• HashMap 源码解读


    HashMap 源码解读

    在很多面试中,都会涉及到HashMap的问题,比如说问你HashMap存储结构,getput的时间复杂度,或者扩容机制等等,这次我们来通过对源码的阅读,来实现对HashMap的理解!(大量源码源码警告!!!)
    先看类的继承结构:

    public class HashMap<K,V> extends AbstractMap<K,V>
        implements Map<K,V>, Cloneable, Serializable {
        	...
        }
    

    可以看到HashMap继承了抽象类AbstractMap,实现了MapCloneableSerializable接口。
    这边有点奇怪,明明抽象类AbstractMap已经实现了Map接口,为什么HashMap又要实现一下?可能的原因:1、为了使用getInterfaces可以获取到Map,因为这样子没法获取到父类的接口;2、笔误(据说是作者 Jpsh Bloch自己说的。。。)
    对于这些接口中的方法就不单独解释了,下面一起来看源码就好。

    首先是一些常量属性

    // 默认初始化容量,16。必须是 2 的幂次。
    static final int DEFAULT_INITIAL_CAPACITY = 1 << 4; // aka 16
    
    // 最大容量 2^30,在构造函数中可以设置,必须是 2 的幂次。
    static final int MAXIMUM_CAPACITY = 1 << 30;
    
    // 默认装载因子 0.75,构造函数中可以自己设置
    static final float DEFAULT_LOAD_FACTOR = 0.75f;
    
    // 变成红黑树结构的容量,大于等于 8 就从表结构变成了红黑树结构
    static final int TREEIFY_THRESHOLD = 8;
    
    // 变成表结构的容量,小于等于 6 就从红黑树结构变成了表结构
    static final int UNTREEIFY_THRESHOLD = 6;
    
    // 红黑树结构的最小容量,最少是 4 * TREEIFY_THRESHOLD 以避免重构时的冲突
    static final int MIN_TREEIFY_CAPACITY = 64;
    

    然后是一个静态内部类Node<K,V>

    	// 实现了 Entry 接口可用于 AbstractMap 中的方法
    	static class Node<K,V> implements Map.Entry<K,V> {
    		// hash 值
            final int hash;
            // 键
            final K key;
            // 值
            V value;
            // 下一个节点
            Node<K,V> next;
    
            Node(int hash, K key, V value, Node<K,V> next) {
                this.hash = hash;
                this.key = key;
                this.value = value;
                this.next = next;
            }
            // Node 的 get、set 方法,用于被外部类方法调用
            public final K getKey()        { return key; }
            public final V getValue()      { return value; }
            public final String toString() { return key + "=" + value; }
    
            // 键的 hash 值 ^ 值的 hash 值
            // 这边我们其他的可以不了解,但是 String 的 hash 算法必须了解。
            public final int hashCode() {
                return Objects.hashCode(key) ^ Objects.hashCode(value);
            }
    
            public final V setValue(V newValue) {
                V oldValue = value;
                value = newValue;
                return oldValue;
            }
    
            // 两个节点的比较,先比较地址,否则如果是 Map.Entry 则分别比较键和值
            public final boolean equals(Object o) {
                if (o == this)
                    return true;
                if (o instanceof Map.Entry) {
                    Map.Entry<?,?> e = (Map.Entry<?,?>)o;
                    if (Objects.equals(key, e.getKey()) &&
                        Objects.equals(value, e.getValue()))
                        return true;
                }
                return false;
            }
        }
    

    看完了内部存储键值对的静态内部类,接下来看静态方法

    	// 查看某个键的 hash 值,在基础的 hashCode() 方法后又对其进行了处理
    	static final int hash(Object key) {
            int h;
            return (key == null) ? 0 : (h = key.hashCode()) ^ (h >>> 16);
        }
    
        // x 如果直接实现了 comparable 接口,就返回 x 的 Class,否则返回 Null
        static Class<?> comparableClassFor(Object x) {
        	...
        }
    
        // 如果 x 是 kc 类型,返回 k.compareTo(x) 的结果,否则返回 0
        static int compareComparables(Class<?> kc, Object k, Object x) {
            return (x == null || x.getClass() != kc ? 0 :
                    ((Comparable)k).compareTo(x));
        }
    
        // 这边是返回最小的大于 cap 的 2 的幂次,比如说 cap 为 3 则结果是 4, cap 为 5 则结果是 8 。|= 就是按位或后赋值。
        static final int tableSizeFor(int cap) {
            int n = cap - 1;
            n |= n >>> 1;
            n |= n >>> 2;
            n |= n >>> 4;
            n |= n >>> 8;
            n |= n >>> 16;
            return (n < 0) ? 1 : (n >= MAXIMUM_CAPACITY) ? MAXIMUM_CAPACITY : n + 1;
        }
    

    接下来是一些变量属性

    // 表结构是存储的内容
    transient Node<K,V>[] table;
    
    // 
    transient Set<Map.Entry<K,V>> entrySet;
    
    // 键值对数量
    transient int size;
    
    // 当发生结构性变化时增加,用于表面遍历时对HashMap进行修改操作
    transient int modCount;
    
    // 下一次 resize 的值
    int threshold;
    
    // hash table 的装载因子
    final float loadFactor;
    

    再下面是 public 的操作

    	/** 
    	* 构造函数们
    	*/
    
    	// 传入初始容量和装载因子的构造函数,这里可以看到,initialCapacity 并不是直接去创建这个大小的数组,而是使用 tableSizeFor 函数后传递给了 threshold 属性
    	public HashMap(int initialCapacity, float loadFactor) {
            if (initialCapacity < 0)
                throw new IllegalArgumentException("Illegal initial capacity: " +
                                                   initialCapacity);
            if (initialCapacity > MAXIMUM_CAPACITY)
                initialCapacity = MAXIMUM_CAPACITY;
            if (loadFactor <= 0 || Float.isNaN(loadFactor))
                throw new IllegalArgumentException("Illegal load factor: " +
                                                   loadFactor);
            this.loadFactor = loadFactor;
            this.threshold = tableSizeFor(initialCapacity);
        }
    
        // 传入初始容量,并使用默认的装载因子调用上面的构造函数
        public HashMap(int initialCapacity) {
            this(initialCapacity, DEFAULT_LOAD_FACTOR);
        }
    
        // 无参的构造函数,默认调用
        public HashMap() {
            this.loadFactor = DEFAULT_LOAD_FACTOR; // all other fields defaulted
        }
    
        // 将 m 的节点放入表或者树中
        public HashMap(Map<? extends K, ? extends V> m) {
            this.loadFactor = DEFAULT_LOAD_FACTOR;
            putMapEntries(m, false);
        }
    
        // 实现了 Map 接口中的 putAll 方法
        final void putMapEntries(Map<? extends K, ? extends V> m, boolean evict) {
            // 获取 m 的大小
            int s = m.size();
            if (s > 0) {
            	// 当 HashMap 为空时,也就是没有内容时,计算 t 和 threshhold进行比较
                if (table == null) { // pre-size
                    float ft = ((float)s / loadFactor) + 1.0F;
                    int t = ((ft < (float)MAXIMUM_CAPACITY) ?
                             (int)ft : MAXIMUM_CAPACITY);
                    if (t > threshold)
                        threshold = tableSizeFor(t);
                }
                // 如果 m 的大小比下一次 resize 的值要大,直接 resize
                else if (s > threshold)
                    resize();
                 // 遍历 m 将节点进行保存
                for (Map.Entry<? extends K, ? extends V> e : m.entrySet()) {
                    K key = e.getKey();
                    V value = e.getValue();
                    putVal(hash(key), key, value, false, evict);
                }
            }
        }
    
        // 返回键值对数量
        public int size() {
            return size;
        }
    
        // 返回键值对数量是否为0(即 HashMap 是否还没有键值对)
        public boolean isEmpty() {
            return size == 0;
        }
    
        // 通过 getNode 的方法获取对应 key 的节点的 value
        public V get(Object key) {
            Node<K,V> e;
            return (e = getNode(hash(key), key)) == null ? null : e.value;
        }
    
