• 查询几所学校特定时间的相关数据


    今天自己写的一条SQL语句,用到了表连接和临时表,语法供自己以后参考。

    SELECT
        us.school_name 学校名称,
        CONCAT(
            ug.grade_name,
            uc.classes_name
        ) 年级班级,
        uu.user_id 用户ID,
        uu.user_real_name 学生姓名,
        ta.assignment_id 作业序号,
        ta.assignment_write_time 作文写作耗时(以秒记),
        ta.assignment_word_count 字数,
        ta.assignment_submit_count 作文提交次数,
        ta.assignment_start_date 布置作业开始时间,
        ta.assignment_end_date 作业截止时间,
        ta.assignment_submit_date 作业提交教师时间,
        ta.assignment_mark1 作业评分的第一项(内容),
        ta.assignment_mark2 作业评分的第二项(语言),
        ta.assignment_mark3 作业评分的第三项(文采或结构),
        ta.assignment_mark_sum 三项评分的总分,
        teacher_list.user_real_name 教师姓名
    FROM
        t_assignment ta
    LEFT JOIN u_user uu ON ta.user_id = uu.user_id
    LEFT JOIN u_classes_user ucu ON uu.user_id = ucu.user_id
    LEFT JOIN u_classes uc ON ucu.classes_id = uc.classes_id
    LEFT JOIN u_school_grade usg ON uc.school_grade_id = usg.school_grade_id
    LEFT JOIN u_grade ug ON usg.grade_id = ug.grade_id
    LEFT JOIN u_school us ON usg.school_id = us.school_id
    LEFT JOIN u_user_role uur ON uu.user_id = uur.user_id
    LEFT JOIN u_role ur ON uur.role_id = ur.role_id
    LEFT JOIN (
        SELECT
            ucu.classes_id,
            uu.user_real_name
        FROM
            u_user uu
        LEFT JOIN u_user_role uur ON uu.user_id = uur.user_id
        LEFT JOIN u_role ur ON uur.role_id = ur.role_id
        LEFT JOIN u_classes_user ucu ON uu.user_id = ucu.user_id
        WHERE
            uur.role_id = '42'
    ) teacher_list ON teacher_list.classes_id = ucu.classes_id
    WHERE
        ta.assignment_start_date > '2014-09-01 00:00:00'
    AND ta.assignment_start_date < '2015-01-31'
    AND uur.role_id = '38'
    AND us.school_id IN ('7', '8', '5', '2');
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  • 原文地址:https://www.cnblogs.com/liweiwei1419/p/4323361.html
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