Initially on a notepad only one character 'A' is present. You can perform two operations on this notepad for each step:
Copy All: You can copy all the characters present on the notepad (partial copy is not allowed).
Paste: You can paste the characters which are copied last time.
Given a number n. You have to get exactly n 'A' on the notepad by performing the minimum number of steps permitted. Output the minimum number of steps to get n 'A'.
Example 1:
Input: 3
Output: 3
Explanation:
Intitally, we have one character 'A'.
In step 1, we use Copy All operation.
In step 2, we use Paste operation to get 'AA'.
In step 3, we use Paste operation to get 'AAA'.
Note:
The n will be in the range [1, 1000].
思路:dp[i]表示复制i个‘A’需要的最少步数。dp[i] = i如果每次只复制一个'A'这是最大值,或者dp[i] = dp[j] + i/j.复制长度为j的'A'串,粘贴i/j-1次。
class Solution {
public:
int minSteps(int n) {
//vector<vector<int> > dp(n, vector<int>(2, INT_MAX));
vector<int> dp(n+1, 0);
dp[0] = 0;
dp[1] = 0;
dp[2] = 2;
for (int i = 2; i <= n; ++i) {
dp[i] = i;
for (int j = 2; j <= i; ++j) {
if (i % j == 0) {
dp[i] = min(dp[i], dp[j] + i/j);
}
}
}
return dp[n];
}
};