        // 利用 key 的 hash 值以及 key 获取对应 key 的 Node
        final Node<K,V> getNode(int hash, Object key) {
            Node<K,V>[] tab; Node<K,V> first, e; int n; K k;
            // 这个判断有三部分,第一部分判断存储数组是否为空,第二部分判断数组长度是否为0,第三部分判断 (n-1) & hash 值的位置是否存在该 key 对应的节点(这样主要是因为 put 的时候就是这么存的)
            if ((tab = table) != null && (n = tab.length) > 0 &&
                (first = tab[(n - 1) & hash]) != null) {
                // 如果 key 的 hash 值和对应节点 key 的 hash 值相等并且 key 相等或者 equals 之后相等且不为 null,则返回该节点
                if (first.hash == hash && // always check first node
                    ((k = first.key) == key || (key != null && key.equals(k))))
                    return first;
                // 如果上面的不成立,并且 first 节点上有 next(next 应该是解决 hash 冲突的解决方案)
                if ((e = first.next) != null) {
                	// 如果是 TreeNode(表明是红黑树的结构),那么利用 hash 值和 key 找到红黑树中的节点
                    if (first instanceof TreeNode)
                        return ((TreeNode<K,V>)first).getTreeNode(hash, key);
                    // 否则,不断的找冲突解决方案中的 next 直到找到对应节点或者找完
                    do {
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k))))
                            return e;
                    } while ((e = e.next) != null);
                }
            }
            return null;
        }
    
        // 利用 key 和 getNode 方法找到节点,没找到就没有该 key 对应的节点  
        public boolean containsKey(Object key) {
            return getNode(hash(key), key) != null;
        }
    
        // 插入键值对
        public V put(K key, V value) {
            return putVal(hash(key), key, value, false, true);
        }
    
        // 插入键值对的实际方法
        final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
                       boolean evict) {
            Node<K,V>[] tab; Node<K,V> p; int n, i;
            // 如果存储数组为 null 或者数组长度为0,那么将存储从结构 resize 一下后赋值给数组并将长度赋值给 n
            if ((tab = table) == null || (n = tab.length) == 0)
                n = (tab = resize()).length;
            // 如果对应的地方没有节点,那么新建节点并赋值到数组的对应位置
            if ((p = tab[i = (n - 1) & hash]) == null)
                tab[i] = newNode(hash, key, value, null);
            // 如果对应地方有节点,那么只可能有两种情况:1、对应的键存在,那么修改值;2、表结构起冲突了不够存了,要么在该节点的位置增加 next 冲突节点,或者转换成树结构的 putval 方法
            else {
                Node<K,V> e; K k;
                // 表结构对应位置存在对应的 key 的节点,那么将 e 赋值成为该节点
                if (p.hash == hash &&
                    ((k = p.key) == key || (key != null && key.equals(k))))
                    e = p;
                // 如果表结构对应位置的 key 跟说好的不一样,并且该位置是个 TreeNode,那么调用树结构的 putVal 操作
                else if (p instanceof TreeNode)
                    e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
                // 如果是该位置不是树结构的节点并且跟说好的不一样,那么在
                else {
                    for (int binCount = 0; ; ++binCount) {
                    	// 本身该位置的节点没有冲突节点,那么加冲突节点
                        if ((e = p.next) == null) {
                            p.next = newNode(hash, key, value, null);
                            if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                                treeifyBin(tab, hash);
                            break;
                        }
                        // 找到该位置冲突节点中需要的值了,赋值给 e
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k))))
                            break;
                        p = e;
                    }
                }
                // 对已经有的对应 key 的键值对,进行值的替换并返回旧的值
                if (e != null) { // existing mapping for key
                    V oldValue = e.value;
                    if (!onlyIfAbsent || oldValue == null)
                        e.value = value;
                    // 这边是一个回调函数,对节点进行修改后会调用这个函数,HashMap中没有定义具体方法
                    afterNodeAccess(e);
                    return oldValue;
                }
            }
            // 新增节点后的处理工作:增加修改次数、增加键值对数量并决定要不要 resize、增加节点后的方法(同样是回调函数,HashMap中没定义)
            ++modCount;
            if (++size > threshold)
                resize();
            afterNodeInsertion(evict);
            return null;
        }
    
        // resize 方法是将数组进行扩容,不是将表结构转换成树结构
        final Node<K,V>[] resize() {
            Node<K,V>[] oldTab = table;
            int oldCap = (oldTab == null) ? 0 : oldTab.length;
            int oldThr = threshold;
            int newCap, newThr = 0;
            if (oldCap > 0) {
            	// 如果原本的长度大于等于最大值,就把 threshold设置成最大值
                if (oldCap >= MAXIMUM_CAPACITY) {
                    threshold = Integer.MAX_VALUE;
                    return oldTab;
                }
                // 否则将新长度变成旧长度 * 2, 将 threshold * 2
                else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
                         oldCap >= DEFAULT_INITIAL_CAPACITY)
                    newThr = oldThr << 1; // double threshold
            }
            // 如果原来容量为0,那么把原来的 threshold 赋值给新的容量
            else if (oldThr > 0) // initial capacity was placed in threshold
                newCap = oldThr;
            // 如果原来的 threshold 为0,那么使用默认值进行赋值
            else {               // zero initial threshold signifies using defaults
                newCap = DEFAULT_INITIAL_CAPACITY;
                newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY);
            }
            // 如果新的 threshold 为0,就使用默认值计算出新的 threshold
            if (newThr == 0) {
                float ft = (float)newCap * loadFactor;
                newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
                          (int)ft : Integer.MAX_VALUE);
            }
            threshold = newThr;
            // 创建一个新的容量的数组
            @SuppressWarnings({"rawtypes","unchecked"})
                Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
            table = newTab;
            // 下面循环做的就是将旧的数组中的节点全部放到新的数组中去
            if (oldTab != null) {
                for (int j = 0; j < oldCap; ++j) {
                    Node<K,V> e;
                    if ((e = oldTab[j]) != null) {
                        oldTab[j] = null;
                        if (e.next == null)
                            newTab[e.hash & (newCap - 1)] = e;
                        else if (e instanceof TreeNode)
                            ((TreeNode<K,V>)e).split(this, newTab, j, oldCap);
                        else { // preserve order
                            Node<K,V> loHead = null, loTail = null;
                            Node<K,V> hiHead = null, hiTail = null;
                            Node<K,V> next;
                            do {
                                next = e.next;
                                if ((e.hash & oldCap) == 0) {
                                    if (loTail == null)
                                        loHead = e;
                                    else
                                        loTail.next = e;
                                    loTail = e;
                                }
                                else {
                                    if (hiTail == null)
                                        hiHead = e;
                                    else
                                        hiTail.next = e;
                                    hiTail = e;
                                }
                            } while ((e = next) != null);
                            if (loTail != null) {
                                loTail.next = null;
                                newTab[j] = loHead;
                            }
                            if (hiTail != null) {
                                hiTail.next = null;
                                newTab[j + oldCap] = hiHead;
                            }
                        }
                    }
                }
            }
            return newTab;
        }
    
        // 如果原来的数组长度小于最小变成树的值,那么 resize,否则把指定 hash 位置的普通的 Node 转化成 TreeNode(TreeNode也是个静态内部类,是红黑树的节点)
        final void treeifyBin(Node<K,V>[] tab, int hash) {
            int n, index; Node<K,V> e;
            if (tab == null || (n = tab.length) < MIN_TREEIFY_CAPACITY)
                resize();
            else if ((e = tab[index = (n - 1) & hash]) != null) {
                TreeNode<K,V> hd = null, tl = null;
                do {
                    TreeNode<K,V> p = replacementTreeNode(e, null);
                    if (tl == null)
                        hd = p;
                    else {
                        p.prev = tl;
                        tl.next = p;
                    }
                    tl = p;
                } while ((e = e.next) != null);
                if ((tab[index] = hd) != null)
                	// 把这个节点和其相关节点变成树
                    hd.treeify(tab);
            }
        }
    
        // 就调用了前面的方法,目的是把 m 的值放到当前 map 中
        public void putAll(Map<? extends K, ? extends V> m) {
            putMapEntries(m, true);
        }
    
