题意:有一个由小写字母组成的字符串,A和B两个人轮流操作,A想让序列的字典序最大,B想最小
两人都能任意选择一位上的字母将其右移一位(a->b,b->c……z->a)或者直接结束游戏
A先手操作,问最后的序列
n<=1e2
思路:
1 #include<bits/stdc++.h> 2 using namespace std; 3 typedef long long ll; 4 typedef unsigned int uint; 5 typedef unsigned long long ull; 6 typedef pair<int,int> PII; 7 typedef pair<ll,ll> Pll; 8 typedef vector<int> VI; 9 typedef vector<PII> VII; 10 #define N 310000 11 #define M 4100000 12 #define fi first 13 #define se second 14 #define MP make_pair 15 #define pi acos(-1) 16 #define mem(a,b) memset(a,b,sizeof(a)) 17 #define rep(i,a,b) for(int i=(int)a;i<=(int)b;i++) 18 #define per(i,a,b) for(int i=(int)a;i>=(int)b;i--) 19 #define lowbit(x) x&(-x) 20 #define Rand (rand()*(1<<16)+rand()) 21 #define id(x) ((x)<=B?(x):m-n/(x)+1) 22 #define ls p<<1 23 #define rs p<<1|1 24 25 const ll MOD=1e9+7,inv2=(MOD+1)/2; 26 double eps=1e-6; 27 int INF=1e9; 28 int da[4]={-1,1,0,0}; 29 int db[4]={0,0,-1,1}; 30 31 char ch[N]; 32 33 int read() 34 { 35 int v=0,f=1; 36 char c=getchar(); 37 while(c<48||57<c) {if(c=='-') f=-1; c=getchar();} 38 while(48<=c&&c<=57) v=(v<<3)+v+v+c-48,c=getchar(); 39 return v*f; 40 } 41 42 43 int main() 44 { 45 //freopen("1.in","r",stdin); 46 //freopen("1.out","w",stdout); 47 48 int cas; 49 scanf("%d",&cas); 50 51 while(cas--) 52 { 53 scanf("%s",ch+1); 54 int n=strlen(ch+1); 55 rep(i,1,n) 56 { 57 if(ch[i]=='y') continue; 58 if(ch[i]=='z') ch[i]='b'; 59 break; 60 } 61 rep(i,1,n) printf("%c",ch[i]); 62 printf(" "); 63 } 64 65 return 0; 66 }