• hdu 1565&&hdu 1569 (最大点权独立集)


    题目意思很明确就是选一些没有相连的数字,使和最大,建成二分图后求最大点权独立集,,





    #include<stdio.h>
    #include<string.h>
    const int N=2510;
    const int inf=0x3fffffff;
    int dis[N],gap[N],head[N],num,start,end,ans;
    struct edge
    {
    	int ed,flow,next;
    }e[N*6];
    void addedge(int x,int y,int w)
    {
    	e[num].ed=y;e[num].flow=w;e[num].next=head[x];head[x]=num++;
    	e[num].ed=x;e[num].flow=0;e[num].next=head[y];head[y]=num++;
    }
    int dfs(int u,int minflow)
    {
    	if(u==end)return minflow;
    	int i,v,f,min_dis=ans-1,flow=0;
    	for(i=head[u];i!=-1;i=e[i].next)
    	{
    		v=e[i].ed;
    		if(e[i].flow<=0)continue;
    		if(dis[v]+1==dis[u])
    		{
    			f=dfs(v,e[i].flow>minflow-flow?minflow-flow:e[i].flow);
    			e[i].flow-=f;
    			e[i^1].flow+=f;
    			flow+=f;
    			if(flow==minflow)break;
    			if(dis[start]>=ans)return flow;
    		}
    		min_dis=min_dis>dis[v]?dis[v]:min_dis;
    	}
    	if(flow==0)
    	{
    		if(--gap[dis[u]]==0)
    			dis[start]=ans;
    		dis[u]=min_dis+1;
    		gap[dis[u]]++;
    	}
    	return flow;
    }
    int isap()
    {
    	int maxflow=0;
    	memset(dis,0,sizeof(dis));
    	memset(gap,0,sizeof(gap));
    	gap[0]=ans;
    	while(dis[start]<ans)
    		maxflow+=dfs(start,inf);
    	return maxflow;
    }
    int main()
    {
    	int i,n,w,j,x,sum,m;
    	while(scanf("%d%d",&n,&m)!=-1)
    	{
    		memset(head,-1,sizeof(head));
    		num=0;sum=0;start=0;end=n*m+1;ans=end+1;
    		for(i=1;i<=n;i++)
    		{
    			for(j=1;j<=m;j++)
    			{
    				x=i*m+j-m;
    				scanf("%d",&w);
    				sum+=w;
    				if((i+j)%2!=0)
    					addedge(x,end,w);
    				else 
    				{
    					addedge(start,x,w);
    					if(i>1)addedge(x,x-m,inf);
    					if(j>1)addedge(x,x-1,inf);
    					if(i<n)addedge(x,x+m,inf);
    					if(j<m)addedge(x,x+1,inf);
    				}
    			}
    		}
    		printf("%d
    ",sum-isap());
    	}
    	return 0;
    }


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  • 原文地址:https://www.cnblogs.com/riskyer/p/3262892.html
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