我认为这题更像一道数学题，找规律的，1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 24, 25, 27, ... 就是要找到这些数之间的规律，a[i]=max(a[s1]*2,max(a[s2]*3,max(a[s3]*5,a[s4]*7)));就是输出格式有点麻烦。
代码：
1 #include<stdio.h>
2 #include<stdlib.h>
3 #include<string.h>
4 #include<iostream>
5 using namespace std;
6 int min(int x,int y)
7 {
8 return x>y?y:x;
9 }
10 int main()
11 {
12 int n,s1,s2,s3,s4;
13 int a[5900];
14 a[1]=1;
15 s1=s2=s3=s4=1;
16 for(int i=2;i<=5842;i++)
17 {
18 a[i]=min(a[s1]*2,min(a[s2]*3,min(a[s3]*5,a[s4]*7)));
19 if(a[i]==a[s1]*2)
20 s1++;
21 if(a[i]==a[s2]*3)
22 s2++;
23 if(a[i]==a[s3]*5)
24 s3++;
25 if(a[i]==a[s4]*7)
26 s4++;
27 }
28 while(scanf("%d",&n),n)
29 {
30 if(n%10==1&&(n%100)!=11)
31 printf("The %dst humble number is %d.\n",n,a[n]);
32 else if(n%10==2&&(n%100)!=12)
33 printf("The %dnd humble number is %d.\n",n,a[n]);
34 else if(n%10==3&&(n%100)!=13)
35 printf("The %drd humble number is %d.\n",n,a[n]);
36 else
37 printf("The %dth humble number is %d.\n",n,a[n]);
38 }
39 return 0;
40 }