题意:中文题
思路:其实就是在n个格子上放m个棋子(n>=m)(xjb套Lucas的板子...
AC代码:
#include "iostream" #include "string.h" #include "stack" #include "queue" #include "string" #include "vector" #include "set" #include "map" #include "algorithm" #include "stdio.h" #include "math.h" #pragma comment(linker, "/STACK:102400000,102400000") #define ll long long #define endl (" ") #define bug(x) cout<<x<<" "<<"UUUUU"<<endl; #define mem(a,x) memset(a,x,sizeof(a)) #define mp(x,y) make_pair(x,y) #define pb(x) push_back(x) #define ft first #define sd second #define lrt (rt<<1) #define rrt (rt<<1|1) using namespace std; const long long INF = 1e18+1LL; const int inf = 1e9+1e8; const int N=1e5+100; const ll mod=1e9+7; ll exp_mod(ll a, ll b, ll p){ ll res = 1; while(b != 0){ if(b&1) res = (res * a) % p; a = (a*a) % p; b >>= 1; } return res; } ll Comb(ll a, ll b, ll p){ if(a < b) return 0; if(a == b) return 1; if(b > a - b) b = a - b; ll ans = 1, ca = 1, cb = 1; for(ll i = 0; i < b; ++i){ ca = (ca * (a - i))%p; cb = (cb * (b - i))%p; } ans = (ca*exp_mod(cb, p - 2, p)) % p; return ans; } ll C(int n, int m, int p){ ll ans = 1; while(n&&m&&ans){ ans = (ans*Comb(n%p, m%p, p)) % p; n /= p; m /= p; } return ans; } int n,m; int main(){ ios::sync_with_stdio(0),cin.tie(0),cout.tie(0); int T; cin>>T; while(T--){ cin>>n>>m; if(n<m ) swap(n,m); cout<<C(n,m,mod)<<endl; } return 0; }