面试题:
两个线程,一个线程打印1-52,另一个打印字母A-Z打印顺序为12A34B...5152Z,
要求用线程间通信
线程间通信:1、生产者+消费者2、通知等待唤醒机制
多线程编程模版中
1、判断
2、干活
3、唤醒
synchronized实现
package com.atguigu.thread; import java.util.concurrent.locks.Condition; import java.util.concurrent.locks.Lock; import java.util.concurrent.locks.ReentrantLock; import org.omg.IOP.Codec; class ShareDataOne//资源类 { private int number = 0;//初始值为零的一个变量 public synchronized void increment() throws InterruptedException { //1判断 if(number !=0 ) { this.wait(); } //2干活 ++number; System.out.println(Thread.currentThread().getName()+" "+number); //3通知 this.notifyAll(); } public synchronized void decrement() throws InterruptedException { // 1判断 if (number == 0) { this.wait(); } // 2干活 --number; System.out.println(Thread.currentThread().getName() + " " + number); // 3通知 this.notifyAll(); } } /** * * @Description: *现在两个线程, * 可以操作初始值为零的一个变量, * 实现一个线程对该变量加1,一个线程对该变量减1, * 交替,来10轮。 * @author xialei * * * 笔记:Java里面如何进行工程级别的多线程编写 * 1 多线程变成模板(套路)-----上 * 1.1 线程 操作 资源类 * 1.2 高内聚 低耦合 * 2 多线程变成模板(套路)-----下 * 2.1 判断 * 2.2 干活 * 2.3 通知 */ public class NotifyWaitDemoOne { public static void main(String[] args) { ShareDataOne sd = new ShareDataOne(); new Thread(() -> { for (int i = 1; i < 10; i++) { try { sd.increment(); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }, "A").start(); new Thread(() -> { for (int i = 1; i < 10; i++) { try { sd.decrement(); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }, "B").start(); } } /* * * * 2 多线程变成模板(套路)-----下 * 2.1 判断 * 2.2 干活 * 2.3 通知 * 3 防止虚假唤醒用while * * * */
换成4个线程会导致错误,虚假唤醒
原因:在java多线程判断时,不能用if,程序出事出在了判断上面,
突然有一添加的线程进到if了,突然中断了交出控制权,
没有进行验证,而是直接走下去了,加了两次,甚至多次
解决虚假唤醒:查看API,java.lang.Object
中断和虚假唤醒是可能产生的,所以要用loop循环,if只判断一次,while是只要唤醒就要拉回来再判断一次。if换成while
java8实现
Condition:查看API,java.util.concurrent  class BoundedBuffer { final Lock lock = new ReentrantLock(); final Condition notFull = lock.newCondition(); final Condition notEmpty = lock.newCondition(); final Object[] items = new Object[100]; int putptr, takeptr, count; public void put(Object x) throws InterruptedException { lock.lock(); try { while (count == items.length) notFull.await(); items[putptr] = x; if (++putptr == items.length) putptr = 0; ++count; notEmpty.signal(); } finally { lock.unlock(); } }
线程间定制化调用通信
package com.atguigu.thread; import java.util.concurrent.locks.Condition; import java.util.concurrent.locks.Lock; import java.util.concurrent.locks.ReentrantLock; class ShareResource { private int number = 1;//1:A 2:B 3:C private Lock lock = new ReentrantLock(); private Condition c1 = lock.newCondition(); private Condition c2 = lock.newCondition(); private Condition c3 = lock.newCondition(); public void print5(int totalLoopNumber) { lock.lock(); try { //1 判断 while(number != 1) { //A 就要停止 c1.await(); } //2 干活 for (int i = 1; i <=5; i++) { System.out.println(Thread.currentThread().getName()+" "+i+" totalLoopNumber: "+totalLoopNumber); } //3 通知 number = 2; c2.signal(); } catch (Exception e) { e.printStackTrace(); } finally { lock.unlock(); } } public void print10(int totalLoopNumber) { lock.lock(); try { //1 判断 while(number != 2) { //A 就要停止 c2.await(); } //2 干活 for (int i = 1; i <=10; i++) { System.out.println(Thread.currentThread().getName()+" "+i+" totalLoopNumber: "+totalLoopNumber); } //3 通知 number = 3; c3.signal(); } catch (Exception e) { e.printStackTrace(); } finally { lock.unlock(); } } public void print15(int totalLoopNumber) { lock.lock(); try { //1 判断 while(number != 3) { //A 就要停止 c3.await(); } //2 干活 for (int i = 1; i <=15; i++) { System.out.println(Thread.currentThread().getName()+" "+i+" totalLoopNumber: "+totalLoopNumber); } //3 通知 number = 1; c1.signal(); } catch (Exception e) { e.printStackTrace(); } finally { lock.unlock(); } } } /** * * @Description: * 多线程之间按顺序调用,实现A->B->C * 三个线程启动,要求如下: * * AA打印5次,BB打印10次,CC打印15次 * 接着 * AA打印5次,BB打印10次,CC打印15次 * ......来10轮 * @author xialei * */ public class ThreadOrderAccess { public static void main(String[] args) { ShareResource sr = new ShareResource(); new Thread(() -> { for (int i = 1; i <=10; i++) { sr.print5(i); } }, "AA").start(); new Thread(() -> { for (int i = 1; i <=10; i++) { sr.print10(i); } }, "BB").start(); new Thread(() -> { for (int i = 1; i <=10; i++) { sr.print15(i); } }, "CC").start(); } }