• 1022. Digital Library


    1022. Digital Library (30)

    时间限制
    1000 ms
    内存限制
    32000 kB
    代码长度限制
    16000 B
    判题程序
    Standard
    作者
    CHEN, Yue

    A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years. Each book is assigned an unique 7-digit number as its ID. Given any query from a reader, you are supposed to output the resulting books, sorted in increasing order of their ID's.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains a positive integer N (<=10000) which is the total number of books. Then N blocks follow, each contains the information of a book in 6 lines:

    • Line #1: the 7-digit ID number;
    • Line #2: the book title -- a string of no more than 80 characters;
    • Line #3: the author -- a string of no more than 80 characters;
    • Line #4: the key words -- each word is a string of no more than 10 characters without any white space, and the keywords are separated by exactly one space;
    • Line #5: the publisher -- a string of no more than 80 characters;
    • Line #6: the published year -- a 4-digit number which is in the range [1000, 3000].

    It is assumed that each book belongs to one author only, and contains no more than 5 key words; there are no more than 1000 distinct key words in total; and there are no more than 1000 distinct publishers.

    After the book information, there is a line containing a positive integer M (<=1000) which is the number of user's search queries. Then M lines follow, each in one of the formats shown below:

    • 1: a book title
    • 2: name of an author
    • 3: a key word
    • 4: name of a publisher
    • 5: a 4-digit number representing the year

    Output Specification:

    For each query, first print the original query in a line, then output the resulting book ID's in increasing order, each occupying a line. If no book is found, print "Not Found" instead.

    Sample Input:
    3
    1111111
    The Testing Book
    Yue Chen
    test code debug sort keywords
    ZUCS Print
    2011
    3333333
    Another Testing Book
    Yue Chen
    test code sort keywords
    ZUCS Print2
    2012
    2222222
    The Testing Book
    CYLL
    keywords debug book
    ZUCS Print2
    2011
    6
    1: The Testing Book
    2: Yue Chen
    3: keywords
    4: ZUCS Print
    5: 2011
    3: blablabla
    
    Sample Output:
    1: The Testing Book
    1111111
    2222222
    2: Yue Chen
    1111111
    3333333
    3: keywords
    1111111
    2222222
    3333333
    4: ZUCS Print
    1111111
    5: 2011
    1111111
    2222222
    3: blablabla
    Not Found
    
    
      1 #include <iostream>
    2 #include <fstream>
    3 #include <vector>
    4 #include <string>
    5 #include <algorithm>
    6 #include <map>
    7 #include <stack>
    8 #include <cmath>
    9 #include <queue>
    10 #include <set>
    11 #include <list>
    12 #include <stdlib.h>
    13 #include <string.h>
    14
    15
    16 using namespace std;
    17
    18 class Book
    19 {
    20 public:
    21 char id[8];
    22 char title[81];
    23 char author[81];
    24 vector<string> keywords;
    25 char publisher[81];
    26 char year[5];
    27
    28
    29 };
    30
    31 bool myComp ( const char* s1 , const char* s2 )
    32 {
    33 if( s1 == NULL || s2 == NULL )
    34 {
    35 return true;
    36 }
    37 int result = strcmp(s1,s2);
    38 if( result > 0 )
    39 {
    40 return false;
    41 }
    42 else
    43 {
    44 return true;
    45 }
    46
    47 }
    48
    49
    50
    51 int main()
    52 {
    53
    54
    55
    56 list<Book> lib;
    57
    58
    59 int n;
    60
    61 cin >> n;
    62
    63 for( int i = 0 ; i < n ; ++i )
    64 {
    65 Book book;
    66 cin >> book.id;
    67
    68 cin.get();
    69
    70
    71 cin.getline(book.title , 80);
    72
    73 cin.getline(book.author , 80);
    74
    75
    76 while( 1 )
    77 {
    78 string keyword;
    79 char ch;
    80 while( 1 )
    81 {
    82 ch = cin.get();
    83
    84 if( ch == ' ' )
    85 {
    86 book.keywords.push_back(keyword);
    87 break;
    88 }
    89 else if ( ch == '\n' )
    90 {
    91 book.keywords.push_back(keyword);
    92 goto NEXT_ITEM;
    93 }
    94 keyword.push_back(ch);
    95 }
    96
    97
    98 }
    99
    100 NEXT_ITEM:;
    101
    102
    103 cin.getline(book.publisher , 80);
    104
    105 cin.getline(book.year , 80);
    106
    107
    108 lib.push_back( book );
    109 }
    110
    111 cin >> n;
    112 cin.get();
    113 for( int i = 0 ; i < n ; ++i )
    114 {
    115 char qry[101];
    116 char cmd[101];
    117
    118
    119 cin.getline(qry , 100);
    120
    121 string qury = qry;
    122
    123 strcpy ( cmd , qury.substr( 3 , qury.size() - 3 ).c_str());
    124
    125 char select = qury[0];
    126
    127 vector<char*> result;
    128 result.clear();
    129
    130 switch(select)
    131 {
    132 case '1':
    133 for( list<Book>::iterator it = lib.begin() ; it != lib.end() ; ++it )
    134 {
    135 if( strcmp( it->title, cmd ) == 0 )
    136 {
    137 result.push_back( it->id );
    138 }
    139 }
    140 break;
    141 case '2':
    142 for( list<Book>::iterator it = lib.begin() ; it != lib.end() ; ++it )
    143 {
    144 if( strcmp( it->author, cmd) == 0 )
    145 {
    146 result.push_back( it->id );
    147 }
    148 }
    149 break;
    150 case '3':
    151 for( list<Book>::iterator it = lib.begin() ; it != lib.end() ; ++it )
    152 {
    153 for( int kw = 0 ; kw < it->keywords.size() ; ++kw )
    154 {
    155 if( strcmp ( it->keywords[kw].c_str(), cmd ) == 0 )
    156 {
    157 result.push_back( it->id );
    158 break;
    159 }
    160 }
    161 }
    162 break;
    163 case '4':
    164 for( list<Book>::iterator it = lib.begin() ; it != lib.end() ; ++it )
    165 {
    166 if( strcmp ( it->publisher, cmd) == 0 )
    167 {
    168 result.push_back( it->id );
    169 }
    170 }
    171 break;
    172 case '5':
    173 for( list<Book>::iterator it = lib.begin() ; it != lib.end() ; ++it )
    174 {
    175 if( strcmp( it->year, cmd) == 0 )
    176 {
    177 result.push_back( it->id );
    178 }
    179 }
    180 break;
    181 }
    182
    183 sort( result.begin() , result.end() , myComp );
    184
    185 cout << qury << endl;
    186 if( result.size() != 0 )
    187 {
    188 for ( int r = 0 ; r < result.size() ; ++r )
    189 {
    190 cout << result[r] << endl;
    191 }
    192 }
    193 else
    194 {
    195 cout << "Not Found" << endl;
    196 }
    197
    198 }
    199
    200 return 0;
    201 }
    There is one case failed with "out of memory". To be debugged...
    P.S.
    This link: http://blog.csdn.net/tiantangrenjian/article/details/6886093
    gives a piece of code that failed wit "time-out" but success in my failed case. It may be funny to combine these two and add a ramdomized selection.
    
    
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  • 原文地址:https://www.cnblogs.com/kking/p/2331805.html
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