• 排序算法的实现(归并,快排,堆排,希尔排序 O(N*log(N)))


          今天跟着左老师的视频,理解了四种复杂度为 O(N*log(N))的排序算法,以前也理解过过程,今天根据实际的代码,感觉基本的算法还是很简单的,只是自己写的时候可能一些边界条件,循环控制条件把握不好。

    //对于一个int数组,请编写一个选择冒泡算法,对数组元素排序。
    //给定一个int数组A及数组的大小n,请返回排序后的数组。
    //测试样例:
    //[1, 2, 3, 5, 2, 3], 6
    //[1, 2, 2, 3, 3, 5]
    
    
    #include <iostream> 
    using namespace std;
    #include<string>
    
    void printResult(string str,int* A,int n)
    {
        cout << str << "的结果:
    ";
        for (int i = 0; i < n; i++)
        {
            cout << A[i] <<" ";
        }
        cout << endl;
    }
    void swap(int *a, int *b)
    {
        int temp=*a;
        *a = *b;
        *b = temp;
    }
    
    //冒泡排序 O(n^2) 
    class BubbleSort {
    public:
        int* bubbleSort(int* A, int n) {
            // write code here
            for (int i = 0; i<n; i++)
            {
                for (int j = 0; j<n - i - 1; j++)
                {
                    if (A[j]>A[j + 1])
                    {
                        int temp = A[j];
                        A[j] = A[j + 1];
                        A[j + 1] = temp;
                    }
                }
            }
            return A;
        }
    };
    
    //请编写一个选择排序算法 O(n^2) 
    class SelectionSort {
    public:
        int* selectionSort(int* A, int n) {
            // write code here
            int k = 0;
            for (int i = 0; i < n-1; i++)
            {
                k = i;
                for (int j = i; j < n; j++)
                {
                    if (A[k]>A[j])
                    {
                        k = j;
                    }
                }
                if (k!=i)
                {
                    int temp = A[i];
                    A[i] = A[k];
                    A[k] = temp;
                }
            }
            return A;
        }
    };
    
    //请编写一个插入算法 O(n^2) 
    class InsertionSort
    {
    public:
        int* insertionSort(int* A, int n)
        {
            for (int i = 1; i < n; i++)
            {
                int temp = A[i];
                int j = i - 1;
                for (; j >= 0;j--)   //j前面的已经排好序,从后面往前比较,当没有比当前值大的时候bereak;
                {
                    if (A[j]>temp)
                    {
                        A[j + 1] = A[j];
                    }
                    else
                    {
                        break;
                    }
                }
                A[j + 1] = temp;
            }
            return A;
        }
    };
    
    //归并排序 O(N*log(N))
    class MergeSort {
    public:
        int* mergeSort(int* A, int n) {
            // write code here
            mergeSort(A, 0, n - 1);
            return A;
        }
        void mergeSort(int* A, int beg, int end)
        {
            if (beg < end)
            {
                int mid = beg + (end - beg) / 2;
                mergeSort(A, beg, mid);
                mergeSort(A, mid + 1, end);
                merge(A,beg,mid,end);
            }
            return;
        }
        void merge(int* A, int beg_, int mid_, int end_)
        {
            int *B = new int[end_ - beg_ + 1];
            int index1 = beg_;
            int index2 = mid_ + 1;
            int i = 0;
            while (index1<=mid_&&index2<=end_)
            {
                if (A[index1]<=A[index2])
                {
                    B[i++] = A[index1++];
                }
                else
                {
                    B[i++] = A[index2++];
                }
            }
            while (index1 <= mid_)
            {
                B[i++] = A[index1++];
            }
            while (index2<=end_)
            {
                B[i++] = A[index2++];
            }
            //memcpy(A,B,end_-beg_+1);
            for (int i = 0; i < end_ - beg_ + 1;i++)
            {
                A[beg_+i] = B[i];   //A[beg_++] 不能写,改变了输入参数
            }
            delete[] B;
        }
    };
    
