• 大数据第40天—Mysql练习题11-行程和用户-杨大伟


    需求:写一段 SQL 语句查出 2019年10月1日 至 2019年10月3日 期间非禁止用户的取消率。基于上表,你的 SQL 语句应返回如下结果,取消率(Cancellation Rate)保留两位小数。

    取消率的计算方式如下:(被司机或乘客取消的非禁止用户生成的订单数量) / (非禁止用户生成的订单总数)

    Trips表:所有出租车的行程信息。每段行程有唯一键 Id,Client_Id 和 Driver_Id 是 Users 表中 Users_Id 的外键。Status 是枚举类型,枚举成员为 (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’)。

     

    IdClient_IdDriver_IdCity_IdStatusRequest_at
    1 1 10 1 completed 2019-10-01
    2 2 11 1 cancelled_by_driver 2019-10-01
    3 3 12 6 completed 2019-10-01
    4 4 13 6 cancelled_by_client 2019-10-01
    5 1 10 1 completed 2019-10-02
    6 2 11 6 completed 2019-10-02
    7 3 12 6 completed 2019-10-02
    8 2 12 12 completed 2019-10-03
    9 3 10 12 completed 2019-10-03
    10 4 13 12 cancelled_by_driver 2019-10-03

    Users 表存所有用户。每个用户有唯一键 Users_Id。Banned 表示这个用户是否被禁止,Role 则是一个表示(‘client’, ‘driver’, ‘partner’)的枚举类型。

    Users_IdBannedCancellation Rate
    1 No client
    2 Yes client
    3 No client
    4 No client
    10 No driver
    11 No driver
    12 No driver
    13 No driver

    展示效果:

    DayCancellation Rate
    2019-10-01 0.33
    2019-10-02 0.00
    2019-10-03 0.50
     1 Create table If Not Exists Trips (Id int, Client_Id int, Driver_Id int, City_Id int, Status ENUM('completed', 'cancelled_by_driver', 'cancelled_by_client'), Request_at varchar(50));
     2 
     3 Create table If Not Exists Users (Users_Id int, Banned varchar(50), Role ENUM('client', 'driver', 'partner'));
     4 
     5 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (1, 1, 10, 1, 'completed', '2019-10-01');
     6 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (2, 2, 11, 1, 'cancelled_by_driver', '2019-10-01');
     7 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (3, 3, 12, 6, 'completed', '2019-10-01');
     8 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (4, 4, 13, 6, 'cancelled_by_client', '2019-10-01');
     9 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (5, 1, 10, 1, 'completed', '2019-10-02');
    10 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (6, 2, 11, 6, 'completed', '2019-10-02');
    11 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (7, 3, 12, 6, 'completed', '2019-10-02');
    12 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (8, 2, 12, 12, 'completed', '2019-10-03');
    13 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (9, 3, 10, 12, 'completed', '2019-10-03');
    14 insert into Trips (Id, Client_Id, Driver_Id, City_Id, Status, Request_at) values (10, 4, 13, 12, 'cancelled_by_driver', '2019-10-03');
    15 
    16 insert into Users (Users_Id, Banned, Role) values (1, 'No', 'client');
    17 insert into Users (Users_Id, Banned, Role) values (2, 'Yes', 'client');
    18 insert into Users (Users_Id, Banned, Role) values (3, 'No', 'client');
    19 insert into Users (Users_Id, Banned, Role) values (4, 'No', 'client');
    20 insert into Users (Users_Id, Banned, Role) values (10, 'No', 'driver');
    21 insert into Users (Users_Id, Banned, Role) values (11, 'No', 'driver');
    22 insert into Users (Users_Id, Banned, Role) values (12, 'No', 'driver');
    23 insert into Users (Users_Id, Banned, Role) values (13, 'No', 'driver');

    最终SQL:

     1 方法一:
     2 SELECT 
     3       T.request_at AS `Day`, 
     4       ROUND(
     5             SUM(IF(T.STATUS = 'completed',0,1))/ COUNT(T.STATUS),
     6             2
     7             ) AS `Cancellation Rate`
     8 FROM 
     9       Trips AS T
    10 JOIN 
    11       Users AS U1 
    12 ON 
    13       T.client_id = U1.users_id AND U1.banned ='No'
    14 JOIN 
    15       Users AS U2 
    16 ON 
    17       T.driver_id = U2.users_id AND U2.banned ='No'
    18 WHERE 
    19       T.request_at BETWEEN '2019-10-01' AND '2019-10-03'
    20 GROUP BY 
    21       T.request_at;
    22 
    23 方法二:
    24 SELECT 
    25       T.request_at AS `Day`, 
    26       ROUND(
    27             SUM(IF(T.STATUS = 'completed',0,1))/ COUNT(T.STATUS),
    28             2
    29             ) AS `Cancellation Rate`
    30 FROM 
    31      trips AS T 
    32 LEFT JOIN (
    33             SELECT
    34                   users_id
    35             FROM
    36                   users
    37             WHERE  
    38                   banned = 'Yes'
    39            ) AS A 
    40 ON 
    41      T.Client_Id = A.users_id
    42 LEFT JOIN (
    43             SELECT
    44                   users_id
    45             FROM 
    46                   users
    47             WHERE 
    48                   banned = 'Yes'
    49            ) AS A1
    50 ON 
    51      T.Driver_Id = A1.users_id
    52 WHERE 
    53      A.users_id IS NULL 
    54      AND A1.users_id IS NULL 
    55      AND T.request_at BETWEEN '2019-10-01' AND '2019-10-03'
    56 GROUP BY 
    57      T.request_at;
    58 
    59 方法三:
    60 SELECT 
    61      T.request_at AS `Day`, 
    62      ROUND(
    63            SUM(IF(T.STATUS = 'completed',0,1))/ COUNT(T.STATUS),
    64            2
    65            ) AS `Cancellation Rate`
    66 FROM
    67      trips AS T
    68 WHERE 
    69      T.Client_Id NOT IN (
    70                           SELECT 
    71                                  users_id
    72                           FROM 
    73                                  users
    74                           WHERE 
    75                                  banned = 'Yes'
    76      )
    77 AND
    78      T.Driver_Id NOT IN (
    79                            SELECT 
    80                                  users_id
    81                            FROM  
    82                                  users
    83                            WHERE 
    84                                  banned = 'Yes'
    85      )
    86 AND 
    87      T.request_at BETWEEN '2019-10-01' AND '2019-10-03';
  • 相关阅读:
    ThinkPHP讲解(一)框架基础
    smarty简单介绍
    留言板
    文件系统处理
    文件上传(带有预览模式)
    文件上传(无预览模式版)
    注册、登陆、审核练习
    session讲解(二)——商城购物车练习
    session讲解(一)——登录网页练习
    P6216 回文匹配
  • 原文地址:https://www.cnblogs.com/shui68home/p/13519154.html
Copyright © 2020-2023  润新知