1023 - Discovering Permutations
Time Limit: 0.5 second(s) | Memory Limit: 32 MB |
In this problem you have to find the permutations using the first N English capital letters. Since there can be many permutations, you have to print the first K permutations.
Input
Input starts with an integer T (≤ 100), denoting the number of test cases.
Each case contains two integers N, K (1 ≤ N ≤ 26, 1 ≤ K ≤ 30).
Output
For each case, print the case number in a line. Then print the first K permutations that contain the first N English capital letters in alphabetical order. If there are less than K permutations then print all of them.
Sample Input |
Output for Sample Input |
2 3 8 10 10 |
Case 1: ABC ACB BAC BCA CAB CBA Case 2: ABCDEFGHIJ ABCDEFGHJI ABCDEFGIHJ ABCDEFGIJH ABCDEFGJHI ABCDEFGJIH ABCDEFHGIJ ABCDEFHGJI ABCDEFHIGJ ABCDEFHIJG |
水dfs
/* *********************************************** Author :guanjun Created Time :2016/6/28 14:50:20 File Name :1023.cpp ************************************************ */ #include <iostream> #include <cstring> #include <cstdlib> #include <stdio.h> #include <algorithm> #include <vector> #include <queue> #include <set> #include <map> #include <string> #include <math.h> #include <stdlib.h> #include <iomanip> #include <list> #include <deque> #include <stack> #define ull unsigned long long #define ll long long #define mod 90001 #define INF 0x3f3f3f3f #define maxn 10010 #define cle(a) memset(a,0,sizeof(a)) const ull inf = 1LL << 61; const double eps=1e-5; using namespace std; priority_queue<int,vector<int>,greater<int> >pq; struct Node{ int x,y; }; struct cmp{ bool operator()(Node a,Node b){ if(a.x==b.x) return a.y> b.y; return a.x>b.x; } }; bool cmp(int a,int b){ return a>b; } char s[30]; int n,k,num,mark; int vis[30]; void dfs(string s,int cnt){ if(cnt==n){ num++; cout<<s<<endl; if(num==k)mark=1; return ; } if(mark)return ; for(int i=0;i<n;i++){ if(!vis[i]){ vis[i]=1; dfs(s+char(i+'A'),cnt+1); vis[i]=0; } } } int main() { #ifndef ONLINE_JUDGE freopen("in.txt","r",stdin); #endif //freopen("out.txt","w",stdout); int T; cin>>T; for(int t=1;t<=T;t++){ printf("Case %d: ",t); cin>>n>>k; cle(vis); num=mark=0; dfs("",0); } return 0; }