BFS.
Word Ladder Example Code
Below is the Vertex and Graph class used for the Word Ladder example code:
class Vertex: def __init__(self,key): self.id = key self.connectedTo = {} def addNeighbor(self,nbr,weight=0): self.connectedTo[nbr] = weight def __str__(self): return str(self.id) + ' connectedTo: ' + str([x.id for x in self.connectedTo]) def getConnections(self): return self.connectedTo.keys() def getId(self): return self.id def getWeight(self,nbr): return self.connectedTo[nbr]
class Graph: def __init__(self): self.vertList = {} self.numVertices = 0 def addVertex(self,key): self.numVertices = self.numVertices + 1 newVertex = Vertex(key) self.vertList[key] = newVertex return newVertex def getVertex(self,n): if n in self.vertList: return self.vertList[n] else: return None def __contains__(self,n): return n in self.vertList def addEdge(self,f,t,cost=0): if f not in self.vertList: nv = self.addVertex(f) if t not in self.vertList: nv = self.addVertex(t) self.vertList[f].addNeighbor(self.vertList[t], cost) def getVertices(self): return self.vertList.keys() def __iter__(self): return iter(self.vertList.values())
Code for buildGraph function:
def buildGraph(wordFile): d = {} g = Graph() wfile = open(wordFile,'r') # create buckets of words that differ by one letter for line in wfile: print line word = line[:-1] print word for i in range(len(word)): bucket = word[:i] + '_' + word[i+1:] if bucket in d: d[bucket].append(word) else: d[bucket] = [word] # add vertices and edges for words in the same bucket for bucket in d.keys(): for word1 in d[bucket]: for word2 in d[bucket]: if word1 != word2: g.addEdge(word1,word2) return g