• Django 分页


    介绍

    Django为我们提供一个自带的分页功能,完成不复杂的分页完全小菜一碟。

    它被放在了:

    from django.core.paginator import Paginator

    语法

    class Paginator:
    
        def __init__(self, object_list, per_page, orphans=0,
                     allow_empty_first_page=True):
            self.object_list = object_list
            self._check_object_list_is_ordered()
            self.per_page = int(per_page)
            self.orphans = int(orphans)
            self.allow_empty_first_page = allow_empty_first_page
    • object_list    需要分页的对象,一般从数据库取。
    • per_page     每页显示多少条数据。
    • orphans       一般针对最后一页,少于多少条数据,将数据自动附加到前一页。
    • allow_empty_first_page    是否允许第一页为空。
    from django.core.paginator import Paginator
    
    objects
    = ['john','paul','george','ringo','lucy','meiry','checy','wind','flow','rain']
    p = Paginator(objects,3) # 3条数据为一页,实例化分页对象 print p.count # 10 对象总共10个元素 print p.num_pages # 4 对象可分4页 print p.page_range # range(1, 5) 对象页的可迭代范围 page1 = p.page(1) # 取对象的第一分页对象 print page1.object_list # 第一分页对象的元素列表 ['john', 'paul', 'george'] print page1.number # 第一分页对象的当前页值 1 page2 = p.page(2) # 取对象的第二分页对象 print page2.object_list # 第二分页对象的元素列表 ['ringo', 'lucy', 'meiry'] print page2.number # 第二分页对象的当前页码值 2 print page1.has_other_pages() # 除了第一分页对象是否有其它页 True print page2.has_previous() # 第二分页对象是否有前一页 True print page2.has_next() # 第二分页对象是否有下一页 True
    print page2.next_page_number() # 第二分页对象下一页码的值 3 print page2.previous_page_number() # 第二分页对象的上一页码值 1
    print page2.start_index() # 第二分页对象的元素开始索引 4 print page2.end_index() # 第2分页对象的元素结束索引 6

    官网实例

    views.py

    from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger
    from django.shortcuts import render
     
    def listing(request):
        contact_list = Contacts.objects.all()
        paginator = Paginator(contact_list, 25) # Show 25 contacts per page
     
        page = request.GET.get('page')
        try:
            contacts = paginator.page(page)
        except PageNotAnInteger:
            # If page is not an integer, deliver first page.
            contacts = paginator.page(1)
        except EmptyPage:
            # If page is out of range (e.g. 9999), deliver last page of results.
            contacts = paginator.page(paginator.num_pages)
     
        return render(request, 'list.html', {'contacts': contacts})

    HTML

    {% for contact in contacts %}
        {# Each "contact" is a Contact model object. #}
        {{ contact.full_name|upper }}<br />
        ...
    {% endfor %}
     
    <div class="pagination">
        <span class="step-links">
            {% if contacts.has_previous %}
                <a href="?page={{ contacts.previous_page_number }}">previous</a>
            {% endif %}
     
            <span class="current">
                Page {{ contacts.number }} of {{ contacts.paginator.num_pages }}.
            </span>
     
            {% if contacts.has_next %}
                <a href="?page={{ contacts.next_page_number }}">next</a>
            {% endif %}
        </span>
    </div>

    快速使用

    接下来,我们自己去模仿一下官网的实例,前端使用了bootstrap。

    views.py

    from django.shortcuts import render,redirect,HttpResponse
    from django.core.paginator import Paginator,PageNotAnInteger,EmptyPage
    
    def teacher(request,*args,**kwargs):
        if request.method == "GET":
            page = request.GET.get("page")
            content_list = models.Teacher.objects.all().values("grade","name","grade__caption") # 从数据取数据
            paginator = Paginator(content_list,3) # 实例化对象
            try:
                contents = paginator.page(page) # 根据URL(页数),获取相应的数据
            except PageNotAnInteger: 
                contents = paginator.page(1)
            except EmptyPage:
                contents = paginator.page(paginator.num_pages) # 页码不存在返回最后一页。
            return render(request,"teacher.html",{"contents":contents})

    teacher.html

                    <ul class="pagination">
                        {% if contents.has_previous %}
                            <li><a href="?page={{ contents.previous_page_number }}">&laquo;</a></li>
                        {% endif %}
    {% for content in contents.paginator.page_range %} {% if content == contents.number %}
    <li class="active" ><a href="?page={{ content }}">{{ content }}</a></li> {% else %} <li><a href="?page={{ content }}">{{ content }}</a></li> {% endif %} {% endfor %}
    {% if contents.has_next %} <li><a href="?page={{ contents.next_page_number }}">&raquo;</a></li> {% endif %} </ul>

     

    自定义

    我想让它显示5页页码,那该咋办?

    可以使用过滤器进行简单的判断。

    views.py

    from django.shortcuts import render,redirect,HttpResponse
    from django.core.paginator import Paginator,PageNotAnInteger,EmptyPage
    
    def teacher(request,*args,**kwargs):
        if request.method == "GET":
            page = request.GET.get("page")
            content_list = models.Teacher.objects.all().values("grade","name","grade__caption") # 从数据取数据
            paginator = Paginator(content_list,3) # 实例化对象
            try:
                contents = paginator.page(page) # 根据URL(页数),获取相应的数据
            except PageNotAnInteger: 
                contents = paginator.page(1)
            except EmptyPage:
                contents = paginator.page(paginator.num_pages) # 页码不存在返回最后一页。
            return render(request,"teacher.html",{"contents":contents})

    register.py

    from django import template
    from django.utils.html import format_html
    
    register = template.Library()
    
    @register.simple_tag
    def select_page(curr_page,loop_page,num_pages,display=3):
        offset = abs(curr_page - loop_page)
        if curr_page < display:
            display += display - curr_page
        elif curr_page + display - 1> num_pages:
            display += num_pages - curr_page
            if curr_page == num_pages:
                display += display - 1
        if offset < display:
            if curr_page == loop_page:
                ele = "<li class='active'><a href=?page=%s>%s</a></li>"%(loop_page,loop_page)
            else:
                ele = "<li><a href=?page=%s>%s</a></li>"%(loop_page,loop_page)
            return format_html(ele)
        else:
            return ""

    teacher.html

    {% load register %}
    
    <ul class="pagination">
                        {% if contents.has_previous %}
                            <li><a href="?page={{ contents.previous_page_number }}">&laquo;</a></li>
                        {% endif %}
                        {% for content in contents.paginator.page_range %}
                            {% select_page contents.number content contents.paginator.num_pages %}
                        {% endfor %}
                        {% if contents.has_next %}
                            <li><a href="?page={{ contents.next_page_number }}">&raquo;</a></li>
                        {% endif %}
                    </ul>

     

     

    过滤器,接受4个参数,其中一个有默认值。

    (当前页,循环页,总页,前后显示页面个数=3)

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  • 原文地址:https://www.cnblogs.com/py-peng/p/12689297.html
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