        // 删除这个 key 对应的节点,调用了后面的 removeNode 方法
        public V remove(Object key) {
            Node<K,V> e;
            return (e = removeNode(hash(key), key, null, false, true)) == null ?
                null : e.value;
        }
    
        // 删除对应 key,value 的节点
        final Node<K,V> removeNode(int hash, Object key, Object value,
                                   boolean matchValue, boolean movable) {
            Node<K,V>[] tab; Node<K,V> p; int n, index;
            if ((tab = table) != null && (n = tab.length) > 0 &&
                (p = tab[index = (n - 1) & hash]) != null) {
                Node<K,V> node = null, e; K k; V v;
                // 如果这个 hash 位置的第一个节点就是对应 key 的节点
                if (p.hash == hash &&
                    ((k = p.key) == key || (key != null && key.equals(k))))
                    node = p;
               	// 找这个 hash 位置其他的节点
                else if ((e = p.next) != null) {
                	// 如果是树节点,用 getTreeNode 获取到节点
                    if (p instanceof TreeNode)
                        node = ((TreeNode<K,V>)p).getTreeNode(hash, key);
                    // 如果是普通节点,那么遍历下去
                    else {
                        do {
                            if (e.hash == hash &&
                                ((k = e.key) == key ||
                                 (key != null && key.equals(k)))) {
                                node = e;
                                break;
                            }
                            p = e;
                        } while ((e = e.next) != null);
                    }
                }
                // 删除节点的逻辑,这边有个标志位 matchValue,用于判断需不需要考虑 value 的对应
                if (node != null && (!matchValue || (v = node.value) == value ||
                                     (value != null && value.equals(v)))) {
                    // 考虑到树节点删除对于树的结构性改变,使用 removeTreeNode方法
                    if (node instanceof TreeNode)
                        ((TreeNode<K,V>)node).removeTreeNode(this, tab, movable);
                    // 当前 hash 位置只有一个节点,直接把要删除节点的 next 放到数组的这个 hash 位置
                    else if (node == p)
                        tab[index] = node.next;
                    // 当前 hash 位置不止一个节点,直接使用链表中删除节点的方法
                    else
                        p.next = node.next;
                    ++modCount;
                    --size;
                    afterNodeRemoval(node);
                    return node;
                }
            }
            return null;
        }
    
        // 清空所有节点,但是数组的长度没变
        public void clear() {
            Node<K,V>[] tab;
            modCount++;
            if ((tab = table) != null && size > 0) {
                size = 0;
                for (int i = 0; i < tab.length; ++i)
                    tab[i] = null;
            }
        }
    
        // 遍历所有节点查看是否存在 value 的节点
        public boolean containsValue(Object value) {
            Node<K,V>[] tab; V v;
            if ((tab = table) != null && size > 0) {
                for (int i = 0; i < tab.length; ++i) {
                    for (Node<K,V> e = tab[i]; e != null; e = e.next) {
                        if ((v = e.value) == value ||
                            (value != null && value.equals(v)))
                            return true;
                    }
                }
            }
            return false;
        }
    
        // 返回 KeySet
        public Set<K> keySet() {
            Set<K> ks = keySet;
            if (ks == null) {
                ks = new KeySet();
                keySet = ks;
            }
            return ks;
        }
    
        // 内部类 KeySet,提供了一些集合常用的方法。因为是继承了 AbstractSet 因此键唯一
        final class KeySet extends AbstractSet<K> {
            public final int size()                 { return size; }
            public final void clear()               { HashMap.this.clear(); }
            public final Iterator<K> iterator()     { return new KeyIterator(); }
            public final boolean contains(Object o) { return containsKey(o); }
            public final boolean remove(Object key) {
                return removeNode(hash(key), key, null, false, true) != null;
            }
            public final Spliterator<K> spliterator() {
                return new KeySpliterator<>(HashMap.this, 0, -1, 0, 0);
            }
            public final void forEach(Consumer<? super K> action) {
                Node<K,V>[] tab;
                if (action == null)
                    throw new NullPointerException();
                if (size > 0 && (tab = table) != null) {
                    int mc = modCount;
                    for (int i = 0; i < tab.length; ++i) {
                        for (Node<K,V> e = tab[i]; e != null; e = e.next)
                            action.accept(e.key);
                    }
                    if (modCount != mc)
                        throw new ConcurrentModificationException();
                }
            }
        }
    
        // 和上面 KeySet 相对应,返回 value 的集合
        public Collection<V> values() {
            Collection<V> vs = values;
            if (vs == null) {
                vs = new Values();
                values = vs;
            }
            return vs;
        }
    
        // 内部类 Values,提供了 value 的集合
        final class Values extends AbstractCollection<V> {
            public final int size()                 { return size; }
            public final void clear()               { HashMap.this.clear(); }
            public final Iterator<V> iterator()     { return new ValueIterator(); }
            public final boolean contains(Object o) { return containsValue(o); }
            public final Spliterator<V> spliterator() {
                return new ValueSpliterator<>(HashMap.this, 0, -1, 0, 0);
            }
            public final void forEach(Consumer<? super V> action) {
                Node<K,V>[] tab;
                if (action == null)
                    throw new NullPointerException();
                if (size > 0 && (tab = table) != null) {
                    int mc = modCount;
                    for (int i = 0; i < tab.length; ++i) {
                        for (Node<K,V> e = tab[i]; e != null; e = e.next)
                            action.accept(e.value);
                    }
                    if (modCount != mc)
                        throw new ConcurrentModificationException();
                }
            }
        }
    
        // 返回一个键值对的 set
        public Set<Map.Entry<K,V>> entrySet() {
            Set<Map.Entry<K,V>> es;
            return (es = entrySet) == null ? (entrySet = new EntrySet()) : es;
        }
    
        // 内部类 EntrySet,用于记录 map 中的节点
        final class EntrySet extends AbstractSet<Map.Entry<K,V>> {
            public final int size()                 { return size; }
            public final void clear()               { HashMap.this.clear(); }
            public final Iterator<Map.Entry<K,V>> iterator() {
                return new EntryIterator();
            }
            public final boolean contains(Object o) {
                if (!(o instanceof Map.Entry))
                    return false;
                Map.Entry<?,?> e = (Map.Entry<?,?>) o;
                Object key = e.getKey();
                Node<K,V> candidate = getNode(hash(key), key);
                return candidate != null && candidate.equals(e);
            }
            public final boolean remove(Object o) {
                if (o instanceof Map.Entry) {
                    Map.Entry<?,?> e = (Map.Entry<?,?>) o;
                    Object key = e.getKey();
                    Object value = e.getValue();
                    return removeNode(hash(key), key, value, true, true) != null;
                }
                return false;
            }
            public final Spliterator<Map.Entry<K,V>> spliterator() {
                return new EntrySpliterator<>(HashMap.this, 0, -1, 0, 0);
            }
            public final void forEach(Consumer<? super Map.Entry<K,V>> action) {
                Node<K,V>[] tab;
                if (action == null)
                    throw new NullPointerException();
                if (size > 0 && (tab = table) != null) {
                    int mc = modCount;
                    for (int i = 0; i < tab.length; ++i) {
                        for (Node<K,V> e = tab[i]; e != null; e = e.next)
                            action.accept(e);
                    }
                    if (modCount != mc)
                        throw new ConcurrentModificationException();
                }
            }
        }
    
        // 返回指定 key 的 value,如果没有则返回默认值 defaultValue
        public V getOrDefault(Object key, V defaultValue) {
            Node<K,V> e;
            return (e = getNode(hash(key), key)) == null ? defaultValue : e.value;
        }
    
        // 对应 key 没有 value 时更新,否则返回已有的 value
        @Override
        public V putIfAbsent(K key, V value) {
            return putVal(hash(key), key, value, true, true);
        }
    
        // 删除节点,成功返回 true,没有返回 false
        @Override
        public boolean remove(Object key, Object value) {
            return removeNode(hash(key), key, value, true, true) != null;
        }
    
