• Heap Sort


    package _Sort.Algorithm
    
    /**
     * https://www.geeksforgeeks.org/heap-sort/
     * https://www.cnblogs.com/chengxiao/p/6129630.html
     *
     * Heap Sort is an in-place algorithm. the typical implementation is not stable,but can be made stable.
     * Time complexity of heapify is O(Logn), Time complexity of Create and BuildHelp is O(N) and overall
     * time complexity of HeapSort is O(nLogn).
     * Heap Sort is a comparision base sorting technique base on BinaryHeap data structure.
     *
     * ==Why array based representation for Binary Heap?
     * Since Binary Heap is a Complete Binary Tree, it can easy represented as array and array based representation is
     * space different.
     * if the parent node is sorted at index I,the left child can be calculated by 2*I+1, and the right child can be calculated
     * by 2*I+2 (assuming the indexing start at 0).
     *
     *  MaxHeap: arr[i]>=arr[i*2+1] && arr[i]>=arr[i*2+2]
        MinHeap: arr[i]<=arr[i*2+1] && arr[i]<=arr[i*2+2]
     *
     * ==Heap Sort algorithm for sorting in increasing order:
     * 1. Build a Max or Min head from input array.
     * 2. At this point, the largest item is sorted at the root of the heap. replace it with the last item of the
     * heap followed by reducing the size of heap by 1. finally, heapify the root of tree.
     * 3. repeat above steps while size of heap is greater than 1.
     *
     * ==How to build heap?
     * Heapify procedure can be applied to a node only if its children nodes are heapified. so the heapification must
     * be performed in the bottom up order.
     *
     * Lets understand with the help of an example:
     *
     * Input data: 4, 10, 3, 5, 1
          4(0)
         /   
      10(1)   3(2)
      /   
    5(3) 1(4)
    
    The numbers in bracket represent the indices in the array representation of data.
    
    Applying heapify procedure to index 1:
          4(0)
         /   
      10(1)   3(2)
      /   
    5(3)  1(4)
    
    Applying heapify procedure to index 0:
          10(0)
          /  
        5(1) 3(2)
       /   
     4(3) 1(4)
    The heapify procedure calls itself recursively to build heap in top down manner.
     * */
    class HeapSort {
    
        fun sort(array:IntArray){
            val n = array.size
            //build heap, bottom to up
            for (i in n/2-1 downTo 0){
                heapify(array,n,i)
            }
            //one by one extract an element from heap
            for (i in n-1 downTo 1){
                //move current node to end
                val temp = array[0]
                array[0] = array[i]
                array[i] = temp
                //call max heapify on the reduced heap
                heapify(array,i,0)
            }
            printArray(array)
        }
    
        private fun printArray(array: IntArray) {
            for (item in array) {
                print("$item ,")
            }
        }
    
        /**
         *To heapify sub tree rooted with node i which is an index in array[].
         * n is size of heap.
         * */
        private fun heapify(array: IntArray, n:Int, i:Int){
            var largest  = i
            val left = 2*i+1
            val right = 2*i+2
    
            //if left child is largest than root
            if (left < n && array[left] > array[largest]){
                largest = left
            }
    
            //if right child is largest than root
            if (right < n && array[right] > array[largest]){
                largest = right
            }
    
            //if largest is not root
            if (largest != i ){
                val temp = array[i]
                array[i] = array[largest]
                array[largest] = temp
                //recursively heapify the affected sub-tree
                heapify(array,n,largest)
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/johnnyzhao/p/12813279.html
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