package LeetCode_333 import main.TreeNode /** * 333. Largest BST Subtree * Given a binary tree, find the largest subtree which is a Binary Search Tree (BST), where largest means subtree with largest number of nodes in it. Note: A subtree must include all of its descendants. Example: Input: [10,5,15,1,8,null,7] 10 / 5 15 / 1 8 7 Output: 3 Explanation: The Largest BST Subtree in this case is the highlighted one (5,1,8). The return value is the subtree's size, which is 3. Follow up: Can you figure out ways to solve it with O(n) time complexity? * */ class Solution { /* * solution: recursion, Time complexity:O(n*n), Space complexity:O(n) * */ fun largestSubTree(root: TreeNode?): Int { if (root == null) { return 0 } if (isBST(root, null, null)) { return count(root) } return Math.max(largestSubTree(root.left), largestSubTree(root.right)) } private fun isBST(root: TreeNode?, min: Int?, max: Int?): Boolean { if (root == null) { return true } if (min != null && min > root.`val` || max != null && max < root.`val`) { return false } return isBST(root.left, min, root.`val`) && isBST(root.right, root.`val`, max) } private fun count(root: TreeNode?): Int { if (root == null) { return 0 } return count(root.left) + count(root.right) + 1 } }