• 英文姓名排序小程序


    为了练习Comparable接口,实现其compareTo方法,从而为英文姓名进行排序

    这里一个姓名类,有成员变量firstName和lastName,都是String类型。这个姓名类需要实现Comparable接口,从而实现排序。

    附代码:

    package compare;
    //英文姓名排序、通过实现Comparable接口实现compareTo方法来对饮用对象排序
    import java.util.*;
    
    public class TestSort {
        public static void main(String[] args) {
            List<Name> list = new ArrayList<Name>();
            list.add(new Name("j","J"));
            list.add(new Name("d","D"));
            list.add(new Name("b","B"));
            list.add(new Name("c","A"));
            list.add(new Name("a","A"));
            list.add(new Name("i","I"));
            list.add(new Name("f","F"));
            list.add(new Name("g","G"));
            list.add(new Name("h","G"));
            System.out.print(list);
            Collections.sort(list);
            System.out.println();
            System.out.print(list);
        }
    }
    
    class Name implements Comparable<Name> {
        private String firstName;
        private String lastName;
    
        Name(String firstName, String lastName) {
            this.firstName = firstName;
            this.lastName = lastName;
        }
    
        public void setFirstName(String firstName) {
            this.firstName = firstName;
        }
    
        public void setLastName(String lastName) {
            this.lastName = lastName;
        }
    
        public String getFirstName() {
            return this.firstName;
        }
    
        public String getLastName() {
            return this.lastName;
        }
    
        public String toString() {
            StringBuffer sb = new StringBuffer();
            sb.append("[").append(this.lastName).append(" ").append(this.firstName).append("]");
            return sb.toString();
        }
    
        public int compareTo(Name n) {
    //        如果lastName不一样,比较当前对象和传进来对象的lastName的各个字母
    //        如果lastName一样,那么比较firstName
    //        如果lastName和firstName都 一样,表示名字一样,返回0
            if(lastName.compareTo(n.lastName) > 0) {
                return 1;
            } else if(lastName.compareTo(n.lastName) < 0) {
                return -1;
            }else {
                return firstName.compareTo(n.firstName);
            }
        }
    }

    运行结果图:

    注:第一行是未排序前,第二行是排序后。

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  • 原文地址:https://www.cnblogs.com/nora-xie/p/3344336.html
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