• python的组合数据类型及其内置方法说明


    python中,数据结构是通过某种方式(例如对元素进行编号),组织在一起数据结构的集合.

    python常用的组合数据类型有:序列类型,集合类型和映射类型
        在序列类型中,又可以分为列表和元组,字符串也属于序列类型
        在集合类型中,主要有集合类型
    	在映射类型中,主要有字典类型,字典是可变序列
    

    python中一切皆对象,组合数据类型也是对象,因此python的组合数据类型可以嵌套使用,列表中可以嵌套元组和字典,元组中也可以嵌套和字典,当然字典中也可以嵌套元组和列表,例如:['hello','world',[1,2,3]]

    元组,列表以及字符串等数据类型是"有大小的",也即其长度可使用内置函数len()测量
    python对象可以具有其可以被调用的特定“方法(函数)”		
    

    列表的常用内置方法

    在python中,列表使用[]创建,例如['hello','world','linux','python']
    列表是可变序列,其主要表现为:列表中的元素可以根据需要扩展和移除,而列表的内存映射地址不改变	
    列表属于序列类型,可以在python解释器中使用dir(list)查看列表的内置方法			
    

    append

    #在列表的末尾添加元素
    L.append(object) -- append object to end
    
    >>> l1=["hello","world"]
    >>> l2=[1,2,3,4]
    >>> l1.append("linux")
    >>> print(l1)
    ['hello', 'world', 'linux']
    >>> l2.append(5)
    >>> print(l2)
    [1, 2, 3, 4, 5]
    

    clear

    #清除列表中的所有元素
    L.clear() -> None -- remove all items from L
    
    >>> l1=["hello","world"]
    >>> l2=[1,2,3,4]
    >>> l1.clear()
    >>> print(l1)
    []
    >>> l2.clear()
    >>> print(l2)
    []
    

    copy

    #浅复制
    L.copy() -> list -- a shallow copy of L
    
    >>> l1=["hello","world","linux"]
    >>> id(l1)
    140300326525832
    >>> l2=l1.copy()
    >>> id(l2)
    140300326526024
    >>> print(l1)
    ['hello', 'world', 'linux']
    >>> print(l2)
    ['hello', 'world', 'linux']
    

    count

    #返回某个元素在列表中出现的次数
    L.count(value) -> integer -- return number of occurrences of value
    
    >>> l1=[1,2,3,4,2,3,4,1,2]
    >>> l1.count(1)
    2
    >>> l1.count(2)
    3
    >>> l1.count(4)
    2
    

    extend

    #把另一个列表扩展进本列表中
    L.extend(iterable) -- extend list by appending elements from the iterable
    
    >>> l1=["hello","world"]
    >>> l2=["linux","python"]
    >>> l1.extend(l2)
    >>> print(l1)
    ['hello', 'world', 'linux', 'python']
    

    index

    #返回一个元素第一次出现在列表中的索引值,如果元素不存在报错
    L.index(value, [start, [stop]]) -> integer -- return first index of value. Raises ValueError if the value is not present.
    
        >>> l1=[1,2,3,4,2,3,4,1,2]
    	>>> l1.index(1)
    	0
    	>>> l1.index(2)
    	1
    	>>> l1.index(4)
    	3
    	>>> l1.index(5)
    	Traceback (most recent call last):
    	  File "<stdin>", line 1, in <module>
    	ValueError: 5 is not in list
    

    insert

    #在这个索引之前插入一个元素
    L.insert(index, object) -- insert object before index
    
    	>>> l1=['hello', 'world', 'linux', 'python']
    	>>> l1.insert(1,"first")
    	>>> print(l1)
    	['hello', 'first', 'world', 'linux', 'python']
    	>>> l1.insert(1,"second")
    	>>> print(l1)
    	['hello', 'second', 'first', 'world', 'linux', 'python']
    

    pop

    #移除并返回一个索引上的元素,如果是一个空列表或者索引的值超出列表的长度则报错
    L.pop([index]) -> item -- remove and return item at index (default last).Raises IndexError if list is empty or index is out of range.
    
