requests

1、获取URL对应的资源

get、head

2、实例

try:
    url = 'https://www.baidu.com/s?'
    kv = {'wd': 'python'}
    hd = {'user-agent': 'Chrome/10'}
    r = requests.get(url, params=kv, headers=hd, timeout=10)
    r.raise_for_status()
    # 用r.request查看请求信息
    print(r.request.url)
    print(r.url)
    print(r.request.headers)
    print(r.headers)
    print(r.encoding)
    print(r.apparent_encoding)
    r.encoding = r.apparent_encoding
    print(r.text[:1000])

    url = 'https://www.baidu.com'
    r = requests.head(url)
    print(r.headers)
    print(r.text)

except:
    print('请求错误')