截取日期:
select to_char( NEW_TIME( sysdate, 'GMT','EST'), 'yyyy-mm')from dual;
或得年或月或日 Year/ month/Day
select to_char(to_date('2016-01-01','yyyy-mm-dd'),'month') from dual;
-------------------------------------------华丽的分割符----------------------------------------------------------
Year:
yy two digits 两位年 显示值:07
yyy three digits 三位年 显示值:007
yyyy four digits 四位年 显示值:2007
Month:
mm number 两位月 显示值:11
mon abbreviated 字符集表示 显示值:11月,若是英文版,显示nov
month spelled out 字符集表示 显示值:11月,若是英文版,显示november
Day:
dd number 当月第几天 显示值:02
ddd number 当年第几天 显示值:02
dy abbreviated 当周第几天简写 显示值:星期五,若是英文版,显示fri
day spelled out 当周第几天全写 显示值:星期五,若是英文版,显示friday
Hour:
hh two digits 12小时进制 显示值:01
hh24 two digits 24小时进制 显示值:13
Minute:
mi two digits 60进制 显示值:45
Second:
ss two digits 60进制 显示值:25
其它
Q digit 季度 显示值:4
WW digit 当年第几周 显示值:44
W digit 当月第几周 显示值:1
24小时格式下时间范围为: 0:00:00 - 23:59:59....
12小时格式下时间范围为: 1:00:00 - 12:59:59....
1. 日期和字符转换函数用法(to_date,to_char)
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select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss' ) as nowTime from dual; //日期转化为字符串 select to_char(sysdate, 'yyyy' ) as nowYear from dual; //获取时间的年 select to_char(sysdate, 'mm' ) as nowMonth from dual; //获取时间的月 select to_char(sysdate, 'dd' ) as nowDay from dual; //获取时间的日 select to_char(sysdate, 'hh24' ) as nowHour from dual; //获取时间的时 select to_char(sysdate, 'mi' ) as nowMinute from dual; //获取时间的分 select to_char(sysdate, 'ss' ) as nowSecond from dual; //获取时间的秒 |
2. 字符串和时间互转
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select to_date( '2004-05-07 13:23:44' , 'yyyy-mm-dd hh24:mi:ss' ) from dual select to_char( to_date( 222 , 'J' ), 'Jsp' ) from dual //显示Two Hundred Twenty-Two |
3.求某天是星期几
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select to_char(to_date( '2002-08-26' , 'yyyy-mm-dd' ), 'day' ) from dual; //星期一 select to_char(to_date( '2002-08-26' , 'yyyy-mm-dd' ), 'day' , 'NLS_DATE_LANGUAGE = American' ) from dual; // monday //设置日期语言 ALTER SESSION SET NLS_DATE_LANGUAGE= 'AMERICAN' ; //也可以这样 TO_DATE ( '2002-08-26' , 'YYYY-mm-dd' , 'NLS_DATE_LANGUAGE = American' ) |
4. 两个日期间的天数
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select floor(sysdate - to_date( '20020405' , 'yyyymmdd' )) from dual; |
5. 时间为null的用法
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select id, active_date from table1 UNION select 1 , TO_DATE( null ) from dual; //注意要用TO_DATE(null) |
6.月份差
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a_date between to_date( '20011201' , 'yyyymmdd' ) and to_date( '20011231' , 'yyyymmdd' ) //那么12月31号中午12点之后和12月1号的12点之前是不包含在这个范围之内的。 //所以,当时间需要精确的时候,觉得to_char还是必要的 |
7. 日期格式冲突问题
输入的格式要看你安装的ORACLE字符集的类型, 比如: US7ASCII, date格式的类型就是: '01-Jan-01'
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alter system set NLS_DATE_LANGUAGE = American alter session set NLS_DATE_LANGUAGE = American //或者在to_date中写 select to_char(to_date( '2002-08-26' , 'yyyy-mm-dd' ), 'day' , 'NLS_DATE_LANGUAGE = American' ) from dual; //注意我这只是举了NLS_DATE_LANGUAGE,当然还有很多,可查看 select * from nls_session_parameters select * from V$NLS_PARAMETERS |
8.查询特殊条件天数
