• 【NOI2012】美食节


    题面

    https://www.luogu.org/problemnew/show/P2050

    题解

    费用流+动态加点。

    #include<cstdio>
    #include<cstring>
    #include<iostream>
    #include<vector>
    #include<queue>
    #include<cstdlib>
    #define LL long long
    #define N 2000
    #define INF 1000000007
    #define S 0
    #define T (sumn+m+1)
    #define ri register int
    using namespace std;
    
    int n,m,sumn,cc;
    int typ[N],cai[N];
    int p[200][200];
    
    struct graph {
      vector<int> to,w,c;
      vector<int> ed[N];
      LL dis[N]; int cur[N];
      bool vis[N];
      void add_edge(int a,int b,int aw,int ac) {
        to.push_back(b); w.push_back(aw); c.push_back(ac);  ed[a].push_back(to.size()-1);
        to.push_back(a); w.push_back(0);  c.push_back(-ac); ed[b].push_back(to.size()-1);
      }
      bool spfa() {
        memset(dis,0x2f,sizeof(dis));
        memset(vis,0,sizeof(vis));
        queue<int> q;
        dis[S]=0;q.push(S);vis[S]=1;
        while (!q.empty()) {
          int x=q.front(); q.pop();
          for (ri i=0;i<ed[x].size();i++) {
            int e=ed[x][i];
            if (dis[to[e]]>dis[x]+c[e] && w[e]) {
              dis[to[e]]=dis[x]+c[e];
              if (!vis[to[e]]) vis[to[e]]=1,q.push(to[e]);
            }
          }
          vis[x]=0;
        }
        return dis[T]<INF;
      }
      int dfs(int x,int lim) {
        if (!lim) return lim;
        LL sum=0; vis[x]=1;
        for (ri &i=cur[x];i<ed[x].size();i++) {
          int e=ed[x][i];
          if (dis[x]+c[e]==dis[to[e]] && w[e] && !vis[to[e]]) {
            int f;
            if (to[e]==T) {
              //puts("54");
              f=lim; ++cc; typ[cc]=typ[x];
              for (ri j=0;j<ed[x].size();j++) {
                int je=ed[x][j];
                if (je%2==1) {
                  add_edge(to[je],cc,1,c[je^1]+p[cai[to[je]]][typ[cc]]);
                  //cout<<-c[je]+p[cai[to[je]]][typ[cc]]<<endl;
                }
              }
              add_edge(cc,T,1,0);
            }
            else 
              f=dfs(to[e],min(lim,w[e]));
            w[e]-=f; w[1^e]+=f;
            lim-=f; sum+=f;
            if (!lim) return sum;
          }
        }
        return sum;
      }
      LL zkw() {
        LL ret=0;
        while (spfa()) {
          memset(vis,0,sizeof(vis));
          memset(cur,0,sizeof(cur));
          ret+=dfs(S,INF)*dis[T];
        }
        return ret;
      }
    } G;
    
    int main() {
      int x;
      scanf("%d %d",&n,&m);
      sumn=0;
      for (ri i=1;i<=n;i++) {
        scanf("%d",&x);
        cai[i]=i;
        G.add_edge(S,i,x,0);
      }
      sumn=n;
      for (ri i=1;i<=n;i++) 
        for (ri j=1;j<=m;j++) scanf("%d",&p[i][j]);
      for (ri i=1;i<=m;i++) {
        G.add_edge(sumn+i,T,1,0);
        typ[sumn+i]=i;
      }
      for (ri i=1;i<=sumn;i++)
        for (ri j=1;j<=m;j++) G.add_edge(i,sumn+j,1,p[cai[i]][j]);
      cc=T;
      cout<<G.zkw()<<endl;
    }
  • 相关阅读:
    Http和Socket连接区别
    解决TCP网络传输“粘包”问题
    c# 获取MAC IP TCP列表
    《你不常用的c#之四》:Array的小抽屉ArraySegment
    《你不常用的c#之三》:Action 之怪状
    《你不常用的c#之二》:略谈GCHandle
    c#中var关键字用法
    Combotree--别样的构建层级json字符串
    一周代码秀之[11.18~11.24 linq2xml面向对象]
    这个季节的这些时候
  • 原文地址:https://www.cnblogs.com/shxnb666/p/11218805.html
Copyright © 2020-2023  润新知