    //快速排序 O(N*log(N))
    #include <math.h>
    class QuickSort {
    public:
        int* quickSort(int* A, int n) {
            // write code here
            quickSort(A, 0, n - 1);
            return A;
        }
        void quickSort(int* A, int low, int high)
        {
            if (low <= high)
            {
                int part = partition(A, low, high);
                quickSort(A, low, part - 1);
                quickSort(A, part + 1, high);
            }
            return;
        }
    
        int partition(int* A, int low, int high)
        {
            int privotKey = A[low];    //基准元素
            while (low < high)
            {        //从表的两端交替地向中间扫描
                while (low < high  && A[high] >= privotKey) 
                    --high;  //从high 所指位置向前搜索,至多到low+1 位置。将比基准元素小的交换到低端
                swap(&A[low], &A[high]);
                while (low < high  && A[low] <= privotKey) 
                    ++low;
                swap(&A[low], &A[high]);
            }
            return low;
        }
    };
    class QuickSort2 {
    public:
        int* quickSort(int* A, int n) {
            // write code here
            quickSort(A, 0, n - 1);
            return A;
        }
        void quickSort(int* A, int low, int high)
        {
            if (low <= high)
            {
                int randn = low + rand() % (high - low + 1);  //随机选择关键字的下标
                swap(&A[randn], &A[high]);                      //void swap(int* A,int index1,int index2) //最好都操作下标
    
                int part = partition(A, low, high);
                quickSort(A, low, part - 1);
                quickSort(A, part + 1, high);
            }
            return;
        }
    
        int partition(int* A, int low, int high) //O(N)
        {
            //int pivot = A[low];//很多随机选择放在这里面,而且是以值的形式确定,而非下标标记为关键字
            
            int pivot = low-1; //关键字的位置
            for (int i = low ; i <= high; i++)
            {
                if (A[i] <= A[high])
                {
                    swap(&A[i], &A[++pivot]);  //感觉这样会把A数组前面的值覆盖?-->其实没有交换的效果就是把前面的交换到后面
                }
            }
            return pivot;
        }
    };
    
    //推排序  O(N*log(N))
    class HeapSort {
    public:
        int* heapSort(int* A, int n) {
            // write code here
            buildHeap(A, n); //初始时构建堆
            //从最后一个元素开始对序列进行调整
            for (int i = n - 1; i >= 0;i--)
            {
                swap(&A[0], &A[i]);
                heapAdjust(A,0,i);
            }
            return A;
        }
    
        void buildHeap(int* A, int size_A)
        {
            for (int i = (size_A)/ 2-1; i >= 0; i--)
            {
                heapAdjust(A,i,size_A);
            }
        }
    
        void heapAdjust(int* A, int root, int size_A) //大顶堆
        {
            int leftchild = 2 * root + 1;
            if (leftchild<size_A) //递归形式
            {
                int rightchild = leftchild + 1;
                if (rightchild<size_A)
                {
                    if (A[leftchild]<A[rightchild])
                    {
                        leftchild = rightchild;
                    }
                }
                //leftchild为左右子节点中较大的结点
                if (A[root]<A[leftchild])
                {
                    int temp = A[root];
                    A[root] = A[leftchild];   //将较大结点值上移到根节点
                    A[leftchild] = temp; //完成交换,子节点变为以前的根节点
                    heapAdjust(A, leftchild, size_A);
                }
            }
            return;
        }
    };
    class HeapSort2 {
    public:
        int* heapSort(int* A, int n) {
            // write code here
            buildHeap(A, n); //初始时构建堆
            //从最后一个元素开始对序列进行调整
            for (int i = n - 1; i >= 0; i--)
            {
                swap(&A[0], &A[i]);
                heapAdjust(A, 0, i);
            }
            return A;
        }
    
        void buildHeap(int* A, int size_A)
        {
            for (int i = (size_A - 1) / 2; i >= 0; i--)
            {
                heapAdjust(A, i, size_A);
            }
        }
    