        >>> l1=['hello', 'world', 'linux', 'python']
    	>>> l1.pop()
    	'python'
    	>>> l1.pop(1)
    	'world'
    	>>> l1.pop(3)
    	Traceback (most recent call last):
    	  File "<stdin>", line 1, in <module>
    	IndexError: pop index out of range
    

    remove

    #移除第一次出现的元素,如果元素不存在则报错
    L.remove(value) -- remove first occurrence of value.
    Raises ValueError if the value is not present.
    
    	>>> l1=['hello', 'world', 'linux', 'python']
    	>>> l1.remove("hello")
    	>>> print(l1)
    	['world', 'linux', 'python']
    	>>> l1.remove("linux")
    	>>> print(l1)
    	['world', 'python']
    	>>> l1.remove("php")
    	Traceback (most recent call last):
    	  File "<stdin>", line 1, in <module>
    	ValueError: list.remove(x): x not in list
    

    reverse

    #原地反转列表
    L.reverse() -- reverse *IN PLACE*
    
    	>>> l1=['hello', 'world', 'linux', 'python']
    	>>> id(l1)
    	140300326525832
    	>>> l1.reverse()####
    	>>> print(l1)
    	['python', 'linux', 'world', 'hello']
    	>>> id(l1)
    	140300326525832
    

    sort

    #对列表进行原地排序
    L.sort(cmp=None, key=None, reverse=False) -- stable sort *IN PLACE*;
    
    	>>> l1=[1,3,5,7,2,4,6,8]
    	>>> id(l1)
    	140300326526024
    	>>> l1.sort()
    	>>> print(l1)
    	[1, 2, 3, 4, 5, 6, 7, 8]
    	>>> id(l1)
    	140300326526024
    

    元组的常用内置方法

    元组则使用()创建,例如('hello','world'),元组是不可变序列,其主要表现为元组的元素不可以修改,但是元组的元素的元素可以被修改
    元组属于序列类型,可以在python解释器中使用dir(tuple)查看元组的内置方法
    

    count

    #返回某个元素在元组中出现的次数
    T.count(value) -> integer -- return number of occurrences of value
    
    >>> t1=("hello","world",1,2,3,"linux",1,2,3)
    >>> t1.count(1)
    2
    >>> t1.count(3)
    2
    >>> t1.count("hello")
    1
    

    index

    #返回元素在元组中出现的第一个索引的值,元素不存在则报错
    T.index(value, [start, [stop]]) -> integer -- return first index of value.Raises ValueError if the value is not present.
    
    >>> t1=("hello","world",1,2,3,"linux")
    >>> t1=("hello","world",1,2,3,"linux",1,2,3)
    >>> t1.count("hello")
    1
    >>> t1.index("linux")
    5
    >>> t1.index(3)
    4
    

    字典的常用内置方法

    字典属于映射类型,可以在python解释器中使用dir(dict)查看字典的内置方法

    clear

    #清除字典中所有的元素
    D.clear() -> None.  Remove all items from D.
    
    >>> dic1={"k1":11,"k2":22,"k3":"hello","k4":"world"}
    >>> print(dic1)
    {'k3': 'hello', 'k4': 'world', 'k2': 22, 'k1': 11}
    >>> dic1.clear()
    >>> print(dic1)
    {}
    

    copy

    #浅复制
    D.copy() -> a shallow copy of D
    
    >>> dic1={"k1":11,"k2":22,"k3":"hello","k4":"world"}
    >>> id(dic1)
    140300455000584
    >>> dic2=dic1.copy()
    >>> id(dic2)####
    140300455000648
    >>> print(dic2)
    {'k2': 22, 'k4': 'world', 'k3': 'hello', 'k1': 11}
    

    fromkeys(iterable, value=None, /)

    #返回一个以迭代器中的每一个元素做健,值为None的字典
    Returns a new dict with keys from iterable and values equal to value.
    
    >>> dic1={"k1":11,"k2":"hello"}
    >>> dic1.fromkeys([22,33,44,55])
    {33: None, 44: None, 22: None, 55: None}
    >>> print(dic1)
    {'k2': 'hello', 'k1': 11}
    

    get

    #查询某个元素是否在字典中,即使不存在也不会报错
    D.get(k[,d]) -> D[k] if k in D, else d.  d defaults to None.
    