        // 将对应键值对的 node 更改 value
        @Override
        public boolean replace(K key, V oldValue, V newValue) {
            Node<K,V> e; V v;
            if ((e = getNode(hash(key), key)) != null &&
                ((v = e.value) == oldValue || (v != null && v.equals(oldValue)))) {
                e.value = newValue;
                afterNodeAccess(e);
                return true;
            }
            return false;
        }
    
        // 对应键的 node 更改 value
        @Override
        public V replace(K key, V value) {
            Node<K,V> e;
            if ((e = getNode(hash(key), key)) != null) {
                V oldValue = e.value;
                e.value = value;
                afterNodeAccess(e);
                return oldValue;
            }
            return null;
        }
    
        // 传入一个 Function,对应 key 的值如果没有则更新为对 key 进行 Function 运算的结果,否则返回原来的 value
        @Override
        public V computeIfAbsent(K key,
                                 Function<? super K, ? extends V> mappingFunction) {
            if (mappingFunction == null)
                throw new NullPointerException();
            int hash = hash(key);
            Node<K,V>[] tab; Node<K,V> first; int n, i;
            int binCount = 0;
            TreeNode<K,V> t = null;
            Node<K,V> old = null;
            // 下面是先找到对应 key 的节点
            if (size > threshold || (tab = table) == null ||
                (n = tab.length) == 0)
                n = (tab = resize()).length;
            if ((first = tab[i = (n - 1) & hash]) != null) {
                if (first instanceof TreeNode)
                    old = (t = (TreeNode<K,V>)first).getTreeNode(hash, key);
                else {
                    Node<K,V> e = first; K k;
                    do {
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k)))) {
                            old = e;
                            break;
                        }
                        ++binCount;
                    } while ((e = e.next) != null);
                }
                V oldValue;
                if (old != null && (oldValue = old.value) != null) {
                    afterNodeAccess(old);
                    return oldValue;
                }
            }
            // value 是对 key 进行 Function 中的运算后的结果
            V v = mappingFunction.apply(key);
            if (v == null) {
                return null;
            } else if (old != null) {
                old.value = v;
                afterNodeAccess(old);
                return v;
            }
            else if (t != null)
                t.putTreeVal(this, tab, hash, key, v);
            else {
                tab[i] = newNode(hash, key, v, first);
                if (binCount >= TREEIFY_THRESHOLD - 1)
                    treeifyBin(tab, hash);
            }
            ++modCount;
            ++size;
            afterNodeInsertion(true);
            return v;
        }
    
        // 当对应 key 的 node 存在,进行传入的 BitFunction
        public V computeIfPresent(K key,
                                  BiFunction<? super K, ? super V, ? extends V> remappingFunction) {
            if (remappingFunction == null)
                throw new NullPointerException();
            Node<K,V> e; V oldValue;
            int hash = hash(key);
            if ((e = getNode(hash, key)) != null &&
                (oldValue = e.value) != null) {
                V v = remappingFunction.apply(key, oldValue);
                if (v != null) {
                    e.value = v;
                    afterNodeAccess(e);
                    return v;
                }
                else
                	// 如果运算结果是 null,删除节点
                    removeNode(hash, key, null, false, true);
            }
        }
        
        // 
        public V compute(K key,
                         BiFunction<? super K, ? super V, ? extends V> remappingFunction) {
            if (remappingFunction == null)
                throw new NullPointerException();
            int hash = hash(key);
            Node<K,V>[] tab; Node<K,V> first; int n, i;
            int binCount = 0;
            TreeNode<K,V> t = null;
            Node<K,V> old = null;
            // 找到对应 key 的节点
            if (size > threshold || (tab = table) == null ||
                (n = tab.length) == 0)
                n = (tab = resize()).length;
            if ((first = tab[i = (n - 1) & hash]) != null) {
                if (first instanceof TreeNode)
                    old = (t = (TreeNode<K,V>)first).getTreeNode(hash, key);
                else {
                    Node<K,V> e = first; K k;
                    do {
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k)))) {
                            old = e;
                            break;
                        }
                        ++binCount;
                    } while ((e = e.next) != null);
                }
            }
            V oldValue = (old == null) ? null : old.value;
            // 如果找到了节点,用 key 和 value 进行计算并赋值给 value 或者 v 为 null时删除节点
            // 没找到节点但是计算的 v 不为null,那么更新树节点???
            V v = remappingFunction.apply(key, oldValue);
            if (old != null) {
                if (v != null) {
                    old.value = v;
                    afterNodeAccess(old);
                }
                else
                	// 如果运算结果是 null,删除节点
                    removeNode(hash, key, null, false, true);
            }
            else if (v != null) {
                if (t != null)
                    t.putTreeVal(this, tab, hash, key, v);
                else {
                    tab[i] = newNode(hash, key, v, first);
                    if (binCount >= TREEIFY_THRESHOLD - 1)
                        treeifyBin(tab, hash);
                }
                ++modCount;
                ++size;
                afterNodeInsertion(true);
            }
            return v;
        }   
    
        // 找到对应 key 的节点,将节点的值 oldValue 和参数 value 进行运算,并赋值给节点的值。
         @Override
        public V merge(K key, V value,
                       BiFunction<? super V, ? super V, ? extends V> remappingFunction) {
            if (value == null)
                throw new NullPointerException();
            if (remappingFunction == null)
                throw new NullPointerException();
            int hash = hash(key);
            Node<K,V>[] tab; Node<K,V> first; int n, i;
            int binCount = 0;
            TreeNode<K,V> t = null;
            Node<K,V> old = null;
            // 找到节点(ps:每个函数都用,为啥不干脆抽出来?)
            if (size > threshold || (tab = table) == null ||
                (n = tab.length) == 0)
                n = (tab = resize()).length;
            if ((first = tab[i = (n - 1) & hash]) != null) {
                if (first instanceof TreeNode)
                    old = (t = (TreeNode<K,V>)first).getTreeNode(hash, key);
                else {
                    Node<K,V> e = first; K k;
                    do {
                        if (e.hash == hash &&
                            ((k = e.key) == key || (key != null && key.equals(k)))) {
                            old = e;
                            break;
                        }
                        ++binCount;
                    } while ((e = e.next) != null);
                }
            }
            if (old != null) {
                V v;
                // 将节点的 value 和输入的参数 value 进行计算
                if (old.value != null)
                    v = remappingFunction.apply(old.value, value);
                else
                    v = value;
                // 如果计算结果不为 null,赋值给该节点
                if (v != null) {
                    old.value = v;
                    afterNodeAccess(old);
                }
                else
                	// 否则删除节点
                    removeNode(hash, key, null, false, true);
                return v;
            }
            // 这边通过 putVal 去赋值?为什么?
            if (value != null) {
                if (t != null)
                    t.putTreeVal(this, tab, hash, key, value);
                else {
                    tab[i] = newNode(hash, key, value, first);
                    if (binCount >= TREEIFY_THRESHOLD - 1)
                        treeifyBin(tab, hash);
                }
                ++modCount;
                ++size;
                afterNodeInsertion(true);
            }
            return value;
        }
    
        // 遍历每个节点并对其进行 action.accept 的操作
         @Override
        public void forEach(BiConsumer<? super K, ? super V> action) {
            Node<K,V>[] tab;
            if (action == null)
                throw new NullPointerException();
            if (size > 0 && (tab = table) != null) {
                int mc = modCount;
                for (int i = 0; i < tab.length; ++i) {
                    for (Node<K,V> e = tab[i]; e != null; e = e.next)
                        action.accept(e.key, e.value);
                }
                if (modCount != mc)
                    throw new ConcurrentModificationException();
            }
        }
    
        // 遍历每个节点,将 value 转化成 function.apply 操作的结果
        @Override
        public void replaceAll(BiFunction<? super K, ? super V, ? extends V> function) {
            Node<K,V>[] tab;
            if (function == null)
                throw new NullPointerException();
            if (size > 0 && (tab = table) != null) {
                int mc = modCount;
                for (int i = 0; i < tab.length; ++i) {
                    for (Node<K,V> e = tab[i]; e != null; e = e.next) {
                        e.value = function.apply(e.key, e.value);
                    }
                }
                if (modCount != mc)
                    throw new ConcurrentModificationException();
            }
        }
    

