• Codeforces 1490E Accidental Victory


    E. Accidental Victory
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    A championship is held in Berland, in which nn players participate. The player with the number ii has aiai (ai1ai≥1) tokens.

    The championship consists of n1n−1 games, which are played according to the following rules:

    • in each game, two random players with non-zero tokens are selected;
    • the player with more tokens is considered the winner of the game (in case of a tie, the winner is chosen randomly);
    • the winning player takes all of the loser's tokens;

    The last player with non-zero tokens is the winner of the championship.

    All random decisions that are made during the championship are made equally probable and independently.

    For example, if n=4n=4, a=[1,2,4,3]a=[1,2,4,3], then one of the options for the game (there could be other options) is:

    • during the first game, the first and fourth players were selected. The fourth player has more tokens, so he takes the first player's tokens. Now a=[0,2,4,4]a=[0,2,4,4];
    • during the second game, the fourth and third players were selected. They have the same number of tokens, but in a random way, the third player is the winner. Now a=[0,2,8,0]a=[0,2,8,0];
    • during the third game, the second and third players were selected. The third player has more tokens, so he takes the second player's tokens. Now a=[0,0,10,0]a=[0,0,10,0];
    • the third player is declared the winner of the championship.

    Championship winners will receive personalized prizes. Therefore, the judges want to know in advance which players have a chance of winning, i.e have a non-zero probability of winning the championship. You have been asked to find all such players.

    Input

    The first line contains one integer tt (1t1041≤t≤104) — the number of test cases. Then tt test cases follow.

    The first line of each test case consists of one positive integer nn (1n21051≤n≤2⋅105) — the number of players in the championship.

    The second line of each test case contains nn positive integers a1,a2,,ana1,a2,…,an (1ai1091≤ai≤109) — the number of tokens the players have.

    It is guaranteed that the sum of nn over all test cases does not exceed 21052⋅105.

    Output

    For each test case, print the number of players who have a nonzero probability of winning the championship. On the next line print the numbers of these players in increasing order. Players are numbered starting from one in the order in which they appear in the input.

    Example
    input
    Copy
    2
    4
    1 2 4 3
    5
    1 1 1 1 1
    
    output
    Copy
    3
    2 3 4 
    5
    1 2 3 4 5 

    排序,求前缀和,倒着往前来判断
     1 //2021-03-15 19:37:42
     2 #include <iostream>
     3 #include <cstdio>
     4 #include <cstring>
     5 #include <algorithm>
     6 using namespace std;
     7 
     8 typedef long long ll;
     9 
    10 const int N = 2e5+10;
    11 
    12 int T, n;
    13 ll sum[N];
    14 struct node{
    15     int id;
    16     ll a;
    17 }a[N];
    18 
    19 bool cmp(node a, node b){
    20     return a.a < b.a;
    21 }
    22 int b[N];
    23 
    24 int main(){
    25     scanf("%d", &T);
    26     while(T--){
    27         scanf("%d", &n);
    28         for(int i = 1; i <= n; i++){
    29             scanf("%lld", &a[i].a);
    30             a[i].id = i;
    31         }
    32         sort(a+1, a+n+1, cmp);
    33         for(int i = 1; i <= n; i++) sum[i] = sum[i-1] + a[i].a;
    34         ll ans = 1;
    35         for(int i = n-1; i >= 1; i--){
    36             if(sum[i] >= a[i+1].a) ans++;
    37             else break;
    38         }
    39         printf("%lld
    ", ans);
    40         int tot = 0;
    41         for(int i = n-ans+1; i <= n; i++){
    42             b[++tot] = a[i].id;
    43         }
    44         sort(b+1, b+tot+1);
    45         for(int i = 1; i <= tot; i++)
    46             printf("%d ", b[i]);
    47         printf("
    ");
    48             
    49         
    50     }
    51     
    52     return 0;    
    53 }
  • 相关阅读:
    创建异步Web服务
    MCAD考试计划
    微软面试题
    Reborn
    Qt项目注意事项
    在ASP.Net中两种利用CSS实现多界面
    为ASP.NET控件添加常用的JavaScript操作
    用Split函数分隔字符串
    Microsoft .NET Pet Shop 4.0
    搞定QString,string,char*,CString的互转
  • 原文地址:https://www.cnblogs.com/sineagle/p/14539644.html
Copyright © 2020-2023  润新知