题目:
从上到下按层打印二叉树,同一层的节点按照从左到右的顺序打印,每一层打印到一行。
1 /* 2 struct TreeNode { 3 int val; 4 struct TreeNode *left; 5 struct TreeNode *right; 6 TreeNode(int x) : 7 val(x), left(NULL), right(NULL) { 8 } 9 };*/ 10 class Solution { 11 public: 12 vector<vector<int> > Print(TreeNode* root) { 13 vector<vector<int> > res; 14 vector<int> v; 15 if (root == NULL) 16 return res; 17 TreeNode* temp; 18 queue<TreeNode*> q; 19 q.push(root); 20 while(!q.empty()) { 21 v.clear(); 22 int len = q.size(); //队列中的元素个数即为当前行的所有元素 23 v.resize(len, 0); 24 for (int i = 0; i < len; i++) { 25 temp = q.front(); 26 q.pop(); 27 v[i] = temp->val; 28 if (temp->left != NULL) 29 q.push(temp->left); 30 if (temp->right != NULL) 31 q.push(temp->right); 32 } 33 res.push_back(v); 34 } 35 } 36 };