• 大数乘法(分治)


    java代码(long需要改变)

    import java.util.Arrays;
    import java.util.Scanner;
    public class 大数乘法 {
        public static void main(String[] args) {
            Scanner in = new Scanner(System.in);
            System.out.println("输入数据:");
            String a = in.nextLine();
            String b = in.nextLine();
            long num1 = temp(a);
            long num2 = temp(b);
            String result1 =  bigNumberMulti(a, b);
            long result2 = karatsubaMulti(num1, num2);
            System.out.println("普通大数乘法的结果:
    "+a+" * "+b+"
    = "+result1);
            System.out.println("Karatsuba大数乘法结果:
    "+a+" * "+b+"
    = "+result2);
    
        }
    
    
    
        public static String bigNumberMulti(String a, String b){
            //字符串转换成数组
            char[] charArr1 = a.trim().toCharArray();
            char[] charArr2 = b.trim().toCharArray();
            int[] arr1 = new int[charArr1.length];
            int[] arr2 = new int[charArr2.length];
            for (int i = 0; i < charArr1.length; i++) {
                arr1[i] = charArr1[i] - '0';
            }
            for (int i = 0; i < charArr2.length; i++) {
                arr2[i] = charArr2[i] - '0';
            }
    
            //大数乘法(不进位)
            int[] result = new int[arr1.length + arr2.length];
            for (int i = 0; i < arr1.length; i++) {
                for (int j = 0; j < arr2.length; j++) {
                    result[i+j+1] += arr1[i] * arr2[j];
                }
            }
            //处理进位,result是逆序储存的
            for (int k = result.length - 1; k > 0; k--) {
                if(result[k] >= 10 && k != 1){
                    result[k-1] += result[k]/10;
                    result[k] %= 10;
                }
            }
            String resultStr = "";
            for (int i = 1; i < result.length; i++) {
                resultStr += ""+result[i];
            }
            return resultStr;
        }
        public static long karatsubaMulti(long num1, long num2 ){
            if(num1 < 10 || num2 < 10)
                return num1*num2;
            int size1 = String.valueOf(num1).length();
            int size2 = String.valueOf(num2).length();
            int halfSize = Math.max(size1, size2) / 2;
    
            long a = Long.valueOf(String.valueOf(num1).substring(0, size1 - halfSize));
            long b = Long.valueOf(String.valueOf(num1).substring(size1 - halfSize));
            long c = Long.valueOf(String.valueOf(num2).substring(0, size2 - halfSize));
            long d = Long.valueOf(String.valueOf(num2).substring(size2 - halfSize));
    
            long x0 = karatsubaMulti(b, d);
            long x2 = karatsubaMulti(a, c);
            long x1 = karatsubaMulti((a+b), (c+d)) - x0 - x2;
    
            return (long)(x2*Math.pow(10, (2*halfSize)) + x1*Math.pow(10, halfSize) + x0);
    
        }
        public static long temp(String a){
            long result = 0;
            for (int i = 0; i < a.length(); i++) {
                result *= 10;
                result += a.charAt(i) - '0';
            }
            return result;
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/shish/p/12685799.html
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