{
"code": 0,
"msg": null,
"data": {
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"pageSize": 5,
"total": 1,
"pages": 1,
"list": [
{
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"sectionId": "1234567",
"tid": "0cb966d1355211e79954005056b233c9",
"first": "1",
"parentId": null,
"title": "五一要事",
"userId": "123456",
"userName": "王俐",
"postLayer": 1,
"status": "0",
"createTime": 1494401186000,
"content": "五一放假通知",
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"attachments": [
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"downloadUrl": "http://10.144.238.21:8080/starMOOC/forum/downloadFile/0710f56b355911e79954005056b233c9",
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js读取JSON的方法我接触到的有两种：
方法一：函数构造定义法返回
var strJSON = "{name:'json name'}";//得到的JSON
var obj = new Function("return" + strJSON)();//转换后的JSON对象
alert(obj.name);//json name
方法二：js中著名的eval函数
var strJSON = "{name:'json name'}";//得到的JSON
var obj = eval( "(" + strJSON + ")" );//转换后的JSON对象
alert(obj.name);//json name
第二种方法需要注意的是，对象表达式{'name':'json name'}必须用“（）”扩住，否则
var strJSON = "{name:'json name'}";
var obj = eval(strJSON);
alert(obj.constructor);//String 构造函数
alert(obj.name);//undefine
必须把对象表达式扩起来eval执行才能生成一个匿名对象!