• CodeForces Codeforces Round #547 (Div. 3) 2019年3月20日 (补题)


    A.

    Examples

    Input

    120 51840
    Output

    7
    Input

    42 42

    Output

    0
    Input

    48 72

    Output

    -1

    #include <iostream>
    
    using namespace std;
    
    int main()
    {
    	int m, n;
    	cin >> m >> n;
    	int step = 0;
    	if (n % m != 0)
    	{
    		cout << -1 << endl;
    		return 0;
    	}
    	else
    	{
    		int k = n / m;
    		while (k % 2 == 0) {
    			k /= 2;
    			step++;
    		}
    		while (k % 3 == 0) {
    			k /= 3;
    			step++;
    		}
    		if (k != 1) {
    			cout << -1 << endl;
    		}
    			
    		else
    		{
    			cout << step << endl;
    		}
    	}
    }
    

     B.

    Examples

    Input

    5
    1 0 1 0 1
    Output

    2
    Input

    6
    0 1 0 1 1 0

    Output

    2
    Input

    7
    1 0 1 1 1 0 1

    Output

    3
    Input

    3
    0 0 0

    Output

    0

    #include <iostream>
    #include <algorithm>
    
    using namespace std;
    
    int main()
    {
    	int a[200001];
    	int n;
    	cin >> n;
    	for (int i = 0; i < n; ++i) {
    		cin >> a[i];
    	}
    	int s = 0;
    	int max1 = 0;
    	if (a[0] == 0) {
    		
    		for (int i = 1; i < n; i++) {
    			if (a[i] == 1) {		
    				++s;
    				max1 = max(s, max1);
    				continue;
    			}
    			max1 = max(s, max1);
    			s = 0;
    		}
    		cout << max1 << endl;
    	}
    	if (a[0] == 1) {
    		if (a[n - 1] == 0) {
    			for (int i = 0; i < n; i++) {
    				if (a[i] == 1) {
    					++s;
    					max1 = max(s, max1);
    					continue;
    				}
    				max1 = max(s, max1);
    				s = 0;
    			}
    			cout << max1 << endl;
    		}
    		else {
    			int aa = 0;
    			for (int i = n - 1; a[i] == 1 && i >= 0; i--) {
    				s++;
    				aa = i;
    			}
    			for (int i = 0; i < aa; i++) {
    				if (a[i] == 1) {
    					++s;
    					max1 = max(s, max1);
    					continue;
    				}
    				max1 = max(s, max1);
    				s = 0;
    			}
    			cout << max1 << endl;
    		}
    	}
    
    
    }
    

     


     

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  • 原文地址:https://www.cnblogs.com/lightac/p/10564316.html
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