    下面是实现另外两个接口中的方法,即CloneableSerializable的方法:

    	// clone 函数
        @Override
        public Object clone() {
            HashMap<K,V> result;
            try {
                result = (HashMap<K,V>)super.clone();
            } catch (CloneNotSupportedException e) {
                // this shouldn't happen, since we are Cloneable
                throw new InternalError(e);
            }
            result.reinitialize();
            result.putMapEntries(this, false);
            return result;
        }
    
        // 返回装载因子和容量(数组非空则返回数组长度,否则返回 threshold 或者默认初始化容量)
        final float loadFactor() { return loadFactor; }
        final int capacity() {
            return (table != null) ? table.length :
                (threshold > 0) ? threshold :
                DEFAULT_INITIAL_CAPACITY;
        }
    
    
        // 前面存储的 table 使用 transient 修饰的,因此没法持久化,这边自己实现了 writeObject 和 readObject 方法来完成持久化和反持久化
        private void writeObject(java.io.ObjectOutputStream s)
        	throws IOException {
        		...
        	}
    
        private void readObject(java.io.ObjectInputStream s)
            throws IOException, ClassNotFoundException {
            	...
            }
    

    下面是几个迭代器类,用于键啊、值、节点的迭代:

    	// 抽象类,用于下面被继承
    	abstract class HashIterator {
            Node<K,V> next;        // next entry to return
            Node<K,V> current;     // current entry
            int expectedModCount;  // for fast-fail
            int index;             // current slot
    
            // 构造函数
            HashIterator() {
            	// 将外部类(HashMap)的修改次数赋值给 expectedModCount
                expectedModCount = modCount;
                Node<K,V>[] t = table;
                current = next = null;
                index = 0;
                if (t != null && size > 0) { // advance to first entry
                    do {} while (index < t.length && (next = t[index++]) == null);
                }
            }
    
            public final boolean hasNext() {
                return next != null;
            }
    
            final Node<K,V> nextNode() {
                Node<K,V>[] t;
                Node<K,V> e = next;
                if (modCount != expectedModCount)
                    throw new ConcurrentModificationException();
                if (e == null)
                    throw new NoSuchElementException();
                // 如果当前表索引的节点遍历完了,取下一个索引的节点作为 next
                if ((next = (current = e).next) == null && (t = table) != null) {
                    do {} while (index < t.length && (next = t[index++]) == null);
                }
                return e;
            }
    
            public final void remove() {
                Node<K,V> p = current;
                if (p == null)
                    throw new IllegalStateException();
                if (modCount != expectedModCount)
                    throw new ConcurrentModificationException();
                current = null;
                K key = p.key;
                // 在迭代器中将节点 remove 掉了,那么外部类中也会 remove
                removeNode(hash(key), key, null, false, false);
                expectedModCount = modCount;
            }
        }
    
        // 下面是三个实现,区别只在于 next 函数返回的内容
        final class KeyIterator extends HashIterator
            implements Iterator<K> {
            public final K next() { return nextNode().key; }
        }
    
        final class ValueIterator extends HashIterator
            implements Iterator<V> {
            public final V next() { return nextNode().value; }
        }
    
        final class EntryIterator extends HashIterator
            implements Iterator<Map.Entry<K,V>> {
            public final Map.Entry<K,V> next() { return nextNode(); }
        }
    

    下面是几个 spliterator 类(可拆分迭代器):
    一个博客介绍了可拆分迭代器是啥。

    	// 所有 Spliterator 的父类,这边没什么特别的,关键方法都在 Spliterator 接口中,实现子类可以自己重写
        static class HashMapSpliterator<K,V> {
            final HashMap<K,V> map;
            Node<K,V> current;          // current node
            int index;                  // current index, modified on advance/split
            int fence;                  // one past last index
            int est;                    // size estimate
            int expectedModCount;       // for comodification checks
    
            HashMapSpliterator(HashMap<K,V> m, int origin,
                               int fence, int est,
                               int expectedModCount) {
                this.map = m;
                this.index = origin;
                this.fence = fence;
                this.est = est;
                this.expectedModCount = expectedModCount;
            }
    
            // 获取 fence,如果小于 0 则返回外部 tab 数组的长度,否则返回 fence
            final int getFence() { // initialize fence and size on first use
                int hi;
                if ((hi = fence) < 0) {
                    HashMap<K,V> m = map;
                    est = m.size;
                    expectedModCount = m.modCount;
                    Node<K,V>[] tab = m.table;
                    hi = fence = (tab == null) ? 0 : tab.length;
                }
                return hi;
            }
    
            // 强制初始化并返回 est
            public final long estimateSize() {
                getFence(); // force init
                return (long) est;
            }
        }
    
        // 键的 Spliterator, 实现了 Spliterator 接口(该接口中说明用于分治遍历元素,元素可以通过 tryAdvance() 方法独立的遍历或者 forEachRemaining() 方法各个分块按顺序遍历)。
        static final class KeySpliterator<K,V>
            extends HashMapSpliterator<K,V>
            implements Spliterator<K> {
            KeySpliterator(HashMap<K,V> m, int origin, int fence, int est,
                           int expectedModCount) {
                super(m, origin, fence, est, expectedModCount);
            }
    
            // 尝试拆分成出一个新的迭代器
            public KeySpliterator<K,V> trySplit() {
                int hi = getFence(), lo = index, mid = (lo + hi) >>> 1;
                return (lo >= mid || current != null) ? null :
                    new KeySpliterator<>(map, lo, index = mid, est >>>= 1,
                                            expectedModCount);
            }
    
            // 从 current 开始遍历,对节点进行 action.accept 操作,直到没有节点或者 table 的 index 改变了 fence 次(可以认为是经历了 fence 的 bucket)
            public void forEachRemaining(Consumer<? super K> action) {
                int i, hi, mc;
                if (action == null)
                    throw new NullPointerException();
                HashMap<K,V> m = map;
                Node<K,V>[] tab = m.table;
                if ((hi = fence) < 0) {
                    mc = expectedModCount = m.modCount;
                    hi = fence = (tab == null) ? 0 : tab.length;
                }
                else
                    mc = expectedModCount;
                if (tab != null && tab.length >= hi &&
                    (i = index) >= 0 && (i < (index = hi) || current != null)) {
                    Node<K,V> p = current;
                    current = null;
                    do {
                        if (p == null)
                            p = tab[i++];
                        else {
                            action.accept(p.key);
                            p = p.next;
                        }
                    } while (p != null || i < hi);
                    if (m.modCount != mc)
                        throw new ConcurrentModificationException();
                }
            }
    
            // 如果存在剩余元素,则对其执行给定操作,返回true(怎么感觉跟上面一样???)
            public boolean tryAdvance(Consumer<? super K> action) {
                int hi;
                if (action == null)
                    throw new NullPointerException();
                Node<K,V>[] tab = map.table;
                if (tab != null && tab.length >= (hi = getFence()) && index >= 0) {
                    while (current != null || index < hi) {
                        if (current == null)
                            current = tab[index++];
                        else {
                            K k = current.key;
                            current = current.next;
                            action.accept(k);
                            if (map.modCount != expectedModCount)
                                throw new ConcurrentModificationException();
                            return true;
                        }
                    }
                }
                return false;
            }
    
            // 返回此 Spliterator 及其元素的一组特性
            public int characteristics() {
                return (fence < 0 || est == map.size ? Spliterator.SIZED : 0) |
                    Spliterator.DISTINCT;
            }
        }
    