        void heapAdjust(int* A, int root, int size_A)  //调整为大顶堆
        {
            int temp = A[root];
            int leftchild = 2 * root + 1;
            while (leftchild < size_A) //非递归形式
            {
                int rightchild = leftchild + 1;
                if (rightchild < size_A)
                {
                    if (A[leftchild] < A[rightchild])
                    {
                        leftchild = rightchild;
                    }
                }
                //leftchild为左右子节点中较大的结点
                if (A[root] < A[leftchild])
                {
                    A[root] = A[leftchild];   //将较大结点值上移到根节点
                    root = leftchild;         //更新新的根节点
                    leftchild = 2 * root + 1;        
                }
                else  //当前结点大于左右子节点则不需要调整
                {
                    break;
                }        
                A[root] = temp; //完成交换,子节点变为以前的根节点
            }
            return;
        }
    };
    
    //希尔排序  O(N*log(N)) ---不稳定
    class ShellSort {
    public:
        int* shellSort(int* A, int n) {
            // write code here
            int dk = n / 2;
            while (dk>=1)
            {
                shellSort2(A,n,dk);
                dk /= 2;
            }
            return A;
        }
        void shellSort(int* A, int n, int dk)
        {
            for (int i = dk; i < n;i++)
            {
                int index = i; //当前访问的位置
                while (index>=dk)
                {
                    if (A[index-dk]>A[index])
                    {
                        swap(&A[index-dk],&A[index]); //交换不算最优,找到插入位置才交换
                        index -= dk;
                    }
                    else
                    {
                        break;
                    }
                }
            }
        }
        void shellSort2(int* A,int n,int dk)
        {
            for (int i = dk; i < n;i++)
            {
                if (A[i]<A[i-dk]) //找到插入位置
                {
                    int x = A[i];//复制哨兵
                    A[i] = A[i - dk];
                    int j = i - dk; //从该位置向前查找
                    while (x<A[j]&&j>=0) //防止j越界
                    {
                        A[j] = A[j - dk];
                        j -= dk; //向前移动
                    }
                    A[j + dk] = x;// 插入到正确位置
                }
            }
        }
    
    };
    
    
    #define N 13
    int main()
    {
        //待排数据输入方式:
            /*int N = 0;
            cout << "排序数据个数:
    ";
            cin >> N;
            int* A = new int[N];
            cout << "请输入待排序的数据:
    ";
            for (int i = 0; i < N; i++)
            {
            cin >> A[i];
            }*/
        //数据直接给定    
            int B[N] = { 1, 6, 3, 5, 2, 4 };
            int C[13] = { 54, 35, 48, 36, 27, 12, 44, 44, 8, 14, 26, 17, 2 };
            int* A = C;
    
        //从文件中读取,大量数据,计算时间复杂度
            
        printResult("待排原始数据:", C, N);
    
        BubbleSort bubble;
        bubble.bubbleSort(A,N);
        printResult("bubbleSort", A, N);
    
        SelectionSort select;
        select.selectionSort(A, N);
        printResult("selectSort", A, N);
    
        InsertionSort insert;
        insert.insertionSort(A, N);
        printResult("InsetSort", A, N);
    
        MergeSort merge;
        merge.mergeSort(A, N);
        printResult("MergeSort", A, N);
    
        QuickSort qucik;
        qucik.quickSort(A, N);
        printResult("QucikSort",A,N);
    
        QuickSort2 qucik2;
        qucik2.quickSort(A, N);
        printResult("QucikSort2", A, N);
    
        HeapSort heap;
        heap.heapSort(A, N);
        printResult("heapSort", A, N);
    
        HeapSort2 heap2;
        heap2.heapSort(A, N);
        printResult("heapSort2", A, N);
    
    
        ShellSort shell;
        shell.shellSort(A,N);
        printResult("shellSort", A, N);
    
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/ranjiewen/p/5930560.html
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