Public Sub SmartIndenterProcedure() Dim OneComp As VBComponent Dim StartLine As Long, EndLine As Long Dim LineIndex As Long, LineNo As Long, LineCount Dim StartCol As Long, EndCol As Long Dim LineText As String Dim ProcName As String, KeyWord As String Dim IndentLevel As Integer, IsAfterUnderLine As Boolean Dim IndentThisLine As Boolean, BackThisLine As Boolean Dim IndentNextLine As Boolean, BackNextLine As Boolean For Each OneComp In ActiveWorkbook.VBProject.VBComponents LineCount = OneComp.CodeModule.CountOfLines For LineNo = 1 To LineCount ProcName = OneComp.CodeModule.ProcOfLine(LineNo, vbext_pk_Proc) ProcLineCount = OneComp.CodeModule.ProcCountLines(ProcName, vbext_pk_Proc) LineNo = LineNo + ProcLineCount - 1 StartLine = OneComp.CodeModule.ProcStartLine(ProcName, vbext_pk_Proc) EndLine = OneComp.CodeModule.ProcCountLines(ProcName, vbext_pk_Proc) + StartLine '循环每一行,删除行首缩进 For LineIndex = StartLine To EndLine LineText = OneComp.CodeModule.Lines(LineIndex, 1) Do Until Left(LineText, 1) <> " " OneComp.CodeModule.ReplaceLine LineIndex, Mid(LineText, 2) LineText = OneComp.CodeModule.Lines(LineIndex, 1) Loop Next LineIndex IndentLevel = 0 For LineIndex = StartLine To EndLine LineText = OneComp.CodeModule.Lines(LineIndex, 1) KeyWord = Left(LineText, IIf(InStr(LineText, " ") = 0, Len(LineText), InStr(LineText, " ") - 1)) Select Case KeyWord Case "Do", "For", "Private", "Select", "Sub", "While", "With", "Function", "Type" IndentNextLine = True Case "If" If Right(LineText, 4) = "Then" Then IndentNextLine = True Case "Loop", "Next", "End" BackThisLine = True Case "Case", "Else", "ElseIf" BackThisLine = True IndentNextLine = True Case "Public", "Private" If Split(LineText, " ")(1) = "Sub" Or Split(LineText, " ")(1) = "Function" Then IndentNextLine = True End If End Select '判断续行问题 If Right(LineText, 2) = " _" And IsAfterUnderLine = False Then IndentNextLine = True IsAfterUnderLine = True ElseIf Right(LineText, 2) <> " _" And IsAfterUnderLine Then BackNextLine = True IsAfterUnderLine = False End If '处理本行的缩进级别 If IndentThisLine Then IndentLevel = IndentLevel + 1 IndentThisLine = False End If If BackThisLine Then IndentLevel = IndentLevel - 1 BackThisLine = False End If On Error GoTo ErrHandler OneComp.CodeModule.ReplaceLine LineIndex, Space$(IndentLevel * 4) & LineText On Error GoTo 0 If IndentNextLine Then IndentLevel = IndentLevel + 1 IndentNextLine = False End If If BackNextLine Then IndentLevel = IndentLevel - 1 BackNextLine = False End If Next LineIndex Next LineNo Next OneComp Set OneComp = Nothing Exit Sub ErrHandler: If IndentLevel < 0 Then IndentLevel = 0 Resume Next End Sub