (int i = des; i not_eq src; i = edges[pre[i] xor 1].to) {
                edges[pre[i]].flow -= mn[des];
                edges[pre[i] xor 1].flow += des;
            }
        }
        return res;
    }
    
    int main()
    {
    #ifndef ONLINE_JUDGE
        freopen("input.txt", "r", stdin);
    #endif
        memset(head, -1, sizeof head);
        int n = read(), m = read(), s = read(), t = read();
        while (m--) {
            int u = read(), v = read(), w = read();
            addEdge(u, v, w);
            addEdge(v, u, 0);
        }
        write(ek(s, t), true);
        return 0;
    }
    

    Version 2: Dinic

    #include <bits/stdc++.h>
    
    using namespace std;
    using ll = long long;
    using p = pair<int, int>;
    const int inf(0x3f3f3f3f);
    const int maxn(1e4 + 10);
    const int maxm(2e5 + 10);
    int ecnt, head[maxn];
    int dep[maxn], cur[maxn];
    
    struct edge {
        int to, flow, nxt;
    } edges[maxm];
    
    template<typename T = int>
    inline const T read()
    {
        T x = 0, f = 1;
        char ch = getchar();
        while (ch < '0' or ch > '9') {
            if (ch == '-') f = -1;
            ch = getchar();
        }
        while (ch >= '0' and ch <= '9') {
            x = (x << 3) + (x << 1) + ch - '0';
            ch = getchar();
        }
        return x * f;
    }
    
    template<typename T>
    inline void write(T x, bool ln)
    {
        if (x < 0) {
            putchar('-');
            x = -x;
        }
        if (x > 9) write(x / 10, false);
        putchar(x % 10 + '0');
        if (ln) putchar(10);
    }
    
    inline void addEdge(int u, int v, int w)
    {
        edges[ecnt].to = v;
        edges[ecnt].flow = w;
        edges[ecnt].nxt = head[u];
        head[u] = ecnt++;
    }
    
    bool bfs(int src, int des)
    {
        queue<int> q;
        memset(dep, -1, sizeof(dep));
        dep[src] = 0;
        q.push(src);
        while (not q.empty()) {
            int u = q.front();
            q.pop();
            for (int i = head[u]; compl i; i = edges[i].nxt) {
                int v = edges[i].to, w = edges[i].flow;
                if (dep[v] == -1 and w) {
                    q.push(v);
                    dep[v] = dep[u] + 1;
                }
            }
        }
        return compl dep[des];
    }
    
    int dfs(int u, int des, int rflow)
    {
        if (u == des) return rflow;
        int res = 0;
        for (int i = cur[u]; compl i and rflow; i = edges[i].nxt) {
            int v = edges[i].to;
            if (dep[v] not_eq dep[u] + 1 or not edges[i].flow) continue;
            cur[u] = i;
            int flow = dfs(v, des, min(edges[i].flow, rflow));
            edges[i].flow -= flow;
            edges[i xor 1].flow += flow;
            rflow -= flow;
            res += flow;
        }
        if (not res) dep[u] = -1;
        return res;
    }
    
    ll dinic(int src, int des)
    {
        ll res = 0;
        while (bfs(src, des)) {
            memcpy(cur, head, sizeof(head));
            res += dfs(src, des, inf);
        }
        return res;
    }
    
    int main()
    {
    #ifndef ONLINE_JUDGE
        freopen("input.txt", "r", stdin);
    #endif
        int n = read(), m = read(), s = read(), t = read();
        memset(head, -1, sizeof(head));
        while (m--) {
            int u = read(), v = read(), w = read();
            addEdge(u, v, w);
            addEdge(v, u, 0);
        }
        write(dinic(s, t), true);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/singularity2u/p/14091538.html
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