题目:Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
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思路:
本题的一个思路就是在当前节点求解左右子树的高度,如果两边高度绝对值相差为1,则返回错误,然后继续判断左右子节点。
本题不难。
代码:
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isBalanced(TreeNode* root) { if(root==NULL) return true; int left=treeDepth(root->left); int right=treeDepth(root->right); if(abs(left-right)>1) return false; return isBalanced(root->left)&&isBalanced(root->right); } int treeDepth(TreeNode* root){ if(root==NULL) return 0; int left=1,right=1; left+=treeDepth(root->left); right+=treeDepth(root->right); return max(left,right); } };