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select count(*) from ( select rownum- 1 rnum from all_objects where rownum <= to_date( '2002-02-28' , 'yyyy-mm-dd' ) - to_date(' 2002 - 02 - 01 ',' yyyy-mm-dd')+ 1 ) where to_char( to_date( '2002-02-01' , 'yyyy-mm-dd' )+rnum- 1 , 'D' ) not in ( '1' , '7' ) //查找2002-02-28至2002-02-01间除星期一和七的天数 //在前后分别调用DBMS_UTILITY.GET_TIME, 让后将结果相减(得到的是1/100秒, 而不是毫秒). |
9. 查找月份
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select months_between(to_date( '01-31-1999' , 'MM-DD-YYYY' ), to_date( '12-31-1998' , 'MM-DD-YYYY' )) "MONTHS" FROM DUAL; //结果为:1 select months_between(to_date( '02-01-1999' , 'MM-DD-YYYY' ), to_date( '12-31-1998' , 'MM-DD-YYYY' )) "MONTHS" FROM DUAL; //结果为:1.03225806451613 |
10. Next_day的用法
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Next_day(date, day) Monday-Sunday, for format code DAY Mon-Sun, for format code DY 1 - 7 , for format code D |
11.获得小时数
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//extract()找出日期或间隔值的字段值 SELECT EXTRACT(HOUR FROM TIMESTAMP '2001-02-16 2:38:40' ) from offer select sysdate ,to_char(sysdate, 'hh' ) from dual; SYSDATE TO_CHAR(SYSDATE, 'HH' ) -------------------- --------------------- 2003 - 10 - 13 19 : 35 : 21 07 select sysdate ,to_char(sysdate, 'hh24' ) from dual; SYSDATE TO_CHAR(SYSDATE, 'HH24' ) -------------------- ----------------------- 2003 - 10 - 13 19 : 35 : 21 19 |
12.年月日的处理
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SELECT older_date, newer_date, years, months, ABS ( TRUNC ( newer_date - ADD_MONTHS (older_date, years * 12 + months) ) ) days FROM ( SELECT TRUNC ( MONTHS_BETWEEN (newer_date, older_date) / 12 ) YEARS, MOD ( TRUNC ( MONTHS_BETWEEN (newer_date, older_date) ), 12 ) MONTHS, newer_date, older_date FROM ( SELECT hiredate older_date, ADD_MONTHS (hiredate, ROWNUM) + ROWNUM newer_date FROM emp ) ) |
13.处理月份天数不定的办法
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select to_char(add_months(last_day(sysdate) + 1 , - 2 ), 'yyyymmdd' ),last_day(sysdate) from dual |
14.找出今年的天数
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select add_months(trunc(sysdate, 'year' ), 12 ) - trunc(sysdate, 'year' ) from dual //闰年的处理方法 to_char( last_day( to_date( '02' | | :year, 'mmyyyy' ) ), 'dd' ) //如果是28就不是闰年 |
15.yyyy与rrrr的区别
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YYYY99 TO_C ------- ---- yyyy 99 0099 rrrr 99 1999 yyyy 01 0001 rrrr 01 2001 |
16.不同时区的处理
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select to_char( NEW_TIME( sysdate, 'GMT' , 'EST' ), 'dd/mm/yyyy hh:mi:ss' ) , sysdate from dual; |
17. 5秒钟一个间隔
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Select TO_DATE(FLOOR(TO_CHAR(sysdate, 'SSSSS' )/ 300 ) * 300 , 'SSSSS' ) , TO_CHAR(sysdate, 'SSSSS' ) from dual //2002-11-1 9:55:00 35786 //SSSSS表示5位秒数 |
18.一年的第几天
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select TO_CHAR(SYSDATE, 'DDD' ),sysdate from dual //310 2002-11-6 10:03:51 |
19.计算小时,分,秒,毫秒
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SELECT Days, A, TRUNC (A * 24 ) Hours, TRUNC (A * 24 * 60 - 60 * TRUNC(A * 24 )) Minutes, TRUNC ( A * 24 * 60 * 60 - 60 * TRUNC (A * 24 * 60 ) ) Seconds, TRUNC ( A * 24 * 60 * 60 * 100 - 100 * TRUNC (A * 24 * 60 * 60 ) ) mSeconds FROM ( SELECT TRUNC (SYSDATE) Days, SYSDATE - TRUNC (SYSDATE) A FROM dual ) SELECT * FROM tabname ORDER BY DECODE (MODE, 'FIFO' , 1 ,- 1 ) * TO_CHAR (rq, 'yyyymmddhh24miss' ) // floor((date2-date1) /365) 作为年 // floor((date2-date1, 365) /30) 作为月 // d(mod(date2-date1, 365), 30)作为日. |
