• LeetCode: 455 Assign Cookies(easy)


    题目:

    Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.

    Note:
    You may assume the greed factor is always positive. 
    You cannot assign more than one cookie to one child.

    Example 1:

    Input: [1,2,3], [1,1]
    
    Output: 1
    
    Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. 
    And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
    You need to output 1.

    Example 2:

    Input: [1,2], [1,2,3]
    
    Output: 2
    
    Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. 
    You have 3 cookies and their sizes are big enough to gratify all of the children, 
    You need to output 2.

    代码:

     1 class Solution {
     2 public:
     3     int findContentChildren(vector<int>& g, vector<int>& s) {
     4         int result = 0;
     5         while ((!g.empty())&&(!s.empty())){
     6             auto gmax = max_element(g.begin(), g.end());
     7             auto smax = max_element(s.begin(), s.end());
     8             if (*gmax <= *smax){
     9                 result++;
    10                 g.erase(gmax);
    11                 s.erase(smax);
    12             }
    13             else
    14                 g.erase(gmax);
    15         }
    16         return result;
    17     }
    18 };

    改良版:

     1 class Solution {
     2 public:
     3     int findContentChildren(vector<int>& g, vector<int>& s) {
     4         int result = 0;
     5         sort(g.begin(), g.end(), greater<int>());
     6         sort(s.begin(), s.end(), greater<int>());
     7         vector<int>::iterator gtem = g.begin();
     8         vector<int>::iterator stem = s.begin();
     9         
    10         while (gtem != g.end() && stem != s.end()){
    11             if (*gtem > *stem)
    12                 gtem++;
    13             else{
    14                 result++;
    15                 gtem++;
    16                 stem++;
    17             }
    18         }
    19         return result;
    20     }
    21 };
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  • 原文地址:https://www.cnblogs.com/llxblogs/p/7507353.html
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