• BZOJ 1055 玩具取名(区间DP)


    很显然的区间DP,定义dp[i][j][k], 如果dp[i][j][k]=1表示字符串[i,j]可以组成k字符。

    # include <cstdio>
    # include <cstring>
    # include <cstdlib>
    # include <iostream>
    # include <vector>
    # include <queue>
    # include <stack>
    # include <map>
    # include <set>
    # include <cmath>
    # include <algorithm>
    using namespace std;
    # define lowbit(x) ((x)&(-x))
    # define pi acos(-1.0)
    # define eps 1e-9
    # define MOD 12345678
    # define INF 1000000000
    # define mem(a,b) memset(a,b,sizeof(a))
    # define FOR(i,a,n) for(int i=a; i<=n; ++i)
    # define FO(i,a,n) for(int i=a; i<n; ++i)
    # define bug puts("H");
    # define lch p<<1,l,mid
    # define rch p<<1|1,mid+1,r
    # define mp make_pair
    # define pb push_back
    typedef pair<int,int> PII;
    typedef vector<int> VI;
    # pragma comment(linker, "/STACK:1024000000,1024000000")
    typedef long long LL;
    int Scan() {
        int res=0, flag=0;
        char ch;
        if((ch=getchar())=='-') flag=1;
        else if(ch>='0'&&ch<='9') res=ch-'0';
        while((ch=getchar())>='0'&&ch<='9')  res=res*10+(ch-'0');
        return flag?-res:res;
    }
    void Out(int a) {
        if(a<0) {putchar('-'); a=-a;}
        if(a>=10) Out(a/10);
        putchar(a%10+'0');
    }
    const int N=1005;
    //Code begin...
    
    struct To{int a[18][2];}to[5];
    int dp[205][205][5], p[30], len, a[5];
    char wing[205];
    
    void init(){p['W'-'A']=1; p['I'-'A']=2; p['N'-'A']=3; p['G'-'A']=4; mem(dp,-1);}
    void dfs(int l, int r)
    {
        if (~dp[l][r][0]) return ;
        if (l==r) {dp[l][r][0]=1; dp[l][r][p[wing[l]-'A']]=1; return ;}
        FO(i,l,r) {
            dfs(l,i); dfs(i+1,r);
            FOR(j,1,4) FOR(k,1,a[j]) {
                int tmp1=to[j].a[k][0], tmp2=to[j].a[k][1];
                if (dp[l][i][tmp1]==1&&dp[i+1][r][tmp2]==1) {dp[l][r][j]=1; break;}
            }
        }
        dp[l][r][0]=1;
        return ;
    }
    int main ()
    {
        char s[5];
        init();
        scanf("%d%d%d%d",a+1,a+2,a+3,a+4);
        FOR(i,1,a[1]) scanf("%s",s), to[1].a[i][0]=p[s[0]-'A'], to[1].a[i][1]=p[s[1]-'A'];
        FOR(i,1,a[2]) scanf("%s",s), to[2].a[i][0]=p[s[0]-'A'], to[2].a[i][1]=p[s[1]-'A'];
        FOR(i,1,a[3]) scanf("%s",s), to[3].a[i][0]=p[s[0]-'A'], to[3].a[i][1]=p[s[1]-'A'];
        FOR(i,1,a[4]) scanf("%s",s), to[4].a[i][0]=p[s[0]-'A'], to[4].a[i][1]=p[s[1]-'A'];
        scanf("%s",wing+1);
        len=strlen(wing+1);
        dfs(1,len);
        int flag=0;
        if (dp[1][len][1]==1) flag=1, putchar('W');
        if (dp[1][len][2]==1) flag=1, putchar('I');
        if (dp[1][len][3]==1) flag=1, putchar('N');
        if (dp[1][len][4]==1) flag=1, putchar('G');
        if (!flag) {puts("The name is wrong!"); return 0;}
        putchar('
    ');
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/lishiyao/p/6501864.html
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