        // 各个环节跟 KeySpliterator 类似
        static final class ValueSpliterator<K,V>
            extends HashMapSpliterator<K,V>
            implements Spliterator<V> {
            ValueSpliterator(HashMap<K,V> m, int origin, int fence, int est,
                             int expectedModCount) {
                super(m, origin, fence, est, expectedModCount);
            }
    
            public ValueSpliterator<K,V> trySplit() {
                int hi = getFence(), lo = index, mid = (lo + hi) >>> 1;
                return (lo >= mid || current != null) ? null :
                    new ValueSpliterator<>(map, lo, index = mid, est >>>= 1,
                                              expectedModCount);
            }
    
            public void forEachRemaining(Consumer<? super V> action) {
                int i, hi, mc;
                if (action == null)
                    throw new NullPointerException();
                HashMap<K,V> m = map;
                Node<K,V>[] tab = m.table;
                if ((hi = fence) < 0) {
                    mc = expectedModCount = m.modCount;
                    hi = fence = (tab == null) ? 0 : tab.length;
                }
                else
                    mc = expectedModCount;
                if (tab != null && tab.length >= hi &&
                    (i = index) >= 0 && (i < (index = hi) || current != null)) {
                    Node<K,V> p = current;
                    current = null;
                    do {
                        if (p == null)
                            p = tab[i++];
                        else {
                            action.accept(p.value);
                            p = p.next;
                        }
                    } while (p != null || i < hi);
                    if (m.modCount != mc)
                        throw new ConcurrentModificationException();
                }
            }
    
            public boolean tryAdvance(Consumer<? super V> action) {
                int hi;
                if (action == null)
                    throw new NullPointerException();
                Node<K,V>[] tab = map.table;
                if (tab != null && tab.length >= (hi = getFence()) && index >= 0) {
                    while (current != null || index < hi) {
                        if (current == null)
                            current = tab[index++];
                        else {
                            V v = current.value;
                            current = current.next;
                            action.accept(v);
                            if (map.modCount != expectedModCount)
                                throw new ConcurrentModificationException();
                            return true;
                        }
                    }
                }
                return false;
            }
    
            public int characteristics() {
                return (fence < 0 || est == map.size ? Spliterator.SIZED : 0);
            }
        }
    
        // 同上
        static final class EntrySpliterator<K,V>
            extends HashMapSpliterator<K,V>
            implements Spliterator<Map.Entry<K,V>> {
            EntrySpliterator(HashMap<K,V> m, int origin, int fence, int est,
                             int expectedModCount) {
                super(m, origin, fence, est, expectedModCount);
            }
    
            public EntrySpliterator<K,V> trySplit() {
                int hi = getFence(), lo = index, mid = (lo + hi) >>> 1;
                return (lo >= mid || current != null) ? null :
                    new EntrySpliterator<>(map, lo, index = mid, est >>>= 1,
                                              expectedModCount);
            }
    
            public void forEachRemaining(Consumer<? super Map.Entry<K,V>> action) {
                int i, hi, mc;
                if (action == null)
                    throw new NullPointerException();
                HashMap<K,V> m = map;
                Node<K,V>[] tab = m.table;
                if ((hi = fence) < 0) {
                    mc = expectedModCount = m.modCount;
                    hi = fence = (tab == null) ? 0 : tab.length;
                }
                else
                    mc = expectedModCount;
                if (tab != null && tab.length >= hi &&
                    (i = index) >= 0 && (i < (index = hi) || current != null)) {
                    Node<K,V> p = current;
                    current = null;
                    do {
                        if (p == null)
                            p = tab[i++];
                        else {
                            action.accept(p);
                            p = p.next;
                        }
                    } while (p != null || i < hi);
                    if (m.modCount != mc)
                        throw new ConcurrentModificationException();
                }
            }
    
            public boolean tryAdvance(Consumer<? super Map.Entry<K,V>> action) {
                int hi;
                if (action == null)
                    throw new NullPointerException();
                Node<K,V>[] tab = map.table;
                if (tab != null && tab.length >= (hi = getFence()) && index >= 0) {
                    while (current != null || index < hi) {
                        if (current == null)
                            current = tab[index++];
                        else {
                            Node<K,V> e = current;
                            current = current.next;
                            action.accept(e);
                            if (map.modCount != expectedModCount)
                                throw new ConcurrentModificationException();
                            return true;
                        }
                    }
                }
                return false;
            }
    
            public int characteristics() {
                return (fence < 0 || est == map.size ? Spliterator.SIZED : 0) |
                    Spliterator.DISTINCT;
            }
        }
    

    下面是针对LinkedHashMap需要重写的方法:

    	// 创建一个非树节点
        Node<K,V> newNode(int hash, K key, V value, Node<K,V> next) {
            return new Node<>(hash, key, value, next);
        }
    
        // 将一个非树节点转化成树节点
        Node<K,V> replacementNode(Node<K,V> p, Node<K,V> next) {
            return new Node<>(p.hash, p.key, p.value, next);
        }
    
        // 创建一个树节点
        TreeNode<K,V> newTreeNode(int hash, K key, V value, Node<K,V> next) {
            return new TreeNode<>(hash, key, value, next);
        }
    
        // 将一个节点下的节点转换成树形结构
        TreeNode<K,V> replacementTreeNode(Node<K,V> p, Node<K,V> next) {
            return new TreeNode<>(p.hash, p.key, p.value, next);
        }
    
        // 重置默认状态,被 clone() 和 readObject() 调用
        void reinitialize() {
            table = null;
            entrySet = null;
            keySet = null;
            values = null;
            modCount = 0;
            threshold = 0;
            size = 0;
        }
    
        // 回调函数,需要 LinkedHashMap 自己重写
        void afterNodeAccess(Node<K,V> p) { }
        void afterNodeInsertion(boolean evict) { }
        void afterNodeRemoval(Node<K,V> p) { }
    
        // 只被 writeObject() 方法调用,保证顺序
        void internalWriteEntries(java.io.ObjectOutputStream s) throws IOException {
            Node<K,V>[] tab;
            if (size > 0 && (tab = table) != null) {
                for (int i = 0; i < tab.length; ++i) {
                    for (Node<K,V> e = tab[i]; e != null; e = e.next) {
                        s.writeObject(e.key);
                        s.writeObject(e.value);
                    }
                }
            }
        }
    

    后面是树形结构的类和方法:
    emmmmmm......由于红黑树不是很懂,这部分就先不看了

        /**
         * Entry for Tree bins. Extends LinkedHashMap.Entry (which in turn
         * extends Node) so can be used as extension of either regular or
         * linked node.
         */
        static final class TreeNode<K,V> extends LinkedHashMap.Entry<K,V> {
            TreeNode<K,V> parent;  // red-black tree links
            TreeNode<K,V> left;
            TreeNode<K,V> right;
            TreeNode<K,V> prev;    // needed to unlink next upon deletion
            boolean red;
            TreeNode(int hash, K key, V val, Node<K,V> next) {
                super(hash, key, val, next);
            }
    
            /**
             * Returns root of tree containing this node.
             */
            final TreeNode<K,V> root() {
                for (TreeNode<K,V> r = this, p;;) {
                    if ((p = r.parent) == null)
                        return r;
                    r = p;
                }
            }
    
            /**
             * Ensures that the given root is the first node of its bin.
             */
            static <K,V> void moveRootToFront(Node<K,V>[] tab, TreeNode<K,V> root) {
                int n;
                if (root != null && tab != null && (n = tab.length) > 0) {
                    int index = (n - 1) & root.hash;
                    TreeNode<K,V> first = (TreeNode<K,V>)tab[index];
                    if (root != first) {
                        Node<K,V> rn;
                        tab[index] = root;
                        TreeNode<K,V> rp = root.prev;
                        if ((rn = root.next) != null)
                            ((TreeNode<K,V>)rn).prev = rp;
                        if (rp != null)
                            rp.next = rn;
                        if (first != null)
                            first.prev = root;
                        root.next = first;
                        root.prev = null;
                    }
                    assert checkInvariants(root);
                }
            }
    
            /**
             * Finds the node starting at root p with the given hash and key.
             * The kc argument caches comparableClassFor(key) upon first use
             * comparing keys.
             */
            final TreeNode<K,V> find(int h, Object k, Class<?> kc) {
                TreeNode<K,V> p = this;
                do {
                    int ph, dir; K pk;
                    TreeNode<K,V> pl = p.left, pr = p.right, q;
                    if ((ph = p.hash) > h)
                        p = pl;
                    else if (ph < h)
                        p = pr;
                    else if ((pk = p.key) == k || (k != null && k.equals(pk)))
                        return p;
                    else if (pl == null)
                        p = pr;
                    else if (pr == null)
                        p = pl;
                    else if ((kc != null ||
                              (kc = comparableClassFor(k)) != null) &&
                             (dir = compareComparables(kc, k, pk)) != 0)
                        p = (dir < 0) ? pl : pr;
                    else if ((q = pr.find(h, k, kc)) != null)
                        return q;
                    else
                        p = pl;
                } while (p != null);
                return null;
            }
    
