• 四则运算改进


    github地址如下:

    https://github.com/huige666666/gaijin/commit/d3925696483426c57045a99ca4d22b7121bede46

    1,题目:

     对上一次的四则运算题目进行升级,我选择了对功能进行升级,使得计算时能够带括号进行运算。

    2,思路:

     实现的功能或者难点有以下几个:

    a. 连续运算

    b. 识别数字和运算符以及括号

    c. 乘法/除法和括号优先级的问题

    d. 把带小数的字符串转换成数字

    先算乘法和除法,把算完的结果储存在一个float类型的数组里面,把遇到的加号和减号放在一个字符数组里,最后再算加减法。当遇到括号时,运用递归的思想,先算出最里面的括号,依次算外面的,再进行下一组运算。

    当出现多级括号时,为了能够找到最里面的括号,并且准确的识别并保存括号内的数,用count_rcount_l计算左右两边括号的数目,从左边第一个括号开始,当右边的括号大于左边的括号时,就证明已经把里面的括号遍历完毕。

    3,代码说明:

     此时加了一个对多级括号的处理,当s1读取括号里的字符串时,如果右面的括号多于左边的括号,则读取字符串完毕,注意在下一次读取时要把运算符数组(operat)和左右括号的计数(count_lcount_r)重新变成0

     #include <cstdio>

    #include <cstring>

    float aux(char*s);

    int main()

    {

    float number[80],x=0,y=0,tem_y=1;

    int len,i=0,j=0,k=0,l=0,count_r=0,count_l=0,tem_j,tem_k,tem_i;

    char operat[80],s[80],s1[80];

    printf("Please input the numbers which you want to calculate:");

    scanf("%s",s);

    len=strlen(s);

    if(s[0]=='(')

    {

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r||count_l==0))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    i=0;

    for(;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y*=0.1;

    }

    number[j]=x+y;

    }

    j++;

    for(;i<len;)

    {

    if(s[i]=='*')

    {

    if(s[i+1]=='(')

    {

    i++;

    l=0;

    count_l=count_r=0;

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r||count_l==0))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    x=0;y=0;tem_y=1;

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y*=0.1;

    }

    number[j]=x+y;

    }

    number[j-1]=number[j-1]*number[j];

    }

    if(s[i]=='/')

    {

    if(s[i+1]=='(')

    {

    i++;

    l=0;

    count_l=count_r=0;

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r||count_l==0))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    x=0;y=0;tem_y=1;

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y*=0.1;

    }

    number[j]=x+y;

    }

    if(number[j]==0)

    {

    printf(" The operator is error! ");

    //system("pause");

    return 0;

    }

    number[j-1]=number[j-1]/number[j];

    }

    if(s[i]=='+'||s[i]=='-')

    {

    operat[k]=s[i];

    k++;

    if(s[i+1]=='(')

    {

    i++;

    l=0;

    count_l=count_r=0;

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r||count_l==0))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=++tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    x=0;y=0;tem_y=1;

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y*=0.1;

    }

    number[j]=x+y;

    j++;

    }

    }

    }

    for(i=0;i<j+k;i++)

    {

    if(operat[i] == '+')

    {

    number[0] += number[i+1];

    continue;

    }

    if(operat[i]=='-')

    {

    number[0] -= number[i+1];

    continue;

    }

    }

    printf(" %s = %.2f ",&s,number[0]);

    //system("pause");

    return 0 ;

    }

    float aux(char*s)

    {

    float number[80],x=0,y=0,tem_y=1;

    int len,i=0,j=0,k=0,l=0,count_r=0,count_l=0,tem_j,tem_k,tem_i;

    char operat[80],s1[80];

    len=strlen(s);

    if(s[0]=='(')

    {

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    i=0;

    for(;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y=0.1*tem_y;

    }

    number[j]=x+y;

    }

    j++;

    for(;i<len;)

    {

    if(s[i]=='*')

    {

    if(s[i+1]=='(')

    {

    i++;

    l=0;

    count_l=count_r=0;

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r||count_l==0))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    x=0;y=0;tem_y=1;

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y*=0.1;

    }

    number[j]=x+y;

    }

    number[j-1]=number[j-1]*number[j];

    }

    if(s[i]=='/')

    {

    if(s[i+1]=='(')

    {

    i++;

    l=0;

    count_l=count_r=0;

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r||count_l==0))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    x=0;y=0;tem_y=1;

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y*=0.1;

    }

    number[j]=x+y;

    }

    if(number[j]==0)

    {

    printf(" The operator is error! ");

    //system("pause");

    return 0;

    }

    number[j-1]=number[j-1]/number[j];

    }

    if(s[i]=='+'||s[i]=='-')

    {

    operat[k]=s[i];

    k++;

    if(s[i+1]=='(')

    {

    i++;

    l=0;

    count_l=count_r=0;

    while(1)

    {

    i++;

    if(s[i]=='(')

    count_l++;

    s1[l]=s[i];

    l++;

    if(s[i]==')')

    count_r++;

    if(s[i]==')'&&(count_l<count_r||count_l==0))

    break;

    }

    s1[l-1]='';

    tem_j=j;tem_k=k;tem_i=i;

    number[tem_j]=aux(s1);

    j=++tem_j;

    k=tem_k;

    i=++tem_i;

    }

    else

    {

    x=0;y=0;tem_y=1;

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    x=(s[i]-'0')+x*10;

    if(s[i]=='.')

    for(i++;s[i]<='9'&&s[i]>='0';i++)

    {

    y=(s[i]-'0')*0.1*tem_y+y;

    tem_y*=0.1;

    }

    number[j]=x+y;

    j++;

    }

    }

    }

    for(i=0;i<j+k;i++)

    {

    if(operat[i] == '+')

    {

    number[0] += number[i+1];

    continue;

    }

    if(operat[i]=='-')

    {

    number[0] -= number[i+1];

    continue;

    }

    }

    operat[0]=0;

    return number[0];

    }

    4,测试运行:

    5,效能分析

     考虑到用户输入会影响效能分析中的时间因素,去掉了主函数中接受用户输入并比较的部分,直接改成由代码随机生成算式然后计算结果。

    6,PSP表格:

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  • 原文地址:https://www.cnblogs.com/qiuhonghui/p/10614391.html
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