A Computer Graphics Problem
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 43 Accepted Submission(s): 40
Problem Description
In this problem we talk about the study of Computer Graphics. Of course, this is very, very hard.
We have designed a new mobile phone, your task is to write a interface to display battery powers.
Here we use '.' as empty grids.
When the battery is empty, the interface will look like this:
When the battery is 60% full, the interface will look like this:
Each line there are 14 characters.
Given the battery power the mobile phone left, say x%, your task is to output the corresponding interface. Here x will always be a multiple of 10, and never exceeds 100.
We have designed a new mobile phone, your task is to write a interface to display battery powers.
Here we use '.' as empty grids.
When the battery is empty, the interface will look like this:
*------------*
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
*------------*
When the battery is 60% full, the interface will look like this:
*------------*
|............|
|............|
|............|
|............|
|------------|
|------------|
|------------|
|------------|
|------------|
|------------|
*------------*
Each line there are 14 characters.
Given the battery power the mobile phone left, say x%, your task is to output the corresponding interface. Here x will always be a multiple of 10, and never exceeds 100.
Input
The first line has a number T (T < 10) , indicating the number of test cases.
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)
Output
For test case X, output "Case #X:" at the first line. Then output the corresponding interface.
See sample output for more details.
See sample output for more details.
Sample Input
2
0
60
Sample Output
Case #1:
*------------*
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
*------------*
Case #2:
*------------*
|............|
|............|
|............|
|............|
|------------|
|------------|
|------------|
|------------|
|------------|
|------------|
*------------*
Source
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zhuyuanchen520
大水题一发
就是拼手速
1 /* *********************************************** 2 Author :kuangbin 3 Created Time :2013-9-11 12:01:07 4 File Name :2013-9-111001.cpp 5 ************************************************ */ 6 7 #include <stdio.h> 8 #include <string.h> 9 #include <iostream> 10 #include <algorithm> 11 #include <vector> 12 #include <queue> 13 #include <set> 14 #include <map> 15 #include <string> 16 #include <math.h> 17 #include <stdlib.h> 18 #include <time.h> 19 using namespace std; 20 int main() 21 { 22 //freopen("in.txt","r",stdin); 23 //freopen("out.txt","w",stdout); 24 int iCase = 0; 25 int T; 26 int n; 27 scanf("%d",&T); 28 while(T--) 29 { 30 iCase++; 31 printf("Case #%d: ",iCase); 32 scanf("%d",&n); 33 printf("*"); 34 for(int i = 0;i < 12;i++)printf("-"); 35 printf("* "); 36 int t = n/10; 37 for(int i = 0;i < 10-t;i++) 38 { 39 printf("|"); 40 for(int j = 0;j < 12;j++)printf("."); 41 printf("| "); 42 } 43 for(int i = 0;i < t;i++) 44 { 45 printf("|"); 46 for(int j = 0;j < 12;j++)printf("-"); 47 printf("| "); 48 } 49 printf("*"); 50 for(int i = 0;i < 12;i++)printf("-"); 51 printf("* "); 52 53 54 } 55 return 0; 56 }