题目链接:https://cn.vjudge.net/contest/68127#problem/B
#include<iostream>
#include<string>
#include<queue>
#include<algorithm>
#include<cstring>
#include<cmath>
using namespace std;
# define maxn 200+10
# define inf 0x3f3f3f3f
int n,m;
int a[maxn];
int vis[maxn];
vector<int >wakaka[maxn];
queue<int >q;
void match()
{
while(!q.empty())q.pop();
memset(vis,0,sizeof(vis));
q.push(1);
while(!q.empty())
{
int top=q.front();
vis[top]=1;
q.pop();
int len=wakaka[top].size();
for(int i=0; i<len; i++)
{
int temp=wakaka[top][i];
if(vis[temp])continue;
a[temp]=-a[top];
q.push(temp);
}
}
}
int main()
{
while(cin>>n>>m)
{
for(int i=1; i<=n; i++)
{
wakaka[i].clear();
}
int flag=0;
memset(a,0,sizeof(a));//首先给所有点都设置为0,如果不是朋友关系,则变成1和-1
for(int i=1; i<=m; i++)
{
int u,v;
cin>>u>>v;
wakaka[u].push_back(v);
wakaka[v].push_back(u);
if(a[u]&&a[v]&&a[u]==a[v])//如果之前已经确定u和v是非朋友关系,结果又变成了朋友关系,这样就矛盾了,所以建图失败
{
flag=1;
}
if(a[u]==0)a[u]=1;
a[v]=-a[u];
}
if(flag==1)cout<<"No"<<endl;
else
{
match();
int num1=0,num2=0;
for(int i=1; i<=n; i++)
{
if(a[i]==1)num1++;
if(a[i]==-1)num2++;
}
cout<<min(num1,num2)<<endl;
}
}
return 0;
}