            /**
             * Calls find for root node.
             */
            final TreeNode<K,V> getTreeNode(int h, Object k) {
                return ((parent != null) ? root() : this).find(h, k, null);
            }
    
            /**
             * Tie-breaking utility for ordering insertions when equal
             * hashCodes and non-comparable. We don't require a total
             * order, just a consistent insertion rule to maintain
             * equivalence across rebalancings. Tie-breaking further than
             * necessary simplifies testing a bit.
             */
            static int tieBreakOrder(Object a, Object b) {
                int d;
                if (a == null || b == null ||
                    (d = a.getClass().getName().
                     compareTo(b.getClass().getName())) == 0)
                    d = (System.identityHashCode(a) <= System.identityHashCode(b) ?
                         -1 : 1);
                return d;
            }
    
            /**
             * Forms tree of the nodes linked from this node.
             * @return root of tree
             */
            final void treeify(Node<K,V>[] tab) {
                TreeNode<K,V> root = null;
                for (TreeNode<K,V> x = this, next; x != null; x = next) {
                    next = (TreeNode<K,V>)x.next;
                    x.left = x.right = null;
                    if (root == null) {
                        x.parent = null;
                        x.red = false;
                        root = x;
                    }
                    else {
                        K k = x.key;
                        int h = x.hash;
                        Class<?> kc = null;
                        for (TreeNode<K,V> p = root;;) {
                            int dir, ph;
                            K pk = p.key;
                            if ((ph = p.hash) > h)
                                dir = -1;
                            else if (ph < h)
                                dir = 1;
                            else if ((kc == null &&
                                      (kc = comparableClassFor(k)) == null) ||
                                     (dir = compareComparables(kc, k, pk)) == 0)
                                dir = tieBreakOrder(k, pk);
    
                            TreeNode<K,V> xp = p;
                            if ((p = (dir <= 0) ? p.left : p.right) == null) {
                                x.parent = xp;
                                if (dir <= 0)
                                    xp.left = x;
                                else
                                    xp.right = x;
                                root = balanceInsertion(root, x);
                                break;
                            }
                        }
                    }
                }
                moveRootToFront(tab, root);
            }
    
            /**
             * Returns a list of non-TreeNodes replacing those linked from
             * this node.
             */
            final Node<K,V> untreeify(HashMap<K,V> map) {
                Node<K,V> hd = null, tl = null;
                for (Node<K,V> q = this; q != null; q = q.next) {
                    Node<K,V> p = map.replacementNode(q, null);
                    if (tl == null)
                        hd = p;
                    else
                        tl.next = p;
                    tl = p;
                }
                return hd;
            }
    
            /**
             * Tree version of putVal.
             */
            final TreeNode<K,V> putTreeVal(HashMap<K,V> map, Node<K,V>[] tab,
                                           int h, K k, V v) {
                Class<?> kc = null;
                boolean searched = false;
                TreeNode<K,V> root = (parent != null) ? root() : this;
                for (TreeNode<K,V> p = root;;) {
                    int dir, ph; K pk;
                    if ((ph = p.hash) > h)
                        dir = -1;
                    else if (ph < h)
                        dir = 1;
                    else if ((pk = p.key) == k || (k != null && k.equals(pk)))
                        return p;
                    else if ((kc == null &&
                              (kc = comparableClassFor(k)) == null) ||
                             (dir = compareComparables(kc, k, pk)) == 0) {
                        if (!searched) {
                            TreeNode<K,V> q, ch;
                            searched = true;
                            if (((ch = p.left) != null &&
                                 (q = ch.find(h, k, kc)) != null) ||
                                ((ch = p.right) != null &&
                                 (q = ch.find(h, k, kc)) != null))
                                return q;
                        }
                        dir = tieBreakOrder(k, pk);
                    }
    
                    TreeNode<K,V> xp = p;
                    if ((p = (dir <= 0) ? p.left : p.right) == null) {
                        Node<K,V> xpn = xp.next;
                        TreeNode<K,V> x = map.newTreeNode(h, k, v, xpn);
                        if (dir <= 0)
                            xp.left = x;
                        else
                            xp.right = x;
                        xp.next = x;
                        x.parent = x.prev = xp;
                        if (xpn != null)
                            ((TreeNode<K,V>)xpn).prev = x;
                        moveRootToFront(tab, balanceInsertion(root, x));
                        return null;
                    }
                }
            }
    
            /**
             * Removes the given node, that must be present before this call.
             * This is messier than typical red-black deletion code because we
             * cannot swap the contents of an interior node with a leaf
             * successor that is pinned by "next" pointers that are accessible
             * independently during traversal. So instead we swap the tree
             * linkages. If the current tree appears to have too few nodes,
             * the bin is converted back to a plain bin. (The test triggers
             * somewhere between 2 and 6 nodes, depending on tree structure).
             */
            final void removeTreeNode(HashMap<K,V> map, Node<K,V>[] tab,
                                      boolean movable) {
                int n;
                if (tab == null || (n = tab.length) == 0)
                    return;
                int index = (n - 1) & hash;
                TreeNode<K,V> first = (TreeNode<K,V>)tab[index], root = first, rl;
                TreeNode<K,V> succ = (TreeNode<K,V>)next, pred = prev;
                if (pred == null)
                    tab[index] = first = succ;
                else
                    pred.next = succ;
                if (succ != null)
                    succ.prev = pred;
                if (first == null)
                    return;
                if (root.parent != null)
                    root = root.root();
                if (root == null || root.right == null ||
                    (rl = root.left) == null || rl.left == null) {
                    tab[index] = first.untreeify(map);  // too small
                    return;
                }
                TreeNode<K,V> p = this, pl = left, pr = right, replacement;
                if (pl != null && pr != null) {
                    TreeNode<K,V> s = pr, sl;
                    while ((sl = s.left) != null) // find successor
                        s = sl;
                    boolean c = s.red; s.red = p.red; p.red = c; // swap colors
                    TreeNode<K,V> sr = s.right;
                    TreeNode<K,V> pp = p.parent;
                    if (s == pr) { // p was s's direct parent
                        p.parent = s;
                        s.right = p;
                    }
                    else {
                        TreeNode<K,V> sp = s.parent;
                        if ((p.parent = sp) != null) {
                            if (s == sp.left)
                                sp.left = p;
                            else
                                sp.right = p;
                        }
                        if ((s.right = pr) != null)
                            pr.parent = s;
                    }
                    p.left = null;
                    if ((p.right = sr) != null)
                        sr.parent = p;
                    if ((s.left = pl) != null)
                        pl.parent = s;
                    if ((s.parent = pp) == null)
                        root = s;
                    else if (p == pp.left)
                        pp.left = s;
                    else
                        pp.right = s;
                    if (sr != null)
                        replacement = sr;
                    else
                        replacement = p;
                }
                else if (pl != null)
                    replacement = pl;
                else if (pr != null)
                    replacement = pr;
                else
                    replacement = p;
                if (replacement != p) {
                    TreeNode<K,V> pp = replacement.parent = p.parent;
                    if (pp == null)
                        root = replacement;
                    else if (p == pp.left)
                        pp.left = replacement;
                    else
                        pp.right = replacement;
                    p.left = p.right = p.parent = null;
                }
    
                TreeNode<K,V> r = p.red ? root : balanceDeletion(root, replacement);
    
                if (replacement == p) {  // detach
                    TreeNode<K,V> pp = p.parent;
                    p.parent = null;
                    if (pp != null) {
                        if (p == pp.left)
                            pp.left = null;
                        else if (p == pp.right)
                            pp.right = null;
                    }
                }
                if (movable)
                    moveRootToFront(tab, r);
            }
    
