• 【学习笔记】linq与lambda写法对照


    linq与lambda写法对照

    SQL LINQ Lambda
    SELECT * FROM Employee from e in Employees select e Employees.Select ()
    SELECT e.LoginID,e.JobTitle FROM Employee AS e from e in Employees select new {e.LoginID, e.JobTitle} Employees.Select ( e =>
    new{LoginID = e.LoginID,JobTitle = e.JobTitle}
    )
    SELECT e.LoginID AS ID, e.JobTitle AS Title FROM Employee AS e from e in Employees select new {ID = e.LoginID, Title = e.JobTitle} Employees.Select (e =>
    new{ID = e.LoginID,Title = e.JobTitle
    }
    )
    SELECT DISTINCT e.JobTitle FROM Employee AS e (from e in Employees select e.JobTitle).Distinct() Employees.Select (e => e.JobTitle)
    .Distinct ()
    SELECT e.* FROM Employee AS e WHERE e.LoginID = ‘test’ from e in Employees where e.LoginID == “test” select e Employees.Where (e => (e.LoginID == “test”))
    SELECT e.* FROM Employee AS e WHERE e.LoginID = ‘test’ AND e.SalariedFlag = 1 from e in Employees where e.LoginID == “test” && e.SalariedFlag select e Employees.Where (e => ((e.LoginID == “test”) && e.SalariedFlag))
    SELECT e.* FROM Employee AS e WHERE e.VacationHours >= 2 AND e.VacationHours <= 10 from e in Employees where e.VacationHours >= 2 && e.VacationHours <= 10 select e Employees.Where (e => (((Int32)(e.VacationHours) >= 2) && ((Int32)(e.VacationHours) <= 10)))
    SELECT e.* FROM Employee AS e ORDER BY e.NationalIDNumber from e in Employees orderby e.NationalIDNumber select e Employees.OrderBy (e => e.NationalIDNumber)
    SELECT e.* FROM Employee AS e ORDER BY e.HireDate DESC, e.NationalIDNumber from e in Employees orderby e.HireDate descending, e.NationalIDNumber select e Employees.OrderByDescending (e => e.HireDate).ThenBy (e => e.NationalIDNumber)
    SELECT e.* FROM Employee AS e WHERE e.JobTitle LIKE ‘Vice%’ OR SUBSTRING(e.JobTitle, 0, 3) = ‘Pro’ from e in Employees where e.JobTitle.StartsWith(“Vice”) || e.JobTitle.Substring(0, 3) == “Pro” select e Employees.Where (e => (e.JobTitle.StartsWith (“Vice”) || (e.JobTitle.Substring (0, 3) == “Pro”)))
    SELECT SUM(e.VacationHours) FROM Employee AS e   Employees.Sum(e => e.VacationHours);
    SELECT COUNT(*) FROM Employee AS e   Employees.Count();
    SELECT SUM(e.VacationHours) AS TotalVacations,e.JobTitle FROM Employee AS e GROUP BY e.JobTitle from e in Employees group e by e.JobTitle into g select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)} Employees.GroupBy (e => e.JobTitle)
    .Select (g =>new{JobTitle = g.Key,
    TotalVacations = g.Sum (e => (Int32)(e.VacationHours)) })
    SELECT e.JobTitle, SUM(e.VacationHours) AS TotalVacations FROM Employee AS e GROUP BY e.JobTitle HAVING e.COUNT(*) > 2 from e in Employees group e by e.JobTitle into g where g.Count() > 2 select new {JobTitle = g.Key, TotalVacations = g.Sum(e => e.VacationHours)} Employees.GroupBy (e => e.JobTitle)
    .Where (g => (g.Count () > 2)).Select (
    g =>new{JobTitle = g.Key, TotalVacations = g.Sum (e => (Int32)(e.VacationHours))} )
    SELECT * FROM Product AS p,ProductReview AS pr from p in Products from pr in ProductReviews select new {p, pr} Products.SelectMany (p => ProductReviews,(p, pr) =>new{
    p = p,
    pr = pr})
    SELECT * FROM Product AS p INNER JOIN ProductReview AS pr ON p.ProductID = pr.ProductID from p in Products join pr in ProductReviews on p.ProductID equals pr.ProductID select new {p, pr} Products.Join (ProductReviews,
    p => p.ProductID,pr => pr.ProductID,
    (p, pr) =>new{p = p,pr = pr})
    SELECT * FROM Product AS p INNER JOIN ProductCostHistory AS pch ON p.ProductID = pch.ProductID AND p.SellStartDate = pch.StartDate from p in Products join pch in ProductCostHistories on new {p.ProductID, StartDate = p.SellStartDate} equals new {pch.ProductID, StartDate = pch.StartDate}select new {p, pch} Products.Join (ProductCostHistories,
    p =>new{ProductID = p.ProductID,
    StartDate = p.SellStartDate},
    pch =>new{ProductID = pch.ProductID,
    StartDate = pch.StartDate},
    (p, pch) =>new{p = p,pch = pch})
    SELECT * FROM Product AS p LEFT OUTER JOIN ProductReview AS pr ON p.ProductID = pr.ProductID from p in Products join pr in ProductReviews on p.ProductID equals pr.ProductID into prodrev select new {p, prodrev} Products.GroupJoin (ProductReviews,
    p => p.ProductID,pr => pr.ProductID,(p, prodrev) => new{p = p,prodrev = prodrev
    })
    SELECT p.ProductID AS ID FROM Product AS p UNION SELECT pr.ProductReviewID FROM ProductReview AS pr (from p in Products select new {ID = p.ProductID}).Union(from pr in ProductReviews select new {ID = pr.ProductReviewID}) Products.Select (p => new{ID =p.ProductID}).Union (ProductReviews
    .Select (pr =>new{
    ID = pr.ProductReviewID}))
    SELECT TOP (10) * FROM Product AS p WHERE p.StandardCost < 100 (from p in Products where p.StandardCost < 100 select p).Take(10) Products.Where (p => (p.StandardCost < 100)).Take (10)
    SELECT * FROM [Product] AS p WHERE p.ProductID IN (SELECT pr.ProductID FROM [ProductReview] AS [pr] WHERE pr.[Rating] = 5) from p in Products where (from pr in ProductReviews where pr.Rating == 5 select pr.ProductID).Contains(p.ProductID)select p Products.Where (p =>ProductReviews.Where (pr => (pr.Rating == 5)) .Select (pr => pr.ProductID).Contains (p.ProductID)

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  • 原文地址:https://www.cnblogs.com/kudsu/p/13548937.html
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