20.next_day函数
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//返回下个星期的日期,day为1-7或星期日-星期六,1表示星期日 next_day(sysdate, 6 )是从当前开始下一个星期五。后面的数字是从星期日开始算起。 // 1 2 3 4 5 6 7 //日 一 二 三 四 五 六 select (sysdate-to_date( '2003-12-03 12:55:45' , 'yyyy-mm-dd hh24:mi:ss' ))* 24 * 60 * 60 from dual //日期 返回的是天 然后 转换为ss |
21,round[舍入到最接近的日期](day:舍入到最接近的星期日)
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select sysdate S1, round(sysdate) S2 , round(sysdate, 'year' ) YEAR, round(sysdate, 'month' ) MONTH , round(sysdate, 'day' ) DAY from dual |
22,trunc[截断到最接近的日期,单位为天] ,返回的是日期类型
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select sysdate S1, trunc(sysdate) S2, //返回当前日期,无时分秒 trunc(sysdate, 'year' ) YEAR, //返回当前年的1月1日,无时分秒 trunc(sysdate, 'month' ) MONTH , //返回当前月的1日,无时分秒 trunc(sysdate, 'day' ) DAY //返回当前星期的星期天,无时分秒 from dual |
23,返回日期列表中最晚日期
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select greatest( '01-1月-04' , '04-1月-04' , '10-2月-04' ) from dual |
24.计算时间差
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注:oracle时间差是以天数为单位,所以换算成年月,日 select floor(to_number(sysdate-to_date( '2007-11-02 15:55:03' , 'yyyy-mm-dd hh24:mi:ss' ))/ 365 ) as spanYears from dual //时间差-年 select ceil(moths_between(sysdate-to_date( '2007-11-02 15:55:03' , 'yyyy-mm-dd hh24:mi:ss' ))) as spanMonths from dual //时间差-月 select floor(to_number(sysdate-to_date( '2007-11-02 15:55:03' , 'yyyy-mm-dd hh24:mi:ss' ))) as spanDays from dual //时间差-天 select floor(to_number(sysdate-to_date( '2007-11-02 15:55:03' , 'yyyy-mm-dd hh24:mi:ss' ))* 24 ) as spanHours from dual //时间差-时 select floor(to_number(sysdate-to_date( '2007-11-02 15:55:03' , 'yyyy-mm-dd hh24:mi:ss' ))* 24 * 60 ) as spanMinutes from dual //时间差-分 select floor(to_number(sysdate-to_date( '2007-11-02 15:55:03' , 'yyyy-mm-dd hh24:mi:ss' ))* 24 * 60 * 60 ) as spanSeconds from dual //时间差-秒 |
25.更新时间
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//oracle时间加减是以天数为单位,设改变量为n,所以换算成年月,日 select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss' ), to_char(sysdate+n* 365 , 'yyyy-mm-dd hh24:mi:ss' ) as newTime from dual //改变时间-年 select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss' ), add_months(sysdate,n) as newTime from dual //改变时间-月 select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss' ), to_char(sysdate+n, 'yyyy-mm-dd hh24:mi:ss' ) as newTime from dual //改变时间-日 select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss' ), to_char(sysdate+n/ 24 , 'yyyy-mm-dd hh24:mi:ss' ) as newTime from dual //改变时间-时 select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss' ), to_char(sysdate+n/ 24 / 60 , 'yyyy-mm-dd hh24:mi:ss' ) as newTime from dual //改变时间-分 select to_char(sysdate, 'yyyy-mm-dd hh24:mi:ss' ), to_char(sysdate+n/ 24 / 60 / 60 , 'yyyy-mm-dd hh24:mi:ss' ) as newTime from dual //改变时间-秒 |
26.查找月的第一天,最后一天
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SELECT Trunc(Trunc(SYSDATE, 'MONTH' ) - 1 , 'MONTH' ) First_Day_Last_Month, Trunc(SYSDATE, 'MONTH' ) - 1 / 86400 Last_Day_Last_Month, Trunc(SYSDATE, 'MONTH' ) First_Day_Cur_Month, LAST_DAY(Trunc(SYSDATE, 'MONTH' )) + 1 - 1 / 86400 Last_Day_Cur_Month FROM dual; |