• LeetCode


    题目:

    Given a sorted linked list, delete all duplicates such that each element appear only once.

    For example,
    Given 1->1->2, return 1->2.
    Given 1->1->2->3->3, return 1->2->3.

    思路:

    package list;
    
    public class RemoveDuplicatesFromSortedList {
    
        public ListNode deleteDuplicates(ListNode head) {
            ListNode p = head;
            ListNode start = head;
            while (head != null && head.next != null) {
                ListNode headNext = head.next;
                if (head.next.val != head.val) {
                    start = head.next;
                } else {
                    start.next = head.next.next;
                }
                
                head = headNext;
            }
            return p;
        }
        
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            ListNode a1 = new ListNode(1);
            ListNode a2 = new ListNode(1);
            ListNode a3 = new ListNode(1);
            ListNode a4 = new ListNode(1);
            ListNode a5 = new ListNode(1);
            a1.next = a2;
            a2.next = a3;
            a3.next = a4;
            a4.next = a5;
            a5.next = null;
            RemoveDuplicatesFromSortedList r = new RemoveDuplicatesFromSortedList();
            ListNode head = r.deleteDuplicates(a1);
            while (head != null) {
                System.out.println(head.val);
                head = head.next;
            }
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/null00/p/5096137.html
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