            /**
             * Splits nodes in a tree bin into lower and upper tree bins,
             * or untreeifies if now too small. Called only from resize;
             * see above discussion about split bits and indices.
             *
             * @param map the map
             * @param tab the table for recording bin heads
             * @param index the index of the table being split
             * @param bit the bit of hash to split on
             */
            final void split(HashMap<K,V> map, Node<K,V>[] tab, int index, int bit) {
                TreeNode<K,V> b = this;
                // Relink into lo and hi lists, preserving order
                TreeNode<K,V> loHead = null, loTail = null;
                TreeNode<K,V> hiHead = null, hiTail = null;
                int lc = 0, hc = 0;
                for (TreeNode<K,V> e = b, next; e != null; e = next) {
                    next = (TreeNode<K,V>)e.next;
                    e.next = null;
                    if ((e.hash & bit) == 0) {
                        if ((e.prev = loTail) == null)
                            loHead = e;
                        else
                            loTail.next = e;
                        loTail = e;
                        ++lc;
                    }
                    else {
                        if ((e.prev = hiTail) == null)
                            hiHead = e;
                        else
                            hiTail.next = e;
                        hiTail = e;
                        ++hc;
                    }
                }
    
                if (loHead != null) {
                    if (lc <= UNTREEIFY_THRESHOLD)
                        tab[index] = loHead.untreeify(map);
                    else {
                        tab[index] = loHead;
                        if (hiHead != null) // (else is already treeified)
                            loHead.treeify(tab);
                    }
                }
                if (hiHead != null) {
                    if (hc <= UNTREEIFY_THRESHOLD)
                        tab[index + bit] = hiHead.untreeify(map);
                    else {
                        tab[index + bit] = hiHead;
                        if (loHead != null)
                            hiHead.treeify(tab);
                    }
                }
            }
    
            /* ------------------------------------------------------------ */
            // Red-black tree methods, all adapted from CLR
    
            static <K,V> TreeNode<K,V> rotateLeft(TreeNode<K,V> root,
                                                  TreeNode<K,V> p) {
                TreeNode<K,V> r, pp, rl;
                if (p != null && (r = p.right) != null) {
                    if ((rl = p.right = r.left) != null)
                        rl.parent = p;
                    if ((pp = r.parent = p.parent) == null)
                        (root = r).red = false;
                    else if (pp.left == p)
                        pp.left = r;
                    else
                        pp.right = r;
                    r.left = p;
                    p.parent = r;
                }
                return root;
            }
    
            static <K,V> TreeNode<K,V> rotateRight(TreeNode<K,V> root,
                                                   TreeNode<K,V> p) {
                TreeNode<K,V> l, pp, lr;
                if (p != null && (l = p.left) != null) {
                    if ((lr = p.left = l.right) != null)
                        lr.parent = p;
                    if ((pp = l.parent = p.parent) == null)
                        (root = l).red = false;
                    else if (pp.right == p)
                        pp.right = l;
                    else
                        pp.left = l;
                    l.right = p;
                    p.parent = l;
                }
                return root;
            }
    
            static <K,V> TreeNode<K,V> balanceInsertion(TreeNode<K,V> root,
                                                        TreeNode<K,V> x) {
                x.red = true;
                for (TreeNode<K,V> xp, xpp, xppl, xppr;;) {
                    if ((xp = x.parent) == null) {
                        x.red = false;
                        return x;
                    }
                    else if (!xp.red || (xpp = xp.parent) == null)
                        return root;
                    if (xp == (xppl = xpp.left)) {
                        if ((xppr = xpp.right) != null && xppr.red) {
                            xppr.red = false;
                            xp.red = false;
                            xpp.red = true;
                            x = xpp;
                        }
                        else {
                            if (x == xp.right) {
                                root = rotateLeft(root, x = xp);
                                xpp = (xp = x.parent) == null ? null : xp.parent;
                            }
                            if (xp != null) {
                                xp.red = false;
                                if (xpp != null) {
                                    xpp.red = true;
                                    root = rotateRight(root, xpp);
                                }
                            }
                        }
                    }
                    else {
                        if (xppl != null && xppl.red) {
                            xppl.red = false;
                            xp.red = false;
                            xpp.red = true;
                            x = xpp;
                        }
                        else {
                            if (x == xp.left) {
                                root = rotateRight(root, x = xp);
                                xpp = (xp = x.parent) == null ? null : xp.parent;
                            }
                            if (xp != null) {
                                xp.red = false;
                                if (xpp != null) {
                                    xpp.red = true;
                                    root = rotateLeft(root, xpp);
                                }
                            }
                        }
                    }
                }
            }
    
            static <K,V> TreeNode<K,V> balanceDeletion(TreeNode<K,V> root,
                                                       TreeNode<K,V> x) {
                for (TreeNode<K,V> xp, xpl, xpr;;)  {
                    if (x == null || x == root)
                        return root;
                    else if ((xp = x.parent) == null) {
                        x.red = false;
                        return x;
                    }
                    else if (x.red) {
                        x.red = false;
                        return root;
                    }
                    else if ((xpl = xp.left) == x) {
                        if ((xpr = xp.right) != null && xpr.red) {
                            xpr.red = false;
                            xp.red = true;
                            root = rotateLeft(root, xp);
                            xpr = (xp = x.parent) == null ? null : xp.right;
                        }
                        if (xpr == null)
                            x = xp;
                        else {
                            TreeNode<K,V> sl = xpr.left, sr = xpr.right;
                            if ((sr == null || !sr.red) &&
                                (sl == null || !sl.red)) {
                                xpr.red = true;
                                x = xp;
                            }
                            else {
                                if (sr == null || !sr.red) {
                                    if (sl != null)
                                        sl.red = false;
                                    xpr.red = true;
                                    root = rotateRight(root, xpr);
                                    xpr = (xp = x.parent) == null ?
                                        null : xp.right;
                                }
                                if (xpr != null) {
                                    xpr.red = (xp == null) ? false : xp.red;
                                    if ((sr = xpr.right) != null)
                                        sr.red = false;
                                }
                                if (xp != null) {
                                    xp.red = false;
                                    root = rotateLeft(root, xp);
                                }
                                x = root;
                            }
                        }
                    }
                    else { // symmetric
                        if (xpl != null && xpl.red) {
                            xpl.red = false;
                            xp.red = true;
                            root = rotateRight(root, xp);
                            xpl = (xp = x.parent) == null ? null : xp.left;
                        }
                        if (xpl == null)
                            x = xp;
                        else {
                            TreeNode<K,V> sl = xpl.left, sr = xpl.right;
                            if ((sl == null || !sl.red) &&
                                (sr == null || !sr.red)) {
                                xpl.red = true;
                                x = xp;
                            }
                            else {
                                if (sl == null || !sl.red) {
                                    if (sr != null)
                                        sr.red = false;
                                    xpl.red = true;
                                    root = rotateLeft(root, xpl);
                                    xpl = (xp = x.parent) == null ?
                                        null : xp.left;
                                }
                                if (xpl != null) {
                                    xpl.red = (xp == null) ? false : xp.red;
                                    if ((sl = xpl.left) != null)
                                        sl.red = false;
                                }
                                if (xp != null) {
                                    xp.red = false;
                                    root = rotateRight(root, xp);
                                }
                                x = root;
                            }
                        }
                    }
                }
            }
    
            /**
             * Recursive invariant check
             */
            static <K,V> boolean checkInvariants(TreeNode<K,V> t) {
                TreeNode<K,V> tp = t.parent, tl = t.left, tr = t.right,
                    tb = t.prev, tn = (TreeNode<K,V>)t.next;
                if (tb != null && tb.next != t)
                    return false;
                if (tn != null && tn.prev != t)
                    return false;
                if (tp != null && t != tp.left && t != tp.right)
                    return false;
                if (tl != null && (tl.parent != t || tl.hash > t.hash))
                    return false;
                if (tr != null && (tr.parent != t || tr.hash < t.hash))
                    return false;
                if (t.red && tl != null && tl.red && tr != null && tr.red)
                    return false;
                if (tl != null && !checkInvariants(tl))
                    return false;
                if (tr != null && !checkInvariants(tr))
                    return false;
                return true;
            }
        }
    
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  • 原文地址:https://www.cnblogs.com/lewisyoung/p/12897958.html
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