• 解决Android 5.0中出现的警告:Service Intent must be explicit


    extends:http://www.eoeandroid.com/thread-568853-1-1.html

    本帖最后由 469874851 于 2015-3-11 18:15 编辑

    有些时候我们使用Service的时需要采用隐私启动的方式,但是Android 5.0一出来后,其中有个特性就是Service Intent  must be explitict,也就是说从Lollipop开始,service服务必须采用显示方式启动。
    而android源码是这样写的(源码位置:sdk/sources/android-21/android/app/ContextImpl.java):
    private void validateServiceIntent(Intent service) {
            if (service.getComponent() == null && service.getPackage() == null) {
                if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {
                    IllegalArgumentException ex = new IllegalArgumentException(
                            "Service Intent must be explicit: " + service);
                    throw ex;
                } else {
                    Log.w(TAG, "Implicit intents with startService are not safe: " + service
                            + " " + Debug.getCallers(2, 3));
                }
            }
        }

    既然,源码里是这样写的,那么这里有两种解决方法:

    1、设置Action和packageName:

    参考代码如下:
    Intent mIntent = new Intent();
    mIntent.setAction("XXX.XXX.XXX");//你定义的service的action
    mIntent.setPackage(getPackageName());//这里你需要设置你应用的包名
    context.startService(mIntent);


    此方式是google官方推荐使用的解决方法。


    在此附上地址供大家参考:http://developer.android.com/goo ... tml#billing-service,有兴趣的可以去看看。

    2、将隐式启动转换为显示启动--参考地址:http://stackoverflow.com/a/26318757/1446466
    public static Intent getExplicitIntent(Context context, Intent implicitIntent) {
            // Retrieve all services that can match the given intent
            PackageManager pm = context.getPackageManager();
            List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);
            // Make sure only one match was found
            if (resolveInfo == null || resolveInfo.size() != 1) {
                return null;
            }
            // Get component info and create ComponentName
            ResolveInfo serviceInfo = resolveInfo.get(0);
            String packageName = serviceInfo.serviceInfo.packageName;
            String className = serviceInfo.serviceInfo.name;
            ComponentName component = new ComponentName(packageName, className);
            // Create a new intent. Use the old one for extras and such reuse
            Intent explicitIntent = new Intent(implicitIntent);
            // Set the component to be explicit
            explicitIntent.setComponent(component);
            return explicitIntent;
        } 

    调用方式如下:
    Intent mIntent = new Intent();
    mIntent.setAction("XXX.XXX.XXX");
    Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));
    context.startService(eintent);

     
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  • 原文地址:https://www.cnblogs.com/niray/p/4453258.html
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