    >>> dic1={'k3': None, 'k2': 'hello', 'k1': 11, 'k4': 'world'}
    >>> dic1.get("k3")
    >>> value1=dic1.get("k1")
    >>> print(value1)
    11
    >>> value2=dic1.get("k2")
    >>> print(value2)
    hello
    >>> value3=dic1.get("k5")
    >>> print(value3)
    None
    

    items

    #返回一个由每个键及对应的值构成的元组组成的列表
    D.items() -> a set-like object providing a view on D's items
    
    >>> dic1={"k1":11,"k2":22,"k3":"hello","k4":"world"}
    >>> dic1.items()
    dict_items([('k3', 'hello'), ('k4', 'world'), ('k2', 22), ('k1', 11)])
    >>> type(dic1.items())
    <class 'dict_items'>
    

    keys

    #返回一个由字典所有的键构成的列表
    D.keys() -> a set-like object providing a view on D's keys
    
    >>> dic1={"k1":11,"k2":22,"k3":"hello","k4":"world"}
    >>> dic1.keys()
    ['k3', 'k2', 'k1', 'k4']
    

    pop

    #从字典中移除指定的键,返回这个键对应的值,如果键不存在则报错
    D.pop(k[,d]) -> v, remove specified key and return the corresponding value.
    If key is not found, d is returned if given, otherwise KeyError is raised
    
    >>> dic1={"k1":11,"k2":22}
    >>> dic1.pop("k1")
    11
    >>> dic1.pop("k2")
    22
    

    popitem

    #从字典中移除一个键值对,并返回一个由所移除的键和值构成的元组,字典为空时,会报错
    D.popitem() -> (k, v), remove and return some (key, value) pair as a 2-tuple; but raise KeyError if D is empty.
    
    >>> dic1={"k1":11,"k2":22}
    >>> dic1.popitem()
    ('k2', 22)
    >>> dic1.popitem()
    ('k1', 11)
    >>> dic1.popitem()
    Traceback (most recent call last):
      File "<stdin>", line 1, in <module>
    KeyError: 'popitem(): dictionary is empty'
    

    setdefault

    #参数只有一个时,字典会增加一个键值对,键为这个参数,值默认为None;后接两个参数时,第一个参数为字典新增的键,第二个参数为新增的键对应的值
    D.setdefault(k[,d]) -> D.get(k,d), also set D[k]=d if k not in D
    
    >>> dic1={"k1":11,"k2":"hello"}
    >>> dic1.setdefault("k3")
    >>> print(dic1)
    {'k3': None, 'k2': 'hello', 'k1': 11}
    >>> dic1.setdefault("k4","world")
    'world'
    >>> print(dic1)
    {'k3': None, 'k2': 'hello', 'k1': 11, 'k4': 'world'}
    

    update

    #把一个字典参数合并入另一个字典,当两个字典的键有重复时,参数字典的键值会覆盖原始字典的键值
    D.update([E, ]**F) -> None.  Update D from dict/iterable E and F.
    If E is present and has a .keys() method, then does:  for k in E: D[k] = E[k]
    If E is present and lacks a .keys() method, then does:  for k, v in E: D[k] = v
    In either case, this is followed by: for k in F:  D[k] = F[k]
    
    >>> dic1={"k1":11,"k2":"hello"}
    >>> dic2={"k3":22,"k4":"world"}
    >>> dic1.update(dic2)
    >>> print(dic1)
    {'k3': 22, 'k2': 'hello', 'k1': 11, 'k4': 'world'}
    >>> dic1={"k1":11,"k2":"hello"}
    >>> dic2={"k1":22,"k4":"world"}
    >>> dic1.update(dic2)
    >>> print(dic1)
    {'k2': 'hello', 'k1': 22, 'k4': 'world'}
    

    values

    #返回一个由字典的所有的值构成的列表
    D.values() -> an object providing a view on D's values
    
    >>> dic1={"k1":11,"k2":22,"k3":"hello","k4":"world"}
    >>> dic1.values()
    ['hello', 22, 11, 'world']
    
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  • 原文地址:https://www.cnblogs.com/renpingsheng/p/6999349.html
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