作业题目
Below are four faulty programs. Each includes a test case that results in failure.
Answer the following questions (in the next slide) about each program.
public int findLast (int[] x, int y) {
//Effects: If x==null throw
NullPointerException
// else return the index of the last element
// in x that equals y.
// If no such element exists, return -1
for (int i=x.length-1; i > 0; i--)
{
if (x[i] == y)
{
return i;
}
}
return -1;
}
// test: x=[2, 3, 5]; y = 2
// Expected = 0
public static int lastZero (int[] x) {
//Effects: if x==null throw
NullPointerException
// else return the index of the LAST 0 in x.
// Return -1 if 0 does not occur in x
for (int i = 0; i < x.length; i++)
{
if (x[i] == 0)
{
return i;
}
} return -1;
}
// test: x=[0, 1, 0]
// Expected = 2
问题
Identify the fault.
If possible, identify a test case that does not execute the
fault. (Reachability)
If possible, identify a test case that executes the fault, but
does not result in an error state.
If possible identify a test case that results in an error, but
not a failure.
作业解答：
1.第一个程序的For循环应该i大于等于0，
第二个程序应改为for (int i=x.length-1; i >= 0; i--) ；
2.第一个程序 x = [], y = 2，
第二个程序 无论怎么输入 都会execute the fault；
3.第一个程序 x = [2,3,4]，y = 4，
第二个程序 test: x = [3]；
4 第一个程序 test: x = [2]，
第二个程序 test: x = [1,0,3]。