1, 获取json字符串中属性(传统方式)
import net.sf.json.JSONObject
JSONObject json = JSONObject.fromObject(response); json.getString("qrcode")
2,获取json字符串中属性(面向对象方式)
import com.fasterxml.jackson.databind.ObjectMapper
PaymentResponse response = new ObjectMapper().readValue(json, PaymentResponse.class);
3,从json文件中反序列化
ObjectMapper mapper = new ObjectMapper(); InputStream is = WebServiceConfig.class.getResourceAsStream("/webservice.json"); TypeFactory typeFactory = mapper.getTypeFactory(); CollectionType collectionType = typeFactory.constructCollectionType(List.class, WebServiceConfig.class); List<WebServiceConfig> config1 = mapper.readValue(is, collectionType);
如果不是集合对象则简单
ObjectMapper mapper = new ObjectMapper(); InputStream is = WebServiceConfig.class.getResourceAsStream("/webservice.json"); WebServiceConfig config1 = mapper.readValue(is, WebServiceConfig.Class);
如果Json文件中有些属性是没有的要加上
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
4, 把对象转换成json字符串
JSONArray.fromObject(user)
5,把json字符串转成对象
JSONObject jsonObject = JSONObject.fromObject(json); BaseUserInfo Address = (BaseUserInfo) JSONObject.toBean(jsonObject, BaseUserInfo.class);
6,对象与json互转
ObjectMapper objectMapper = new ObjectMapper(); // 将Java对象序列化为Json字符串 String objectToJson = objectMapper.writeValueAsString(initUser()); System.out.println(objectToJson); // 将Json字符串反序列化为Java对象 User user = objectMapper.readValue(objectToJson, User.class); System.out.println(user);