• LRU Cache实现


     最近在看Leveldb源码,里面用到LRU(Least Recently Used)缓存,所以自己动手来实现一下。LRU Cache通常实现方式为Hash Map + Double Linked List,我使用std::map来代替哈希表。

    实现代码如下:

    #include <iostream>
    #include <map>
    #include <assert.h>
    
    using namespace std;
    
    // define double linked list node
    template<class K, class V>
    struct Node{
    	K key;
    	V value;
    	Node *pre_node;
    	Node *nxt_node;
    	Node() : key(K()), value(V()), pre_node(0), nxt_node(0){}
    };
    
    // define LRU cache.
    template<class K, class V>
    class LRUCache{
    public:
    	typedef Node<K, V> CacheNode;
    	typedef map<K, CacheNode*> HashTable;
    
    	LRUCache(const int size) : capacity(size), count(0), head(0), tail(0){
    		head = new CacheNode;
    		tail = new CacheNode;
    		head->nxt_node = tail;
    		tail->pre_node = head;
    	}
    	~LRUCache(){
    		HashTable::iterator itr = key_node_map.begin();
    		for (itr; itr != key_node_map.end(); ++itr)
    			delete itr->second;
    		delete head;
    		delete tail;
    	}
    
    	void put(const K &key, const V &value){
    		// check if key already exist.
    		HashTable::const_iterator itr = key_node_map.find(key);
    		if (itr == key_node_map.end()){
    			CacheNode *node = new CacheNode;
    			node->key = key;
    			node->value = value;		
    			if (count == capacity)
    			{
    				CacheNode *tail_node = tail->pre_node;
    				extricateTheNode(tail_node);
    				key_node_map.erase(tail_node->key);
    				delete tail_node;
    				count--;
    			}
    
    			key_node_map[key] = node;
    			count++;
    			moveToHead(node);
    		}
    		else{
    			itr->second->value = value;
    			extricateTheNode(itr->second);
    			moveToHead(itr->second);
    		}
    	}
    
    	V get(const K &key){
    		// check if key already exist.
    		HashTable::const_iterator itr = key_node_map.find(key);
    		if (itr == key_node_map.end()){
    			return V();
    		}
    		else{
    			extricateTheNode(itr->second);
    			moveToHead(itr->second);
    			return itr->second->value;
    		}
    	}
    
    	void print(){
    		if (count == 0)
    			cout << "Empty cache." << endl;
    
    		cout << "Cache information:" << endl;
    		cout << "  " << "capacity: " << capacity << endl;
    		cout << "  " << "count: " << count << endl;
    		cout << "  " << "map size: " << key_node_map.size() << endl;
    		cout << "  " << "keys: ";
    		CacheNode *node = head;
    		while (node->nxt_node != tail)
    		{
    			cout << node->nxt_node->key << ",";
    			node = node->nxt_node;
    		}
    		cout << endl;
    	}
    
    private:
    	void moveToHead(CacheNode *node){
    		assert(head);
    		node->pre_node = head;
    		node->nxt_node = head->nxt_node;
    		head->nxt_node->pre_node = node;
    		head->nxt_node = node;
    	}
    	void extricateTheNode(CacheNode *node){ // evict the node from the list.
    		assert(node != head && node != tail);
    		node->pre_node->nxt_node = node->nxt_node;
    		node->nxt_node->pre_node = node->pre_node;
    	}
    
    private:
    	int capacity;
    	int count;
    	Node<K, V> *head;
    	Node<K, V> *tail;
    	HashTable key_node_map;
    };
    
    int main()
    {
    	LRUCache<int, int> my_cache(4);
    	
    	for (int i = 0; i < 20; ++i)
    	{
    		int key = rand() % 10 + 1;
    		int value = key * 2;
    		cout << "Put[" << key << "," << value << "]>>>" << endl;
    		my_cache.put(key, value);
    		my_cache.print();
    	}
    	
    	for (int i = 0; i < 20; ++i)
    	{
    		int key = rand() % 10 + 1;
    		int value = my_cache.get(key);
    		cout << "Get value of " << key << ": " << value << ".>>>" << endl;
    		my_cache.print();
    	}
    
    	return 0;
    }
    
  • 相关阅读:
    .net core 2.0以上版本加载appsettings.json
    BZOJ 2564: 集合的面积
    P3829 [SHOI2012]信用卡凸包
    P2215 [HAOI2007]上升序列
    P2511 [HAOI2008]木棍分割
    P2510 [HAOI2008]下落的圆盘
    P4053 [JSOI2007]建筑抢修
    P4050 [JSOI2007]麻将
    P4049 [JSOI2007]合金
    P4161 [SCOI2009]游戏
  • 原文地址:https://www.cnblogs.com/pbendan/p/5573645.html
Copyright © 2020-2023  润新知