Solve the equation:
p∗e−x + q∗sin(x) + r∗cos(x) + s∗tan(x) + t∗x2 + u = 0
where 0 ≤ x ≤ 1.
Input
Input consists of multiple test cases and terminated by an EOF. Each test case consists of 6 integers in a single line: p, q, r, s, t and u (where 0 ≤ p, r ≤ 20 and −20 ≤ q,s,t ≤ 0). There will be maximum 2100 lines in the input file.
Output
For each set of input, there should be a line containing the value of x, correct up to 4 decimal places, or the string ‘No solution’, whichever is applicable.
Sample Input
0 0 0 0 -2 1
1 0 0 0 -1 2
1 -1 1 -1 -1 1
Sample Output
0.7071
No solution
0.7554
解题思路
函数可判断出来为单调递减函数,因此判断两端点后二分查找
#include <iostream> #include <cstdio> #include <cstring> #include <queue> #include <cmath> #include <vector> #include <set> #include <map> #include <algorithm> using namespace std; typedef long long ll; #define mod (10e-8) double p,q,r,s,t,u; double check(double x) { return p*exp((-1)*x)+q*sin(x)+r*cos(x)+s*tan(x)+t*x*x+u; } int main() { while(scanf("%lf%lf%lf%lf%lf%lf",&p,&q,&r,&s,&t,&u)!=EOF) { double left=0.0,right=1.0,mid; if(check(left)*check(right)>0){ puts("No solution"); continue; } while((right-left)>mod) { mid=(left+right)/2.0; if(check(left)*check(mid)>0) left=mid; else right=mid; } printf("%.4f ",mid); } return 0; }