• 使用原生JS发送AJAX请求(XML,JSON解析)


    mybutton.addEventListener('click', (e) => {
        let request = new XMLHttpRequest()
        request.onreadystatechange = () => {
            if(request.readyState === 4) {
                console.log('请求完毕')
                if(request.status >= 200 & request.status <= 300) {
                    console.log('请求成功')
                    console.log(request.responseText)
                    //解析xml
                    //let parser = new DOMParser();
                    //let xmlDoc = parser.parseFromString(request.responseText, "text/xml")
                    //let body=xmlDoc.getElementsByTagName('body')[0].textContent
                    //console.log(body)
                    //解析json    服务器返回的是字符串            
                    let string = request.responseText
                    let obj = window.JSON.parse(string)
                    console.log(obj)
                    console.log(obj.note)
                    console.log(obj.note.to)
                } else if(request.status >= 400) {
                    console.log('请求失败')
                }
            }
        }
        request.open('GET', '/xxx')
        request.send()
    })
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  • 原文地址:https://www.cnblogs.com/ronyjay/p/9189687.html
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