一只青蛙一次可以跳上1级台阶,也可以跳上2级。求该青蛙跳上一个n级的台阶总共有多少种跳法(先后次序不同算不同的结果)。
==============Python==============
# -*- coding:utf-8 -*- class Solution: def jumpFloor(self, number): # write code here if number == 1: return 1 if number == 2: return 2 dp1 = 1 dp2 = 2 for i in range(2, number+1): dp1, dp2 = dp2, dp1 + dp2 return dp1
==============Java===============
public class Solution { public int JumpFloor(int target) { if (target == 1) { return 1; } if (target == 2) { return 2; } return JumpFloor(target - 1) + JumpFloor(target - 2); } }